I have the following document in Couchbase:
{
"id": "ee::brown",
"type": "ee",
"firstName": "John",
"lastName": "Brown",
"email": "jbown#gmail.com"
}
The code below tries to get the lastName field for id="ee::brown"
ops := []gocb.LookupInSpec{
gocb.GetSpec("lastName", &gocb.GetSpecOptions{}),
}
getResult, err := collection.LookupIn("ee::brown", ops, &gocb.LookupInOptions{})
if err != nil {
panic(err)
}
var lastName string
err = getResult.ContentAt(0, &lastName)
if err != nil {
panic(err)
}
fmt.Println(lastName)
Running this code generates the following message:
Not Found (KEY_ENOENT)
Running following query in Query workbench retrieves the full document:
select * from mybucket where id="ee::brown"
Also tried setting IsXttra field to true as follows but it did not work either:
ops := []gocb.LookupInSpec{
gocb.GetSpec("lastName", &gocb.GetSpecOptions{IsXattr: true}),
}
Also could not find definition of IsXattr for GetSpecOption. What is it for?
Help please!
Environment: macOS Catalina version 10.15.3;
go-sdk : import "github.com/couchbase/gocb/v2" ;
Couchbase: Enterprise Edition 6.5.0 build 4960
Related
I installed the libs and can run/debug the libvirt related codes in idea IDE, but after running below build command on MacBook
CGO_ENABLED=0 GOOS=windows GOARCH=amd64 go build -o zagent.exe cmd/test/main.go
I got
cmd/test/main.go:11:22: undefined: libvirt.NewConnect
Thank you for your attention, below is the codes:
package main
import (
_logUtils "github.com/easysoft/zagent/internal/pkg/lib/log"
"github.com/libvirt/libvirt-go"
)
func main() {
connStr := "***"
LibvirtConn, err := libvirt.NewConnect(connStr)
if err != nil {
_logUtils.Errorf(err.Error())
return
}
active, err := LibvirtConn.IsAlive()
if err != nil {
_logUtils.Errorf(err.Error())
return
}
if !active {
_logUtils.Errorf("not active")
}
}
The libvirt-go package is a CGo based API to the underlying libvirt.so library. You cannot set CGO_ENABLED=0 and expect it to still work. AFAI, Go toolchain doesn't allow cross-compiling with CGo either.
Although the output setting has been set to text
~/.aws/config
[default]
output=text
the aws-sdk-go returns json. The question is whether the output could be switched to text.
When:
aws route53 get-hosted-zone --id some-id
is run, the output looks as follows:
NAMESERVERS some-ns
NAMESERVERS some-ns1
NAMESERVERS some-ns2
NAMESERVERS some-ns3
According to the this AWS documentation one could set the configuration:
sess, err := session.NewSession(&aws.Config{
Region: aws.String("us-east-2")},
)
One attempt was to consult this Config struct, but an Output option seems to be omitted.
How to set the output to text?
Note: an issue has added to the github page of the aws-sdk-go as well.
Example
package main
import (
"fmt"
"log"
"github.com/aws/aws-sdk-go/aws"
"github.com/aws/aws-sdk-go/aws/session"
"github.com/aws/aws-sdk-go/service/route53"
)
func main() {
session, err := session.NewSession()
if err != nil {
log.Fatal(err)
}
r53 := route53.New(session)
listParams := &route53.ListResourceRecordSetsInput{
HostedZoneId: aws.String("some-id"),
}
records, err := r53.ListResourceRecordSets(listParams)
if err != nil {
log.Fatal(err)
}
fmt.Println(records)
}
returns:
{
IsTruncated: false,
MaxItems: "100",
ResourceRecordSets: [
{
Name: "some-domain.",
ResourceRecords: [{
Value: "some-ip"
}],
TTL: 7200,
Type: "A"
}
}
while aws route53 list-resource-record-sets --hosted-zone-id some-id, results in:
RESOURCERECORDSETS some-domain. 7200 A
RESOURCERECORDS some-ip
Problem
While it is possible to set the format of the aws-cli to output, it does not seem to be possible to do the same for the SDK.
Question
How to let the go-aws-sdk return text rather than json?
I have all of the information you need, you just have to unravel it from the response (records).
To get similar results from the last cli command:
for _, recordSet := range records.ResourceRecordSets {
log.Println("RESOURCERECORDSETS " + *recordSet.Name + strconv.Itoa(int(*recordSet.TTL)) + *recordSet.Type)
for _, record := range recordSet.ResourceRecords {
log.Println("RESOURCERECORDS " + *record.Value)
}
log.Println("")
}
I'm setting up testing in Go. I use go-sqlmock to test mysql connection. Now I try to test mysql insert logic. But the error occurs.
I want to know how to resolve this error.
server side: golang
db: mysql
web framework: gin
dao.go
func PostDao(db *sql.DB, article util.Article, uu string) {
ins, err := db.Prepare("INSERT INTO articles(uuid, title,content) VALUES(?,?,?)")
if err != nil {
log.Fatal(err)
}
ins.Exec(uu, article.TITLE, article.CONTENT)
}
dao_test.go
func TestPostArticleDao(t *testing.T) {
db, mock, err := sqlmock.New()
if err != nil {
t.Fatalf("an error '%s' was not expected when opening a stub database connection", err)
}
defer db.Close()
mock.ExpectExec("^INSERT INTO articles*").
WithArgs("bea1b24d-0627-4ea0-aa2b-8af4c6c2a41c", "test", "test").
WillReturnResult(sqlmock.NewResult(1, 1))
article := util.Article{
ID: 1,
TITLE: "test",
CONTENT: "test",
}
PostDao(db, article, "bea1b24d-0627-4ea0-aa2b-8af4c6c2a41c")
if err := mock.ExpectationsWereMet(); err != nil {
t.Errorf("there were unfulfilled expections: %s", err)
}
}
I expect go test -v runs without error.
But the actual is not.
Here is the error.
=== RUN TestPostArticleDao
2019/08/31 00:08:11 call to Prepare statement with query 'INSERT INTO articles(uuid, title,content) VALUES(?,?,?)', was not expected, next expectation is: ExpectedExec => expecting Exec or ExecContext which:
- matches sql: 'INSERT INTO articles(uuid, title,content) VALUES(?,?,?)'
- is with arguments:
0 - bea1b24d-0627-4ea0-aa2b-8af4c6c2a41c
1 - test
2 - test
- should return Result having:
LastInsertId: 1
RowsAffected: 1
exit status 1
FAIL article/api/dao 0.022s
As #Flimzy suggested, it needs to set ExpectPrepare first.
So I changed dao_test.go in this way:
prep := mock.ExpectPrepare("^INSERT INTO articles*")
prep.ExpectExec().
WithArgs("bea1b24d-0627-4ea0-aa2b-8af4c6c2a41c", "test", "test").
WillReturnResult(sqlmock.NewResult(1, 1))
In my case it worked without asterix:
mock.ExpectExec("INSERT INTO `mytable`").WithArgs(mockdbutils.AnyTime{}, mockdbutils.AnyTime{}, nil, 4455,false).WillReturnResult(sqlmock.NewResult(int64(4455), 1))
mock.ExpectCommit()
I'm puzzled.
I try to run test cases using gorm with mysql in golang and I wanna buile MySQL just for testing, but it does not run safely.
I wanna use this package go-test-mysqld
Error message is below.
panic: sql: Register called twice for driver mysql
My code is
func TestMain(m *testing.M) {
mysqld, err := mysqltest.NewMysqld(nil)
if err != nil {
log.Fatal("runTests: failed", err)
}
defer mysqld.Stop()
dbm, err = gorm.Open("mysqld", mysqld.Datasource("test", "", "", 0 ))
if err != nil {
log.Fatal("db connection error:", err)
}
defer dbm.Close()
code := m.Run()
os.Exit(code)
}
What is the problems in my code?
Or is it impossible to build another mysql in using gorm?
Do you have some ideas?
I am using the following sample program:
func getEnv(appName string, env string) {
svc := elasticbeanstalk.New(session.New(), &aws.Config{Region: aws.String("us-east-1")})
params := &elasticbeanstalk.DescribeConfigurationSettingsInput{
ApplicationName: aws.String(appName), // Required
EnvironmentName: aws.String(env),
}
resp, err := svc.DescribeConfigurationSettings(params)
if err != nil {
fmt.Println(err.Error())
return
}
v := resp.ConfigurationSettings
fmt.Printf("%s", v)
}
It's printing out the following response; this looks like a valid json except for the missing quote makes. ex: ApplicationName and not "ApplicationName".
How do I parse this? or get a valid json from AWS?
ConfigurationSettings: [{
ApplicationName: "myApp",
DateCreated: 2016-01-12 00:10:10 +0000 UTC,
DateUpdated: 2016-01-12 00:10:10 +0000 UTC,
DeploymentStatus: "deployed",
Description: "Environment created from the EB CLI using \"eb create\"",
EnvironmentName: "stag-myApp-app-s1",
OptionSettings: [
...
resp.ConfigurationSettings is not in JSON format any more, the aws-sdk-go package handled that for you. When you do,
v := resp.ConfigurationSettings
v contains an instance []*ConfigurationSettingsDescription that was parsed from the JSON response, and you don't have to parse it yourself. What you are seeing when you print it out is the Go struct representation. You can just go ahead and use it:
if len(v) > 0 {
log.Println(v[0].ApplicationName)
}
This should print out myApp