SQL query gives no results when one of the tables is empty - mysql

I'm trying to perform a SQL query like this:
SELECT
t1.*
FROM
`table1` t1,
`table2` t2
WHERE
t1.x = 1
and the table called table2 (t2) is empty but inside t1 there are entries.
For example this query works perfect:
SELECT
t1.*
FROM
`table1` t1
WHERE
t1.x = 1
So just by adding the second table t2 in the FROM part the query gives no results anymore. So I don't understand what is going on here. In my case it should be possible that one of the tables is empty but the query still needs to give results. How can I achieve this?

Your syntax is using an implied JOIN between table1 and table2, and could be rewritten as:
SELECT t1.*
FROM `table1` t1,
CROSS JOIN `table2` t2
WHERE t1.x = 1
This is JOINing everything in table1 against everything in table2. However, as table2 is empty there is nothing to join to.
With an implied CROSS JOIN, results are only returned when the row on both sides of the join is matched, which in this case it cannot be. Therefore, nothing is returned.
If you rewrote the statement to use a LEFT JOIN, you would see all results from table1, and only matching results from table2:
SELECT t1.*
FROM `table1` t1,
LEFT JOIN `table2` t2 ON 1 = 1
WHERE t1.x = 1
Incidentally, typically you would only use this kind of query if there is a relationship in the data between table1 and table2. In this case, you would JOIN on the related columns, like so:
SELECT t1.*
FROM `table1` t1,
LEFT JOIN `table2` t2 ON t2.matchedColumn = t1.matchedColumn
WHERE t1.x = 1

Related

Return multiple rows from subquery

Basically I have two tables. 1 and 2. I need the field2 column in the table2 table to return multiple rows. I tried the below join (simplified the columns) but unfortunately it returns me only one result.
SELECT table1.field1, table1.field2, table1.field3, sub_q.field4
FROM table1
JOIN (
SELECT t2.field4, t2.filter1, t2.filter2 FROM table2 t2
) sub_q ON (sub_q.filter1 = table1.id AND sub_q.filter2 = 1)
##Should return multiple rows
##but returns only one!
WHERE table1.id = ..;
Edit:
I created a schema here: http://sqlfiddle.com/#!9/1c5737 with the select query as
SELECT t1.field1, t1.field2, t1.field3, t2.field1
FROM table1 t1
JOIN table2 t2 ON t2.filter1 = t1.id AND t2.filter2 = 1
WHERE t1.id = 1;
Only to find out that it works there, so I come back in shame to accept the answer and check where I messed up in my query (probably one of the fields)
Why are you using a subquery in the join? This is how it should be written:
SELECT table1.field1, table1.field2, table1.field3, t2.field1
FROM table1 t1
JOIN table2 t2 ON t2.filter1 = table1.id AND t2.filter2 = 1
Also it is likely that you need LEFT JOIN (or INNER JOIN) instead of JOIN, but cannot be sure without more details on what you're trying to achieve.

More rows after Left Join in MySQL

I've two tables, table1 contains 22780 rows. Now I left join table1 with table2 (which doesn't contain any duplicates) and I get 23588 rows.
SELECT * FROM Table1
left join Tabelle6 ON CAST(Table1.Customer AS Int) = table2.Customer
Why do I get more rows now? I only need every row from table1 once.
Edit: found my issue, table 2 does contain duplicates. But is there any way to join every row only once and ignore any further matches?
As the comment suggests, the easiest way to handle this would probably be to do SELECT DISTINCT to remove duplicates from your result set:
SELECT DISTINCT
t1.col1,
t1.col2,
t1.Customer,
...
FROM Table1 t1
LEFT JOIN Table2 t2
ON CAST(t1.Customer AS Int) = t2.Customer
But there is another option here. We could also join to a subquery which removes duplicate customers. This would ensure that no record from the first table gets duplicated from matching to more than one record in the second table.
SELECT *
FROM Table1 t1
LEFT JOIN
(
SELECT DISTINCT Customer
FROM Table2
) t2
ON CAST(t1.Customer AS Int) = t2.Customer

SQL - show results from table without values from another table

I need to show only results which are in Table1 and Table2 but are not in Table3. Basically, it should be something like TABLE1, Table2 except INNER JOIN between (TABLE1, Table2) and TABLE3.
Should looks like this - On left side Table1 and Table2, on right side Table3
Now I have this:
SELECT mesta_email, mesta_kod
FROM Table1
UNION ALL
SELECT mesta_email, mesta_kod
FROM Table2
// And somehow except values which are in Table3
Can somebody help me please? Thanks a lot.
There are a couple different ways to do this. I believe mysql does better with the outer join/null approach:
select t.*
from (
SELECT mesta_email, mesta_kod
FROM Table1
UNION ALL
SELECT mesta_email, mesta_kod
FROM Table2
) t left join Table3 t3 on t.mesta_email = t3.mesta_email
and t.mesta_kod = t3.mesta_kod
where t3.mesta_email is null
This assume table3 shares the same structure as the other 2 tables.
I would approach the problem almost directly as you write it, using exists and not exists:
select t1.mesta_email, t2.mesta_kod
from table1 t1
where exists (select 1
from table2 t2
where t2.mesta_email = t1.mesta_email and t2.mesta_kod = t1.mesta_kod
) and
not exists (select 1
from table3 t3
where t3.mesta_email = t1.mesta_email and t3.mesta_kod = t1.mesta_kod
);
One advantage of exists/not exists over other approaches involves duplicates. If one of the tables (say table1) has not duplicates, but the others might, there is no need to remove duplicates in the resulting data set.

Merge two queries and return one of the possible values

select value1 as value from T1 where id=10;
if id does not exist in T1 - execute another query:
select value2 as value from T2 where id=10;
So, I want to join these queries and return a single value (value1 or value2). Is it possible?
SOLUTION:
My solution:
select ifnull(value1, value2) as value from T1 left join T2 using(id) where id=10;
you can join the query using union
select value1 as value from T1 where id=10
union
select value2 as value from T2 where id=10;
as a result you can get any one of the value or both
TRY (tested)
SELECT COALESCE(t1.value1, t2.value2) AS Value FROM t1
INNER JOIN t2 USING(id)
WHERE id=10
this will always check first the table t1 for id=10, if there is no value then see table t2 for the same id
Quoted FROM
The single result column that replaces two common columns is defined
using the coalesce operation. That is, for two t1.a and t2.a the
resulting single join column a is defined as a = COALESCE(t1.a, t2.a)
You can join the two queries on the id field and then use the COALESCE function to combine the two resulting fields into the output.
This assumes that you already have a list of IDs to join against, though. Otherwise you're stuck doing a union or full join to get such a list first.
You Can use this too
select Distinct(s1.id) from sample1 as s1 inner join sample2 as s2;
use union of both
like below :
select t1.id from table1 as t1 where id=10
union
select t2.id from table2 as t2 where id=10

mysql query join/sub-query/union

Say I've two tables - "Table1" and "Table2" in my MySQL database.
"id" primary key (auto_increment) in "Table1" is the reference key in "Table2" - "tab_id".
There could be zero or more "Table2" rows for one "Table1" row.
Now I'm trying to do a search on one of the column in "Table2" say "email" column OR on one of the column in "Table1" say "address" and print "Table1" row values.
I see there are 3 possibilities:
1. Join
2. Sub-Query
3. Union
1 Join
SELECT *
FROM Table1 t1, Table t2
WHERE t1.id = t2.tab_id
AND (t1.address like '%str%' OR t2.email like '%str%');
-- This works fine, but when there are no rows in "Table2" relevant to "Table1" .. the JOIN will fail, hence output is in-consistent.
2 Sub-Query
SELECT *
FROM Table1 t1
WHERE t1.address like '%str%'
OR t1.id IN (SELECT t2.tab_id
FROM Table2 t2
WHERE t2.email like '%str%');
-- This works fine, but when there are two manys rows in "Table2" (say 5K) the query goes very slow :(
3 Union
SELECT 'relevant_columns'
FROM Table1 t1, Table t2
WHERE t1.id = t2.tab_id
AND (t1.address like '%str%' OR t2.email like '%str%')
UNION
SELECT 'relevant_columns'
FROM Table1 t1
WHERE t1.address like '%str%'
ORDER BY relevant_column
-- This works fine, may be create a view with a similar UNION, does the job.
Now, my question what is the correct way ... is it okay to call a UNION always?
MySQL Engine: MyISAM
SELECT *
FROM Table1 t1
LEFT JOIN Table t2 ON t2.tab_id = t1.id
WHERE t1.address like '%str%'
OR t2.email like '%str%';
You need to do a LEFT JOIN. When you make a FROM from two tables as you did, it works as an INNER JOIN (or a CROSS JOIN if there is no WHERE clause), which means that the output shows only rows that have a match in both tables. With LEFT JOIN you said that you want all rows from the left table (t1) with the matched row on the right table (t2). If there is no match in t2, then null is used.
You can use sub-query, but as you can see it is not the best choice
An UNION here does not give you any advantage. An UNION is useful to merge together datasets with same columns.
Edit
If you have issues with JOIN, because some Table1 rows do not appear, then you need a LEFT JOIN. The fact that takes a long time, is another problem. Those tables are not big at all, so I guess you need to do some index work on those tables.
If you want help about the union you need to tell me which are those relevant_columns, because they must have the same number of columns, same type and same sequence.
You might optimize the union without joins, depending on what you want to output when t2.email has a match. Here is an example
SELECT t1.id, t1.address, null as email
FROM Table1 t1
WHERE t1.address like '%str%'
union
SELECT t2.tab_id as id, null as address, t2.email
FROM Table t2
WHERE t2.email like '%str%';
SELECT *
FROM Table1 t1
LEFT JOIN Table2 t2
ON t1.id = t2.tab_id
WHERE t1.address like '%str%' OR t2.email like '%str%';