Is there a way to include double condition in HAVING? - mysql

Question

I'm currently working on a query that looks like this. There are two tables - members and member_gathering.
SELECT id, city_id, name FROM members
WHERE "id" = "member_id" IN
(
SELECT "member_id" from member_gathering
GROUP BY "member_id"
HAVING COUNT(DATEDIFF("visited","joined">=365))>=5
ORDER BY "member_id"
)
ORDER BY id*1;
The goal is to have an output of all IDs satisfying the condition of being in more than 5 groups, in which a member is active for more than a year. Being active means having a difference between "visited" and "joined" columns (both are TIMESTAMP) for more than a year (I set that as 365 days).
However, after running, this code shows all the rows in a members table (though manual check of both tables shows that some rows do not satisfy both conditions at the same time).
Any ideas on how to improve the code above? I'm not sure if I can use 'nested' condition inside COUNT(), but all other variants used before show either NULL values or returned all rows in the table, which is obviously not right. Also, I was thinking that problem might be with DATEDIFF function.
All suggestions are welcome: I'm a newbie to MySQL, so I'm not that familiar with it.
UPD: data sample:
1) members
id city_id name
2 980 Joey
5 980 Carl
10 1009 Louis
130 1092 Andrea
2) member_gathering
member_id gathering_id joined visited
2 1 2010-01-01 00:00:00 2010-02-01 00:00:00
2 2 2010-01-01 00:00:00 2010-02-01 00:00:00
5 2 2010-01-01 00:00:00 2010-02-01 00:00:00
10 3 2010-01-01 00:00:00 2010-02-01 00:00:00
130 1 2010-02-01 00:00:00 2013-02-01 00:00:00
130 2 2010-02-01 00:00:00 2013-02-01 00:00:00
130 3 2010-02-01 00:00:00 2014-02-01 00:00:00
130 4 2010-02-01 00:00:00 2018-02-01 00:00:00
130 5 2010-02-01 00:00:00 2015-02-01 00:00:00
Expected result would be only ID 130, thus: 130, 1092, Andreana.

Answer 1

I believe you first need to find all records where datediff is 365 days or more. Then find members who have 5 or more such instances. This needs both WHERE and HAVING clause:
SELECT id, city_id, name
FROM members
WHERE id IN (
SELECT member_id
FROM member_gathering
WHERE DATEDIFF(visited, joined) >= 365
GROUP BY member_id
HAVING COUNT(*) >= 5
)

Answer 2

You could use this way
SELECT id, city_id, name FROM members
WHERE member_id IN
(
SELECT member_id from member_gathering
GROUP BY member_id
HAVING SUM(DATEDIFF(visited, joined) >= 365)>=5
ORDER BY member_id
)
You should use separated expression for count differente category of datediff and remmeber that count work for not null values so if you want obtain the totale for true values you should sue SUM