Sum up the time values corresponding to same date - google-apps-script

Question

In my sheet column A is date and column B is time duration values, I want to find the dates which are repeated and sum up the corresponding time values of the repeated dates and show the sum in the last relevant repeated date. And delete all the other repeated dates. ie if 18/07/2019 is repeated 4 times i have to sum up all the four duration values and display the sum value in the 4th repeated position and delete the first three date 18/07/2019. I have to do this all those dates that are repeated. I have wrote code to my best knowledge
function countDate() {
var data = SpreadsheetApp.getActive();
var sheet = data.getSheetByName("Sheet5");
var lastRow = sheet.getLastRow();
var sh = sheet.getRange('A1:A'+lastRow);
var cell = sh.getValues();
var data= sheet.getRange('B1:B'+lastRow).getValues();
for (var i =0; i < lastRow; ++i){
var count = 0;
var column2 = cell[i][0];
for (var j =0; j < i; j++)
{
var p=0;
var column4 = cell[j][0];
if (column4 - column2 === 0 )
{
var value1 = data[j][0];
var value2 = data[i][0];
var d = value2;
d.setHours(value1.getHours()+value2.getHours()+0);
d.setMinutes(value1.getMinutes()+value2.getMinutes());
sheet.getRange('C'+(i+1)).setValue(d).setNumberFormat("[hh]:mm:ss");
sheet.deleteRow(j+1-p);
p++;
}
}
}
}
The copy of the sheet is shown
column C is the values I obtain through the above code AND column D is the desired value
After computing the sum I need to delete the repeated rows till 15 here

Answer 1

Answer:
You can do this by converting your B-column to a Plain text format and doing some data handling with a JavaScript dictionary.
Code:
function sumThemAllUp() {
var dict = {};
var lastRow = SpreadsheetApp.getActiveSpreadsheet().getSheets()[0].getLastRow();
var dates = SpreadsheetApp.getActiveSpreadsheet().getRange('A1:A' + lastRow).getValues();
var times = SpreadsheetApp.getActiveSpreadsheet().getRange('B1:B' + lastRow).getValues();
var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheets()[0];
sheet.getRange(1, 1, sheet.getLastRow(), sheet.getLastColumn()).setNumberFormat("#");
for (var i = 0; i < dates.length; i++) {
if (!dict[dates[i][0]]) {
dict[dates[i][0]] = times[i][0];
}
else {
var temp = dict[dates[i][0]];
var hours = parseInt(temp.split(':')[0]);
var minutes = parseInt(temp.split(':')[1]);
var additionalHours = parseInt(times[i][0].split(':')[0]);
var additionalMinutes = parseInt(times[i][0].split(':')[1]);
var newMinutes = minutes + additionalMinutes;
var newHours = hours + additionalHours;
if (newMinutes > 60) {
newHours = newHours + 1;
newMinutes = newMinutes - 60;
}
dict[dates[i][0]] = newHours + ':' + newMinutes;
}
}
SpreadsheetApp.getActiveSpreadsheet().getSheets()[0].getRange('A1:B' + lastRow).clear();
var keys = Object.keys(dict);
for (var i = 0; i < keys.length; i++) {
SpreadsheetApp.getActiveSpreadsheet().getSheets()[0].getRange('A' + (i + 1)).setValue(keys[i]);
SpreadsheetApp.getActiveSpreadsheet().getSheets()[0].getRange('B' + (i + 1)).setValue(dict[keys[i]]);
}
}
Assumptions I made:
There are a few assumptions I made when writing this, you can edit as needed but I figured I should let you know:
There are only dates in Column A and only times in Column B.
The times in column B are either Hours:Minutes or Minutes:Seconds. Either way, if the value to the right of the : hits 60, it adds one to the left value and resets.
The Sheet within the Spreadsheet is the first sheet; that which is returned by Spreadsheet.getSheets()[0].
References:
w3schools - JavaScript Objects
Spreadsheet.getSheets()
w3schools - JavaScript String split() Method
MDN web docs - parseInt() method
Google Sheets > API v4 - Date and Number Formats