I've a query:
select * from table where license='92cbb46d087' and email='email#gmail.com' and comments NOT LIKE '%0da44455%';
If I remove comments onwards it returns me 1 record. Even if I change the NOT LIKE string to anything but it is not printing a record.
What I want is find any license matching a license and email and whose comments record does not contain specific payment id. Indeed '%0da44455%' or '%xxxyyxxysss%' or any random string does not exist in the table in comments column.
If comments column can have NULL values, you won't get any output from NOT LIKE and LIKE conditions.
You need to write something like this instead :
WHERE (ISNULL(comments,'')) NOT LIKE '%0da44455%'
The reason behind this is simply because these conditions don't know how to behave with null values — How do you compare null as something that doesn't exist with another thing that doesn't exist?
Lets use subquery and select case to filter out those not like comments.
select * from (select case when coalesce(comments, '') not like '%0da44455%' then 1 else 0 end as tagCom
, * from table where license='92cbb46d087' and email='email#gmail.com') t1
where t1.tagCom = 0
Related
Name
UID
Late
Tin
ABC
0
Bob
ABC
0
SELECT * FROM `logs` WHERE Name='Tin' AND Name='Feryal'
This query returns nothing for me and only works when I want one name.
I could use the SELECT * but for this case I would like to call specific names in the query?
For this use In clause.
SELECT * FROM logs WHERE Name IN ('Tin', 'Feryal');
You can also use or clause
SELECT * FROM logs WHERE Name='Tin' OR Name='Feryal'
To add on to Amit Verma's answer.
SELECT * FROM `logs` WHERE Name='Tin' AND Name='Feryal'
Reading that SQL statement out loud, it sounds like this:
I want to select all the rows from logs where the name is equal to Tin AND the name is equal to Feryal.
You can quickly see from that statement, the reason why 0 rows are returned, it's because that is impossible! You cannot have somebody named both Tin and Feryal at the same time unless they are some bizarre super-positional being and the datatype in the table somehow allows for that.
Amit covers the rest.
This case is similar to: S.O Question; mySQL returns all rows when field=0, and the Accepted answer was a very simple trick, to souround the ZERO with single quotes
FROM:
SELECT * FROM table WHERE email=0
TO:
SELECT * FROM table WHERE email='0'
However, my case is slightly different in that my Query is something like:
SELECT * FROM table WHERE email=(
SELECT my_column_value FROM myTable WHERE my_column_value=0 AND user_id =15 LIMIT 1 )
Which in a sense, becomes like simply saying: SELECT * FROM table WHERE email=0, but now with a Second Query.
PLEASE NOTE: It is a MUST that I use the SECOND QUERY.
When I tried: SELECT * FROM table WHERE email='( SELECT my_column_value FROM myTable WHERE my_column_value=0 LIMIT 1 )' (Notice the Single Quotes on the second query)
MySql SCREAMED Errors near '(.
How can this be achieved
Any Suggestion is highly honored
EDIT1: For a visual perspective of the Query
See the STEN_TB here: http://snag.gy/Rq8dq.jpg
Now, the main aim is to get the sten_h where rawscore_h = 0;
The CURRENT QUERY as a whole.
SELECT sten_h
FROM sten_tb
WHERE rawscore_h = (
SELECT `for_print_stens_rowscore`
FROM `for_print_stens_tb`
WHERE `for_print_stens_student_id` =3
AND `for_print_stens_factor_name` = 'Factor H' )
The result of the Second Query can be any number including ZERO.
Any number from >=1 Works and returns a single corresponding value from sten_h. Only =0 does not Work, it returns all rows
That's the issue.
CORRECT ANSWER OR SOLUTION FOR THIS
Just in case someone ends up in this paradox, the Accepted answer has it all.
SEE STEN_TB: http://snag.gy/Rq8dq.jpg
SEE The desired Query result here: http://snag.gy/wa4yA.jpg
I believe your issue is with implicit datatype conversions. You can make those datatype conversions explicit, to gain control.
(The "trick" with wrapping a literal 0 in single quotes, that makes the literal a string literal, rather than a numeric.)
In the more general case, you can use a CAST or CONVERT function to explicitly specify a datatype conversion. You can use an expression in place of a column name, wherever you need to...
For example, to get the value returned by my_column_value to match the datatype of the email column, assuming email is character type, something like:
... email = (SELECT CONVERT(my_column_value,CHAR(255)) FROM myTable WHERE ...
or, to get the a literal integer value to be a string value:
... FROM myTable WHERE my_column_value = CONVERT(0,CHAR(30)) ...
If email and my_column_value are just indicating true or false then they should almost certainly be both BIT NOT NULL or other two-value type that your schema uses for booleans. (Your ORM may use a particular one.) Casting is frequently a hack made necessary by a poor design.
If it should be a particular user then you shouldn't use LIMIT because tables are unordered and that doesn't return a particular user. Explain in your question what your query is supposed to return including exactly what you mean by "15th".
(Having all those similar columns is bad design: rawscore_a, sten_a, rawscore_b, sten_b,... . Use a table with two columns: rawscore, sten.)
I'm trying to run a SQL SELECT statement against a column that is of type SET. The table is called myTable and the columns in myTable are called base_props and names. The base_props column is of type SET. The values in base_prop are vb,nt, cnt,poss and loc. So I would like to SELECT entries from the column 'name' where base_props have both the values, vb and poss. The results I'm looking to get may have values other than just vb and poss. So to be clear I would like to select all entries that have the values vb and poss regardless if they have other values as well. I've tried the following SQL queries but I can't get the desired results.
SELECT name from myTable WHERE base_props = 'vb' AND base_props = 'poss'
That query returns an empty result set. I've tried using FIND_IN_SET() and IN() but I couldn't get anywhere with that. I've written SQL statements before but never had to deal with columns that are type SET. Any help is appreciated.
The only thing I can come up with is using the LIKE keyword:
SELECT name FROM myTable WHERE (base_props LIKE '%vb%' AND base_props LIKE '%poss%');
This will make sure both vb and cnt are in the base_props column. Of course you can use cnt, nt and loc in there, or any number of base_props values in the sql, just add more AND statements.
OR as a deleted answer by samitha pointed out, you can use FIND_IN_SET:
SELECT name from myTable WHERE FIND_IN_SET('vb', base_props) AND FIND_IN_SET('poss', base_props);
Comment (by spencer7593): "both of these work, but there is a slight difference. The LIKE operator will actually match any member that includes the search string anywhere in a term; the FIND_IN_SET function will only match an exact member. It's also possible to search for members in set by the order they appear in the SET definition, using the MySQL BITAND operator: for example, to match the 1st and 4th members of the set: WHERE base_props & 1 AND base_props & 8". So for example, if you have 'a' and 'aaa' in your set, then using the LIKE "%a%" method will also return rows containing 'aaa'.
Conclusion: use the FIND_IN_SET solution since it will work for all cases.
FIND_IN_SET return index, Try this
SELECT name from myTable WHERE FIND_IN_SET(base_props, 'vb') > 0 AND
FIND_IN_SET(base_props, 'poss') > 0
I have records like these:
RCV0001
RCV0002
RTN0003
RTN0004
SLE0005
RCV0006
I want to query for records that start with 'RCV' only and display only records.
This is what I've tried so far:
select substring(documentnumber, 1)
LIKE '%RCV%'
from transactionheader
But I'm not getting my desired result. Any ideas? I'd gladly appreciate your help. Thanks.
Will need to add a filter on the where statement
select documentnumber
from transactionheader
where documentnumber LIKE 'RCV%'
The expression in the select list of your query returns a boolean, so the query will only return 0, 1 or NULL for every row in the table.
SELECT SUBSTRING(documentnumber, 1) LIKE '%RCV%'
FROM transactionheader
For every row in the table, the first character of documentnumber will be inspected to see if it contains the string 'RCV', which will never be true. The query is going to return 0 or NULL for every row.
There is more than one query that will return documentnumber that start with 'RCV'. Here is one example:
SELECT h.documentnumber
FROM transactionheader h
WHERE h.documentnumber LIKE 'RCV%'
The WHERE clause specifies the conditional tests that will be performed on each row, only rows that "satisfy" the predicate will be returned.
Your original query has no WHERE clause so everything is being selected. Also, I would recommend using REGEXP instead. Here is my rewritten example.
SELECT substring(documentnumber, 1)
FROM transaction header
WHERE documentnumber REGEXP '^RCV'
;
So I have a data with format like ;1;;2; and then I need to use this number in a query so I thought I'd convert it to 1,2 and use that in a IN condition. In my table, the result should return 2 rows but instead it is returning only 1 row.
My query is like this. The subquery return 1,2 with no problem but only 1 row is retrieve.
select *
from wt_lists
where id IN ((select replace (replace(sendto, ';;',','),';','')
from wt_stats where statsid IN (1)))
But when I try it with this. It returns the correct result, which in my case is 2 rows.
select *
from wt_lists
where id IN (1,2)
What am I missing here?
Comma delimited strings need to be explicitly defined in the query in order to be used in the IN clause - there's countless examples on SO where people need to use dynamic SQL to incorporate user submitted comma delimited strings.
That said, I have a solution using the FIND_IN_SET function:
SELECT DISTINCT wl.*
FROM WT_LISTS wl
JOIN (SELECT REPLACE(REPLACE(ws.sendto, ';;',','),';','') AS ids
FROM WT_STATS ws
WHERE ws.statsid = 1) x ON FIND_IN_SET(wl.id, x.ids) > 0
You are replacing the string:
';1;;2;'
To:
'1,2'
So, you SQL query looks like:
select * from wt_lists where id IN ('1,2') from wt_stats where statsid IN (1)
To use IN clause you need select different values in different rows.
I found this store procedure that does exactly what you need.
http://kedar.nitty-witty.com/blog/mysql-stored-procedure-split-delimited-string-into-rows/
I have not tested, but it is the way.
Obs: Like David said in the comments above, parsing the data in your application is a better way to do this.