Converting latitude/longitude point to x, y points on the screen Cesium - cesiumjs

I want to be able to check if a given latitude/longitude point is in view in a Cesium globe. Is there a way to convert latitude and longitude to x, y points on the screen, if not then return undefined?

Related

How do i convert GPS coordinates in decimal place to kilometers? I am trying write a function that does this

For Example lets say I have 2 coordinates (lat:7.xxxxx and Long:3.xxxx) and (lat:8.xxxxx and long:5.xxxxx)
I want to tell the distance between the 2 points in kilometers.

Convert LatLng to (x, y) coordinates

I'm working on Google maps which will show multiple vehicles. I've two points(one point which will be the old position and other will be the present position) this positioning system will help write an equation of a line passing through these two points. Which might intersect with other line and inform me about the probability of collision.
But the problem is that I'm fetching the coordinates from the GPS module and it will give the location in Latitude and Longitude format.
I'll need x, y coordinates for this writing the equation of the line passing through them. I've already explored most of the method in different web pages, but the problem is that they will ask for some screen size(or map bounds) which are kind of not compatible with my type of method.
Questions: What is the method to convert Latitude and Longitude to (x, y) coordinates, just like if we see from the space and earth was flat and taking Gulf of Guinea (Lat: 0°, Lon: 0°) as the origin.
If your task requires high accuracy you have to use Latitude/Longitude and to solve Great Circle intersection task. The Earth is not flat.
If you can accept existence of some error in your calculations AND all of your vehicles are located in small limited area (up to 100km, although it depends on error you can accept) you may assume this confined area as flat.
For instance, if one your vehicle is located at N10.0 E10.0, second one is located at N10.1 E10.2, you may choose N10.0 E10.0 as the origin.
As a result, these two vehicles will have the following (X, Y) coords (it assumes that axis X goes along equator):
1) (0.0km 0.0km)
2) (21.86km 11.1km)
X of second vehicle is (40000km / 360 degrees) * cos(10.0) * (10.2 - 10.0) = 21.86km
Y of second vehicle is (40000km / 360 degrees) * (10.1 - 10.0) = 11.1km
If you will try to apply flat line-line intersection for vehicles located in 10 000 km from each other - your calcutions most probably will be incorrect.

Converting degrees to other units of measurement

I am storing a point as latitude and longitude in a Mysql server. They are both float(10,6). Given a radius, say 100 yards or 100 meters, how can I calculate points around the center. I was thinking of using GIS but I heard it is incomplete or very limited in functionality.
1) Tranform the lat/lon to a cartesian based coordinate system of units meter,
the tranformed point is now at (x,y)
2) Use school mathemathics (polar coordinates) to calculate the points:
2a) create points on circle at (0,0) with polar coordinates (r* sin (phi), r* cos(phi)), r in meters, phi in radians
2b) add (x,y) to all that resulting points, to move the circle points from center (0,0) to (x,y)
3) tranform all points back to lat/lon

Correctly draw on Google Maps a point which exceeds 90 degrees of latitude

I'm working on a simulator that plots the flight path of an aircraft on Google Maps.
The simulator is not aware that the latitude is only defined between -90 and +90 degrees and the longitude between -180 and +180 deg. As a result of this, the flight path may include points beyond the map boundaries. Exceeding in longitude is not an issue as it still plots correctly (a point at longitude x and x+360 is the same), but the latitude is a problem.
Is there any way of telling Google Maps to keep the points between the correct boundaries and plot them correctly?
Otherwise, do you have any ideas of where to find functions that do so?
Longitude, latitude and elevation are a bad coordinate system for a flight simulator, because the mapping presents singularities i.e. there are points infinitely close on the earth that have very different coordinates. For example where you're close to one of the poles longitude variation speed can become arbitrarily big compared to airplane speed. When standing exactly on the pole the longitude doesn't even make sense.
A better solution is to use an XYZ coordinate system for the simulator and only convert to longitude/latitude and elevation for plotting. If you can approximate the earth to a sphere for your use case the computation of this transformation is trivial... otherwise things can get much more complex depending on how accurate you want it to be.
That said it's still possible to give "a" meaning to a point with latitude slightly outside the range -90...90 by extending it over the pole...
if latitude < -90:
latitude = -180 - latitude
longitude = longitude + 180
if latitude > 90:
latitude = 180 - latitude
longitude = longitude + 180
but using this coordinate system for navigating is a very bad idea (the same point in space can have multiple triplets of coordinates).
If your simulator doesn't know that the maximum value for latitude is 90 degrees it is broken and needs to be fixed. Google Maps works correctly for valid/possible values of latitude and longitude.

How do I convert from this weird Coordinate unit to LngLat for use in Google Maps?

I have a database full of rows if coordinate pairs like this:
ux: 6643641
uy: 264274
uz: NULL
I have been tasked to make all these coordinates appear on google maps as points of interest, but nobody could tell me what the hell those coordinates were.
What I need for Google Maps is longitude and lengtitude coordinates. I know the one can be converted to the other, but nothing more.
I realize this might not be the correct place to ask about coordinate systems, but I honestly couldn't think of any other place to state the question.
Thanks for any help!
That's my bad, I now see that there is more data for each row:
CoordSystemNumber: 23
CoordSystemName: EUREF89 UTM Sone 33
I think that format is called UTM. You need to know the Zone and Hemisphere to complete the conversion. Is there other data associated with this?
Tell me if this seems helpful :
x = 882880 meters
y = -4924482 meters
z = 3944130 meters
Geocentric latitude and longitude are not commonly used, but they are defined by
latitude = arctan( z / sqrt( x^2 + y^2 ) )
longitude = arctan( y / x )
Taken from here :
http://www.cv.nrao.edu/~rfisher/Ephemerides/earth_rot.html
see this too :
http://en.wikipedia.org/wiki/Geographic_coordinate_system
This wikipedia article might offer some help.
The coordinates are often chosen such that one of the numbers represent vertical position, and two or three of the numbers represent horizontal position. A common choice of coordinates is latitude, longitude and elevation.