I have a table with multiple fields that I am grabbing information from (8 to be specific) but within this query I need to group on one field (ID's) and sum two other fields separately (Units, MV). I can pull all the information together in 2-3 queries but I want to know if i can pull/put everything together in one query.
The correct result would be a query that groups the results on the ID field only, has both Units and MV summed separately but also have the other fields I need too. I can get part of the results in one query if I only have the grouped ID field and summed Units and MV fields but if I add any other fields then the results are incorrect. Any assistance would be appreciated.
I ended up messing around with using DISTINCT within the SQL portion of access and finally got the results. Thank you for all your help!
Related
so I'm very new to Access - just started learning it this week. I have data comprised of a bunch of policy numbers with corresponding ratings and premium values.
What I'm trying to do is create a query table that aggregates this data by rating (=1 or >1), this is the part I can't figure out. In design mode, I have put criteria =1 or >1, but it's not doing anything; when I switch to datasheet view, it just lists all of the ratings instead of two boxes that say =1 and >1. If anyone could give me insight on how to do this, I'd appreciate it!
From what I understand after reading your question, you want a query that shows two columns, one that counts the records with a rating of 1 and one that counts the records with a rating of greater than 1.
The best way to do this is to set up two expression columns, both wrapped in a count as you can see below:
SELECT Count(IIf([Rating]=1,[Rating],Null)) AS [=1], Count(IIf([Rating]>1,[Rating],Null)) AS [>1]
FROM tblSortRating;
If you have any questions or I've misunderstood your question leave a comment and I'll get back to you.
I have a table that contains data from repeated experiments (for example, site A has one sample, and the lab processed the sample three times obtaining slightly different values). I need to average these results in a separate table, but what I have read on the Microsoft support site is that a query that pulls data into another table with a calculated field is not possible on Access.
Can I query multiple data points from one table into a single calculated field in another table? Thank you.
UPDATE
I ended up doing a lot of manual adjustments of the file format to create a calculated field in the existing table that averages each sites data, so my problem is, for my current purposes, solved. However I would still like to understand. Following up with you both, I think the problem was that I had repeated non-unique IDs between rows when I probably should have made data columns with unique variable names so that I could query each variable name for an average.
So, instead of putting each site separately on the y axis, I formatted it by putting the sample number for each site on the x-axis:
I was able to at least create a calculated field using this second format in order to create an average value for each site.
Would have there been a way to write a query using the first method? Luckily, my data set was not at all very hefty, so I could handle a reformat manually, but if the case were with thousands of data entries, I couldn't have done that.
Also, here is the link to the site I mentioned originally https://support.office.com/en-ie/article/add-a-calculated-field-to-a-table-14a60733-2580-48c2-b402-6de54fafbde3.
Thanks all.
Ok here is my dilemma and I am sure more experienced Access users have an easy solution. I have been manually running a set of queries to pull data for business users, that I want to create a form for so they can just run it themselves. This would be easy if it was one query, but the way I have to pull the correct data is first have to run one query that creates a table. I then use that 'new' table in a secondary query to get the data I need.
That first make table query needs to take inputs like supplier number and date range. I then use that output table in another query that sums up total dollar value of purchase orders. I can not include these two steps in one query as it creates an ambiguous outer join.
Any ideas on how I would go about creating a form for something like this?
Well after re-thinking this I think I was OVER thinking it. Instead of creating a table in the first step, I can just save it as a query and join that query to the second query. Then make a form off the two queries.
Is it possible to have the SUM of all numaric fields in the last of a set of rows?
As of now, I'm using a very simple query such as:
SELECT
*,
SUM((UNIX_TIMESTAMP(end) - UNIX_TIMESTAMP(start))/3600)
FROM
times
in SQL you cant have a column that appears in only one row, likewise, you also cant have a row that doenst contain all the columns from the other rows.. So having a row that contains something unique is not possible. You can, however, add the calculated column to all rows in the dataset or do the calculation in the calling code after the data is returned.
I think what you are looking for is GROUP BY WITH ROLLUP you will find details on that in the MySQL manual.
I have list store in mysql table file1=(1,2,3,4,6,7) and other list file2 = (3,2,4,8,9,10,12) is not stored in table, i want compare both and result should be like
result=(6,7,8,9,10,12) then calculate the percentage. like 100*(result/file1+file2) in mysql data structure. i do not know how i will do it.
please know body know guide me or give me a small example.
thanks
Create a temporary table to store the "other" list that is not already in a table, and then use a join or union to get the result you want.
If you are wanting to select the values that are not in either list, then you can use GROUP BY and COUNT to count the occurrence of each number, and then HAVING to select those rows with a count of 1.
I don't think you can easily do that in pure sql. you need a procedural language to get the result in the first list, merge, sort, unique with the second list and compute the result.