i have a table named cq500_all(to record diffrent doctor feedback)
now i want know counts when condition status is
field dr_1_finish and field dr_2_finish value is all fill 1
and
when field dr_1 different dr_2 (like dr_1=1 and dr_2=0,or dr_1=0 and dr_2=1 )
cause i want to know two doctors feedback counts (when different doctor's feedback on jpg)
for example image show CQ500-CT-1_36_08.jpg and CQ500-CT-1_36_09.jpg is match my select counts
it will be two (select counts result)
how to make the query on mysql?
You can count as
select count(*) as total
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1 and dr_1 != dr_2
You will got result in total
Pretty much just the way you've described it:
select *
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1
and dr_1 != dr_2
or (if dr_1 or dr_2 might not be just 0 and 1):
select *
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1
and ((dr_1 = 1 and dr_2 = 0) or (dr_1 = 0 and dr_2 = 1))
Related
I have a table offers with five relevant columns, offer_id, offer_type, offer_amount, end_date and offer_status
I am trying to select the row with the highest offer_amount that matches the correct offer_type and an offer_status of 1 (active).
The query I am using is
SELECT * FROM offers_tbl WHERE offer_status = 1 AND offer_type = 'site-wide' AND offer_amount = (SELECT MAX(offer_amount) FROM offers_tbl )
Whats happening is that this is not returning any results if the MAX(offer_amount) happens to have a offer_status of 0 (inactive).
If the particular row with the highest MAX(offer_amount) happens to have an offer_status of 1, this works fine. Its only when the offer status is 0 that this breaks.
Try making it find MAX out of active ones:
SELECT * FROM offers_tbl WHERE offer_status = 1 AND offer_type = 'site-wide' AND offer_amount = (SELECT MAX(offer_amount) FROM offers_tbl WHERE offer_status = 1)
Otherwise, it's finding MAX offer amounts that could have a status of 0, which makes the outside query not find a match of status of 1 AND that amount.
Scenario:
I have a column in a MySql table:
my_column - [INT] (Unsigned)
What I need:
I need a query to select ONE ENTRY with conditions as follows:
Given A=n
SELECT FIRST the one with my_column = n
ELSE (my_column = n null result)
SELECT the one with my_column = 0
ELSE
SELECT the one with my_column = whatever
ELSE
Return 0 entries
What I looked into:
I tried:
... WHEREmy_columnIN (n,0) ORDER BYmy_columnDESC LIMIT 1
Which applies for the first two steps, but not for the third one.
Thanks for reading.
Given your description, just use case:
order by (case when field = n then 1
when field = 0 then 2
else 3
end)
Then, of course, you would add limit 1.
I have a MySQL table of many records. I am trying to find a way to show the records which meet more than one condition of a query. For example, if I had this table.
TABLE NAME: DATA
ID contactid flag flag_type
-----------------------------------
1 99 Volunteer 1
2 99 Uploaded 2
3 100 Via Import 3
4 100 Volunteer 1
5 100 Uploaded 2
with conditions such as:
WHERE (ID > 2) OR (flag = 'Uploaded') OR (flag_type = 1) ..etc..
The output would be where IDs 4 & 5 only would be returned.
You can count the number of conditions in MySQL and use this value:
where ((id > 2) +
(flag = 'Uploaded') +
(flag_type = 1)
) > 1
A boolean value of "true" is treated as 1 AND "false" is treated as 0. So, by adding up the values, you get the number of conditions that are met.
Often, you do this in an order by, to get the most matching first:
where id > 2 or flag = 'Uploaded' or flag_type = 1
order by ((id > 2) +
(flag = 'Uploaded') +
(flag_type = 1)
) desc;
http://sqlfiddle.com/#!2/572e1/11
This solution selects each of your successful conditions as 1 which is added to "factors". Then we show results with at least 2 factors:
SELECT * FROM
(select id, contactid, flag, flag_type,
(CASE WHEN id > 2 then 1 else 0 END) +
(CASE WHEN flag = 'Uploaded' then 1 else 0 END) +
(CASE WHEN flag_type = 1 then 1 else 0 END) AS factors
from DATA
) t
WHERE factors > 1
With your limited question, this is the most that can be provided.
WHERE `ID`>2 AND (`flag`='Uploaded' OR `flag_type`=1) ..etc
You are on the right path, but you need to read first about boolean logic. ORs are going to return records that match any of the conditions and ANDs will return records that match all of the conditions.
I have 2 my tables with data and 2 "not mine" tables (in ReferenceDB) where thing ID can be mapped to its name.
One of mine tables is orders with following important columns: charName, stationID, typeID, bid.
Another table has following important columns: transactionDateTime, stationID, typeID, person, transactionType
I started my head braking with idea how to find orders that doesn't have any records for them lately (e.g. given amount of days). But for beginning I set me a task just to find orders that has no records for them at all. For that I figured out LEFT JOIN see biggest query below.
An order for me is a combination of charName/persone + stationID + typeID + transactionType/bid so if actually one of those four changes it is different order then.
Problem is that transactionType can be "yes" or "no" and bid is 0 or not 0. So I cant or DON'T KNOW HOW to JOIN ON different data types. So logically I'd like to join on 4 columns like:
FROM ordersTable LEFT JOIN recordsTable ON ordersTable.typeID = recordsTable.typeID
AND ordersTable.stationID = recordsTable.stationID
AND ordersTable.charName = recordsTable.person
AND ordersTable.bid = recordsTable.transactionType
Clearly last string of above wouldn't work cause of different data types.
So for a moment I thought that I can do such query twice for bid=0 with transactionType="yes" and second time for bid != 0 and transactionType = "no" see my query below for 0/"yes" combination. But seems it doesn't works exactly as I'd like it to. because AND ordersTable.bid IN (0) AND recordsTable.transactionType="yes" in JOIN ON doesn't sem do anything. (As I do get results where bid=1)
SELECT invTypes.typeName, stastations.stationName, main.* FROM referenceDB.invTypes, referenceDB.stastations, (
SELECT ordersTable.charName, ordersTable.stationID, ordersTable.typeID, ordersTable.bid, ordersTable.orderState, ordersTable.volRemaining
FROM ordersTable LEFT JOIN recordsTable ON ordersTable.typeID = recordsTable.typeID
AND ordersTable.stationID = recordsTable.stationID
AND ordersTable.charName = recordsTable.person
AND ordersTable.bid IN (0) AND recordsTable.transactionType="yes"
WHERE recordsTable.typeID IS NULL
AND ordersTable.orderState IN (0) ) as main
WHERE stastations.stationID = main.stationID AND invTypes.typeID = main.typeID;
Questions:
Is it possible to tell mySQL to treat "yes" as 0 or vise versa? If yes how do I do it in my query? If no what would be my work around (to find orders that doesn't have records related to them)?
And possibly some one can suggset a query that will find orders that didn't have records within given amount of days?
Thank you in advance!
One way is to use the explicit comparisons:
((ordersTable.bid = 0 and recordsTable.transactionType = 'No') or
(ordersTable.bid = 1 and recordsTable.transactionType = 'Yes')
)
Another would be to use a case statement:
(case when recordsTable.transactionType = 'No' then 0 else 1 end) = ordersTable.bid
SELECT invTypes.typeName, stastations.stationName, main.* FROM referenceDB.invTypes, referenceDB.stastations, (
SELECT ordersTable.charName, ordersTable.stationID, ordersTable.typeID, ordersTable.bid, ordersTable.orderState, ordersTable.volRemaining
FROM ordersTable LEFT JOIN recordsTable ON ordersTable.typeID = recordsTable.typeID
AND ordersTable.stationID = recordsTable.stationID
AND ordersTable.charName = recordsTable.person
AND ((ordersTable.bid = 0 AND recordsTable.transactionType = 'yes') OR
(ordersTable.bid != 0 AND recordsTable.transactionType = 'no'))
WHERE recordsTable.typeID IS NULL
AND ordersTable.orderState IN (0) ) as main
WHERE stastations.stationID = main.stationID AND invTypes.typeID = main.typeID;
I have a table with 5 fields. Each field can store a number from 1 - 59.
Similar to countif in Excel, how do I count the number of times a number from 1 - 59 shows up in all 5 fields?
Here's an example for the count of occurances for the number 1 in all five fields:
SELECT SUM(pick_1 = 1 OR pick_2 = 1 OR pick_3 = 1 OR pick_4 = 1 OR pick_5 = 1) AS total_count_1
FROM tbldraw
Hopefully I made sense.
There was an answer here that had a solution. I think this is just a variation.
Step1: Create a numbers table (1 field, called id, 59 records (values 1 -59))
Step2:
SELECT numbers_table.number as number
, COUNT(tbldraw.pk_record)
FROM numbers_table
LEFT JOIN tbldraw
ON numbers_table.number = tbldraw.pick_1
OR numbers_table.number = tbldraw.pick_2
OR numbers_table.number = tbldraw.pick_3
OR numbers_table.number = tbldraw.pick_4
OR numbers_table.number = tbldraw.pick_5
GROUP BY number
ORDER BY number
How about a two step process? Assuming a table called summary_table ( int id, int ttl), for each number you care about...
insert into summary_table values (1,
(select count(*)
from table
where field1 = 1 or field2 = 1 or field3 = 1 or field4 = 1 or field5 = 1))
do that 59 times, once for each value. You can use a loop in most cases. Then you can select from the summary_table
select *
from summary_table
order by id
That will do it. I leave the coversion of this SQL into a stored procedure for those that know what database is in use.
The ALL() function, which returns true if the preceding operator is true for all parameters, makes the query particularly elegant and succinct.
To find the count a particular number (eg 3):
select count(*)
from tbldraw
where 3 = all (pick_1, pick_2, pick_3, pick_4, pick_5)
To find the count of all such numbers:
select pick_1, count(*)
from tbldraw
where pick_1 = all (pick_2, pick_3, pick_4, pick_5)
group by pick_1