This question already has answers here:
How to remove the stripes that appears when using linear gradient property [duplicate]
(2 answers)
Closed 3 years ago.
I'm opening an HTML file with no content, just the full html skeleton. i styled the html by using this linear-gradient
body {
background: linear-gradient(#e66465, #9198e5);
instead of getting this expected outcome
I get this instead.
This example comes from https://developer.mozilla.org/en-US/docs/Web/CSS/linear-gradient
So what happens here is that the <html> element is just special. It is the height of the viewport, because it has to be, and it defaults to overflow:auto;. and yet, it's height is not explicitly defined, it is granted by the browser. So the gradient doesn't know where to get it's height value, and goes insane.
body {
background: linear-gradient(#e66465, #9198e5);
}
If we give the <html> element an explicit height, then all is fine. In fact not giving the <html> element a height of 100% tends to be the cause of many issues, that are all fixed by giving <html> a height. min-height: 100%; will work as well.
html {
height: 100%;
}
body {
background-image: linear-gradient(#e66465, #9198e5);
}
You could alternatively give the gradient itself a height of 100vh.
body {
background-image: linear-gradient(#e66465, #9198e5);
background-size: 100% 100vh;
}
As mentioned in CSS3 gradient background on body
html{
height:100%
}
body{
width:100px;
height:100px;
background:linear-gradient(red, black);
background-repeat:no-repeat;
height:100%
}
Hope this helps!
html,
body {
height: 100%;
}
body {
margin: 0;
background: linear-gradient(#e66465, #9198e5);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>Linear gradient background</title>
</head>
<body>
</body>
</html>
Related
This question already has answers here:
Responsive css background images
(19 answers)
Closed 5 years ago.
I have an html file, and I set the background url to an image, but the image does not fill the browser's width:
I also tried set the width property to make it wider, but it seems to have no effect.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
<style>
#bg {
height:1500px;
background: url("img/timg7.jpg") center top no-repeat;
width:1800px;
}
</style>
</head>
<body id="bg">
<div style="width:400px; height: 200px; background-color: antiquewhite">
BLOCK
</div>
</body>
</html>
You need the background-size attribute for this.
Your CSS should be:
#bg {
background: url("img/timg7.jpg");
background-size: cover;
background-repeat: no-repeat;
}
In this scenario, you should use background-size, there is a demo for background-size.
Try to use:
background-size: 120%;
Try to use:
background-size: cover;
and please remove those height and width
Try this:
#bg {
background: url("img/timg7.jpg") center top no-repeat;
background-size: cover;
}
#bg{
background: url("img/timg7.jpg");
background-repeat:no-repeat;
background-size:contain;
background-position:center;
}
You don't need an id on your body, as document.body with get it with JavaScript, and you can just use body in the CSS. Of course, that's not your issue. See the code below:
html,body{
padding:0; margin:0;
}
body{
background:url(img/timg7.jpg) no-repeat; background-size:cover;
}
By the way, you should use external CSS, so it's cached into Browser Memory.
Been writing code for the background of a website. The goals are 1) 100% height of the browser window for the first image 2) image stays centered in window and sides are cut off 3) on the home page there is also two additional images that need to have the same effect. Been trying and writing different code chunks and not getting anywhere. I can get one part which just breaks another. Thank you for any assistnaceCurrent code chunk is as follows:
<html>
<head>
<meta charset="UTF-8">
<title>Background Image</title>
<style>
* { margin: 0; padding: 0; }
.background {
background: no-repeat center center fixed;
-webkit-background-size: cover;
-moz-background-size: cover;
-o-background-size: cover;
background-size: cover;
}
</style>
</head>
<body>
<div class="background">
<img src="images/bg.png">
</div>
<div class="background bg2">
<img src="images/bg2.png">
</div>
</body>
</html>
Not sure if I fully understand what your question is but for your image to get the height of the window you need to
.background {
background-image: url(images/bg.png);
height: 100vh;
}
That way the background image will always use the full height of the viewport. Not sure about the rest of the question tho!
If I understand what you are trying to do, there are a few things with your code that is wrong. First I will explain a couple of things and then I'll provide the code that I came up with that works when I tested it. Here goes...
First, in your style element, where you have ".background:", you don't need any of the code that you wrote. The stuff that mentions webkit, moz, etc. is really for stuff that may have cross browser compatibility problems. background-size is not one of those things you would have to worry about with that. The only thing I would put in your "background" class is width and height of 100%.
Second, speaking of width and height, I would include and "html" and "body" element and give them both a width and height of 100%.
Third, you are trying to have your images listed in your html, but you are trying to style them as if you are having your css produce them. Notice how in my html I left the "background" divs empty and then included the url of the photos in the css.
In a nutshell, I believe you may be a little confused as to what method should be used and when/where, because you are actually fusing different approaches together. That said, here is the code I wrote...
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Background Image</title>
<style>
* { margin: 0; padding: 0; }
html, body {
width: 100%;
height: 100%;
}
.background {
width: 100%;
height: 100%;
}
#bg1 {
background: url(images/bg.png) no-repeat center;
background-size: cover;
}
#bg2 {
background: url(images/bg2.pngg) no-repeat center;
background-size: cover;
}
</style>
</head>
<body>
<div class="background" id="bg1">
</div>
<div class="background" id="bg2">
</div>
</body>
</html>
Here is a link that may help you too. They have great directions, exercises and tutorials: w3schools.com
Hope all of that helps Zack! :)
This question already has answers here:
Fullscreen responsive background image in CSS
(5 answers)
Closed 7 years ago.
All:
I am pretty new to CSS background. I wonder if there is any way that I can resize background image to make it always fill the viewport as possible with only CSS.
The rule is:
No matter what ratio of the image, it always scale itself just enough to fill the viewport to make sure no empty space left.
<html>
<head>
<title>BLURRING IMG</title>
<style type="text/css">
html, body {
width: 100%;
height: 100%;
overflow: hidden;
padding:0px;
margin:0px;
}
body {
background: url("https://s3-us-west-2.amazonaws.com/s.cdpn.io/652/ferns-unsplash.jpg");
background-position: fixed;
background-size: 100%, cover;
}
</style>
</head>
<body>
</body>
</html>
And I also want to know what is the difference between:
background-size: auto auto, cover;
and
background-size: cover;
Thanks
background-size: coverand background-position: fixed
I need to make a website for a project. How can I make a moving gif as a fullscreen background?
Here is what I've done so far (an example)
HTML
<head>
<title>OFFICIAL SQUIDDINC</title>
<div class="gif-container"></div>
<head>
<html>
CSS
html, body {
height: 100%;
margin: 0;
}
.gif-container {
background: url("image.gif") center;
background-size: cover;
height: 100%;
}
There's a couple of things gone amiss in this snippet.
For the HTML;
You're missing an opening <html> tag. Albeit this may just be a bad copy paste for the question.
Your <title> is the only thing here that belongs inside the <head> tag.
The rest of your html should be encapsulated within a <body> tag.
<html>
<head>
<title>OFFICIAL SQUIDDINC</title>
<head>
<body>
<div class="gif-container"></div>
</body>
</html>
For the CSS;
You don't need to set a height for the html, body, however you will need to set it for the gif container. I've gone ahead and used the units vh and vw. These mean viewport height and viewport width, respectively. By specifying 100 for each, this will equal exactly the height and width of the browser viewport (screen).
html, body {
margin: 0;
padding: 0;
}
.gif-container {
background: url("image.gif") no-repeat 0 0;
background-size: cover;
height: 100vh;
width: 100vw;
}
DEMO;
http://codepen.io/anon/pen/Byevzv
I've seen these answers already: this, this, this and this.
But it didn't help.
My program is here: http://jsfiddle.net/nav9/6VeB7/9/
Two questions:
1. Does it make sense to have such background code placed within the html tag or the head tag instead of inside the body tag?
2. How do I get a gradient over the background image? It works fine when I place the background image in the html tag and the gradient in the head tag, but I want both in the same tag.
The CSS:
body
{
width: 100%;
height: 100%;
margin: 0px 0px 0px 0px;
/*background: radial-gradient(rgba(45,255,27,0.8), rgba(255,162,12,0.87), rgba(14,12,12,1));*/
background: radial-gradient(rgba(45,255,27,0.8), rgba(255,162,12,0.87), rgba(14,12,12,1));/*, url("images/starTile.png") repeat;*/
background-image: url("images/starTile.png") repeat;
position: fixed;
}
The HTML:
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<link rel="stylesheet" type="text/css" href="Styles.css">
</body>
</html>
UPDATE:
This is the reason it's not a duplicate: I'm trying to repeat the starTile, and the gradient doesn't work when I use repeat. But if I use no-repeat, I can see the gradient as well as a single starTile image.
body
{
background-image: url('images/starTile.png'), radial-gradient(rgba(45,255,27,0.8), rgba(255,162,12,0.87), rgba(14,12,12,1));
background-repeat: repeat, no-repeat;
background-position: left center, left top;
background-size: auto, 100% 100%;
}