Hi everyone this is simple thing to solve but could not find a way out. I want to apply ORDER BY on a name field which have leading space in some values because of that ORDER BY does not produce the desired results. So I apply TRIM in ORDER BY CLAUSE
SELECT * FROM AssetManufacturerName ORDER BY TRIM(AssetManufacturerName)
But this still does not produce desired output as shown below. Because of leading spaces Lenovo is on top. I want it to be on 2nd.
Sample Table
+-------------+----------------+
| ID | Name |
+-------------+----------------+
| 01 | ' Robert King' |
| | |
| 02 | 'Arsim Kip' |
+-------------+----------------+
I gone thorough this question but no joys. I thinks this is MYSQL version issue.
NOTE: Our Application is working on MYSQL 5.5.52.
The trim function may work as intended. I suspect it could be different character like tab.
ORDER BY TRIM(TRIM(BOTH '\t' FROM AssetManufacturerName))
db<>fiddle demo
Related
So I created a database table in MySQL that held permission rights for permissions and commands, the command rights started with the prefix command_ in the column permission_name and then I have an extra column called allowed_ranks, which is a list of INT rank ID's that are required, split by a , character.
The issue is, the command ones were anything higher, and I've put 1 id in allowed_ranks, is there a way I can loop through all the ones with column starting with command_ and change the allowed_ranks that are just 1 ID to every number starting from that to 9? 9 is the maximum rank ID.
I've already done part of the query, I'm just not sure how to do the updating?
UPDATE permission_rights` SET `allowed_ranks` = '?' WHERE `permission_name` LIKE 'command_%';
How would I update it to every number after the columns value up to 9? So lets say I had this record... just a quick example to ensure you know what I mean.
| permission_name | allowed_ids |
----------------------------------
| command_hello | 2
| command_junk | 5
| command_delete | 8
| command_update | 1
Would become...
| permission_name | allowed_ids |
----------------------------------
| command_hello | 2,3,4,5,6,7,8,9
| command_junk | 5,6,7,8,9
| command_delete | 8,9
| command_update | 1,2,3,4,5,6,7,8,9
The better approach would be to use a number generator (some method which will produce number from 1 to n), but general MySQL has no such capability.
If you use MariaDB you can use seq_1_to_1000 as suggested here in Answer by O.Jones.
However your use case seems to be simpler, since you said that the highest rank is 9, I would just use
update a
set a.allowed_ids = RIGHT('1,2,3,4,5,6,7,8,9',19-2*a.allowed_ids)
where a.permission_name like 'command_%'
Been struggling for this for awhile.
Is there a way to find all rows in my table where the word in the column 'word' is a part of a search word?
+---------+-----------------+
| id_word | word |
+---------+-----------------+
| 177041 | utvälj |
| 119270 | fonders |
| 39968 | flamländarens |
| 63567 | hänvisningarnas |
| 61244 | hovdansers |
+---------+-----------------+
I want to extract the row 119270, fonders. I want to do this by passing in the word 'plafonders'.
SELECT * FROM words WHERE word REGEXP 'plafonders$'
That query will of course not work in this case, would've been perfect if it had been the other way around.
Does anyone know a solution to this?
SELECT * FROM words WHERE 'plafonders' REGEXP concat(word, '$')
should accomplish what you want. Your regex:
plafonders$
is looking for plafonders at the end of the column. This is looking for everything the column has until its end, e.g. the regexp is fonders$ for 119270.
See https://regex101.com/r/Ytb3kg/1/ compared to https://regex101.com/r/Ytb3kg/2/.
MySQL's REGEXP does not handle accented letters very well. Perhaps it will work OK in your limited situation.
Here's a slightly faster approach (though it still requires a table scan):
SELECT * FROM words
WHERE 'PLAutvälj' =
RIGHT('PLAutvälj', CHAR_LENGTH(word)) = word;
(To check the accents, I picked a different word from your table.)
I have a Table (T_agents) of agents each has a number of call in a field called NCH I want to create another field call NCHpercent that is the percentage of calls taken by that agent. So the formula is NCH/Total NCH.
So in the query builder I have the following and formula but it dosent work :(
NCHpercent: [NCH.T_agents] / ( SUM(SELECT [NCH.T_agents] FROM [T_agents]) )
What am I doing wrong ?
This would be easier if we could see the table structure as that impacts everything. However I hope I follow this correctly, but I imagine your table (T_agents) as something like:
+-------+-------------+------+
| ID | Agents | NCH |
+-------+-------------+------+
| 1 | agent_1 | 1 |
| 1 | agent_1 | 1 |
| 1 | agent_2 | 2 |
| 1 | agent_3 | 1 |
+-------+-------------+------+
Now assuming that is correct (and NCH is not a unique ID but a total number of calls then we can use a query like this to calculate percentage - note this is not stored in a table, this is just to display the percentage value in a query- I've also added the sum of the total in for the sake of it:
SELECT SUM([T_Agents].NCH) AS total_SUM, [T_agents].Agents, ((SUM(T_agents.NCH))/(select SUM(t_agents.NCH )from T_agents)*100) AS NCHPercent
FROM T_agents
GROUP BY [t_agents].Agents;
In my test the results would be:
2, agent_1, 40
2, agent_2, 40
1, agent_3, 20
However if I got this wrong and the NCH column is in fact
Ok. I just found the answer soing some trial an error. The answer is this code:
NCHperc: [AHT_Tenure].[Calls Handled]/(SELECT Sum(AHT_Tenure.[Calls Handled]) AS [SumaDeCalls Handled]
FROM AHT_Tenure)
By the way thank you guys. And actually the agents name dosent matter for this query since all I wanted was the percentage on each row.
I've searched for this for a long time, but the solutions I've found aren't working as I need.
Let me explain: I have a table containing a couple of thousands of products, each one with an alphanumeric SKU, used also for sorting.
This SKU consists of:
Category Code (variable number of alphabetic characters),
Product Number (integer),
Product Model Variation (optional, variable number of alphabetic characters)
For example: MANT 12 CL (without spaces)
Now, I need to get them ordered like this (and if these were filenames, OSX Finder would order them perfectly):
MANT1
MANT2
MANT2C
MANT2D
MANT2W
MANT3
MANT4C
MANT9
MANT12
MANT12C
MANT12CL
MANT12P
MANT13
MANT21
MANT24
MANT24D
MANT29
Of course ORDER BY sku is plainly wrong:
MANT1
MANT12
MANT12C
MANT12CL
MANT12P
MANT13
MANT2
MANT21
MANT24
MANT24D
MANT29
MANT2C
MANT2D
MANT2W
MANT3
MANT4C
MANT9
And ORDER BY LENGTH(sku), sku has problems sorting the model variations:
MANT1
MANT2
MANT3
MANT9
MANT12
MANT13
MANT21
MANT24
MANT29
MANT2C
MANT2D
MANT2W
MANT4C
MANT12C
MANT12P
MANT24D
MANT12CL
So, is there a way to sort this stuff like Finder would?
(Also, once sorted, is there a way to get the next and previous product? I don't mind using several queries: at this point elegance is the last of my problems...)
Thanks everybody in advance.
One last thing: during my searches I've found this answer to a similar question
but I have no idea how to use it in PHP, so I don't know if it works and is actually an answer to my question.
Are you using PHP when fetching data?
If so, try using natural sort function for in memory sort after data is already loaded?
The order is not 'plain wrong', it simply depends what collation you use. In your case, you might try the binary collation, for example, 'latin1_bin'.
Following example the ORDER BY using COLLATE for UTF8 data:
mysql> SELECT c1 FROM t1 ORDER BY c1;
+------+
| c1 |
+------+
| a1 |
| a12 |
| a13c |
| a2 |
| a21 |
+------+
mysql> SELECT c1 FROM t1 ORDER BY c1 COLLATE 'utf8_bin';
+------+
| c1 |
+------+
| a1 |
| a12 |
| a2 |
| a21 |
| a13c |
+------+
I have a table (pretty big one) with lots of columns, two of them being "post" and "user".
For a given "post", I want to know which "user" posted the most.
I was first thinking about getting all the entries WHERE (post='wanted_post') and then throw a PHP hack to find which "user" value I get the most, but given the large size of my table, and my poor knowledge of MySQL subtle calls, I am looking for a pure-MySQL way to get this value (the "user" id that posted the most on a given "post", basically).
Is it possible ? Or should I fall back on the hybrid SQL-PHP solution ?
Thanks,
Cystack
It sounds like this is what you want... am I missing something?
SELECT user
FROM myTable
WHERE post='wanted_post'
GROUP BY user
ORDER BY COUNT(*) DESC
LIMIT 1;
EDIT: Explanation of what this query does:
Hopefully the first three lines make sense to anyone familiar with SQL. It's the last three lines that do the fun stuff.
GROUP BY user -- This collapses rows with identical values in the user column. If this was the last line in the query, we might expect output something like this:
+-------+
| user |
+-------+
| bob |
| alice |
| joe |
ORDER BY COUNT(*) DESC -- COUNT(*) is an aggregate function, that works along with the previous GROUP BY clause. It tallies all of the rows that are "collapsed" by the GROUP BY for each user. It might be easier to understand what it's doing with a slightly modified statement, and it's potential output:
SELECT user,COUNT(*)
FROM myTable
WHERE post='wanted_post'
GROUP BY user;
+-------+-------+
| user | count |
+-------+-------+
| bob | 3 |
| alice | 1 |
| joe | 8 |
This is showing the number of posts per user.
However, it's not strictly necessary to actually output the value of an aggregate function in this case--we can just use it for the ordering, and never actually output the data. (Of course if you want to know how many posts your top-poster posted, maybe you do want to include it in your output, as well.)
The DESC keyword tells the database to sort in descending order, rather than the default of ascending order.
Naturally, the sorted output would look something like this (assuming we leave the COUNT(*) in the SELECT list):
+-------+-------+
| user | count |
+-------+-------+
| joe | 8 |
| bob | 3 |
| alice | 1 |
LIMIT 1 -- This is probably the easiest to understand, as it just limits how many rows are returned. Since we're sorting the list from most-posts to fewest-posts, and we only want the top poster, we just need the first result. If you wanted the top 3 posters, you might instead use LIMIT 3.