I want to get the current day using dart.
Code I want:-
//I want something like this
var day = DateTime.getCurrentDay();
Output:-
Tuesday
use this pattern
DateFormat('EEEE').format(yourDate);
or
DateFormat('EEEE').format(DateTime.now());
See all available patterns here
ICU Name Skeleton
-------- --------
DAY d
ABBR_WEEKDAY E
WEEKDAY EEEE
ABBR_STANDALONE_MONTH LLL
STANDALONE_MONTH LLLL
NUM_MONTH M
NUM_MONTH_DAY Md
NUM_MONTH_WEEKDAY_DAY MEd
ABBR_MONTH MMM
ABBR_MONTH_DAY MMMd
ABBR_MONTH_WEEKDAY_DAY MMMEd
MONTH MMMM
MONTH_DAY MMMMd
MONTH_WEEKDAY_DAY MMMMEEEEd
ABBR_QUARTER QQQ
QUARTER QQQQ
YEAR y
YEAR_NUM_MONTH yM
YEAR_NUM_MONTH_DAY yMd
YEAR_NUM_MONTH_WEEKDAY_DAY yMEd
YEAR_ABBR_MONTH yMMM
YEAR_ABBR_MONTH_DAY yMMMd
YEAR_ABBR_MONTH_WEEKDAY_DAY yMMMEd
YEAR_MONTH yMMMM
YEAR_MONTH_DAY yMMMMd
YEAR_MONTH_WEEKDAY_DAY yMMMMEEEEd
YEAR_ABBR_QUARTER yQQQ
YEAR_QUARTER yQQQQ
HOUR24 H
HOUR24_MINUTE Hm
HOUR24_MINUTE_SECOND Hms
HOUR j
HOUR_MINUTE jm
HOUR_MINUTE_SECOND jms
HOUR_MINUTE_GENERIC_TZ jmv (not yet implemented)
HOUR_MINUTE_TZ jmz (not yet implemented)
HOUR_GENERIC_TZ jv (not yet implemented)
HOUR_TZ jz (not yet implemented)
MINUTE m
MINUTE_SECOND ms
SECOND s
// DateTime.now() or any DateTime format can be used.
DateFormat('EEEE').format(DateTime.now());
To use other Date formats/patterns like "EEEE" you can visit the Official Documentation
Related
I see below datetimestamp in json but not sure which format is this??
20220914171900Z-0700
any suggestions??
Thanks in advance!
I used constructDateString but no luck!
2022 - yyyy (Year)
09 - MM (Month)
14 - dd (day of month)
17 - HH (Hour of day)
19 - mm (Minute of hour)
00 - ss (Second of minute)
Z-0700 - Z stands for Zulu and represents 00:00 hours offset from UTC. So, Z-0700 means an offset of 07:00 hours from UTC. If you want to get this date-time at UTC, you can do so by adding 07:00 hours to 2022-09-14T17:19.
Demo using Java:
import java.time.OffsetDateTime;
import java.time.ZoneOffset;
import java.time.format.DateTimeFormatter;
class Main {
public static void main(String[] args) {
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("uuuuMMddHHmmss'Z'Z");
String strDateTime = "20220914171900Z-0700";
OffsetDateTime odt = OffsetDateTime.parse(strDateTime, dtf);
System.out.println(odt);
// The same date-time at UTC
OffsetDateTime odtUTC = odt.withOffsetSameInstant(ZoneOffset.UTC);
System.out.println(odtUTC);
}
}
Output:
2022-09-14T17:19-07:00
2022-09-15T00:19Z
ONLINE DEMO
Note: You can use y instead of u here but I prefer u to y.
Learn more about the modern Date-Time API from Trail: Date Time.
I want to have date of every weeks.
I put 07/02/2022 in F5 cell and put =EDATE(F5 + 7) in G5 cell
But N/A comes in G5
I guess maybe I put 07/02/2022 in F5 in a wrong way..
What should I do?
read the error message:
Wrong number of arguments to EDATE. Expected 2 arguments, but got 1 arguments.
correct G5 to =EDATE(F5,7)
In case you refer to tomorrow's date, that is 2/7/2022.
You are, if you read the help, adding 7 months with the command above.
The date of the next week starting on any day
function nextWeekDateStartingOnThis(day = 1) {//Sun(0) - Sat(6)
let dt = new Date();
let nd = new Date(dt.getFullYear(), dt.getMonth(), dt.getDate() + 7 - dt.getDay() + day);
Logger.log(nd);
return nd;//this returns the date of the next monday because day = 1
}
If you want the date of the next tuesday then make day = 2
I have 3 tables in an Access database with the same column names (TempDate and Temp), but different time stamps. The data was collected in 10 minute intervals, but each of the recording devices had different start times. I want to merge these into one table with a single TempDate and one Temp column for each of the tables (temp1, temp2, temp3).
I need help on how to do this in either Access or R. I've started using R with MySQL code but I'm still very new at it. Thanks in advance. Ultimately I want to join this data to another dataframe with a datetime stamp from the same period of dates. I think I can manage that if someone can show me how to tell it to group by an interval. Then finally plot using ggplot
Data
temp1<-data.frame(TempDate=c("2020/08/11 07:13:01","2020/08/11 07:23:01","2020/08/11 07:33:01","2020/08/11 07:43:01"),Temperature=c(1.610,-1.905,-1.905,-0.901))
temp2<-data.frame(TempDate=c("2020/08/11 07:10:01","2020/08/11 07:20:01","2020/08/11 07:30:01","2020/08/11 07:40:01"),Temperature=c(15.641,15.641,15.641,15.641))
temp3<-data.frame(TempDate=c("2020/08/11 07:19:01","2020/08/11 07:29:01","2020/08/11 07:39:01","2020/08/11 07:49:01"),Temperature=c(2.062,3.573,4.076,4.579))
> temp3 #as example
TempDate Temperature
1 2020/08/11 07:19:01 2.062
2 2020/08/11 07:29:01 3.573
3 2020/08/11 07:39:01 4.076
4 2020/08/11 07:49:01 4.579
#what I want row 1 is temps recorded from 07:10:00-07:29:59, etc
>
TempDate Temp1 Temp2 Temp3
1 2020/08/11 07:10:00 1.610 15.641 2.062
2 2020/08/11 07:20:00 -1.905 15.641 3.573
3 2020/08/11 07:30:00 -1.905 15.641 4.076
4 2020/08/11 07:40:00 -1.901 15.641 4.579
UPDATE:
Thanks to Ben for the great answer to get me started solving this problem. In asking another question, floor_date was suggested. This code worked better for my data than the cut function by #Ben. When using cut I would get times ending in 9 (12:19) instead of 0 (12:10). I also tried TempDate+60 within the cut function, but then some dates would get a time in the next 10 minute interval. The below code was more accurate.
library(lubridate)
tempdata<-bind_rows(burrow=burrow,shade=shade,sun=sun,.id='Series') %>%
mutate(TempDate = as.POSIXct(TempDate, tz="UTC"),
TimeStamp = floor_date(TempDate, unit='10 mins'),
TimeStamp = as.POSIXct(TimeStamp, tz="UTC")) %>%
filter(TimeStamp > as.POSIXct("2020-08-12 13:29:00", tz="UTC")) %>%
select(Series, Temperature,TimeStamp) %>%
arrange(TimeStamp)
In R you could do the following, using tidyverse approach.
First, you can use bind_rows to put all your data frames together, and add a source column with the name of data frame those temperatures came from, or destination column in final result.
Then, make sure your TempDate is POSIXct. You can use cut to put your datetimes into 10 minute intervals.
At this point, I would consider leaving the result as is for plotting with ggplot2. It's often preferable to leave in "long" format instead of "wide". However, if you want it in "wide" format, then you can use pivot_wider from tidyr.
library(dplyr)
library(tidyr)
bind_rows(temp1 = temp1, temp2 = temp2, temp3 = temp3, .id = 'source') %>%
mutate(TempDate = as.POSIXct(TempDate),
NewTempDate = cut(TempDate, breaks = "10 min")) %>%
pivot_wider(id_cols = NewTempDate, names_from = source, values_from = Temperature)
Output
NewTempDate temp1 temp2 temp3
<fct> <dbl> <dbl> <dbl>
1 2020-08-11 07:10:00 1.61 15.6 2.06
2 2020-08-11 07:20:00 -1.90 15.6 3.57
3 2020-08-11 07:30:00 -1.90 15.6 4.08
4 2020-08-11 07:40:00 -0.901 15.6 4.58
In Access (VBA), you can round the times down like this:
texttime = "2020/08/11 07:19:01"
truetime = DateValue(texttime) + TimeSerial(Hour(CDate(texttime)), (Minute(CDate(texttime)) \ 10) * 10, 0)
' Result:
' 2020-11-08 07:10:00
However, how to implement this in R, I don't know.
I need to convert month number to month name.
I have date time as the date type - 2009-01-01 00:00:00.000
I also have 4-byte integer data type - 1
how do I convert this 1 to "January" for example?
i think you are in the data flow:
it is really easy to get MOnth Name in a script component from Date:
add a varchar column to your dataflow
Mark your date column for read access
enter the following script
Row.[NewColumnName] = Row.[Your Date Column].ToString("MMMM");
Result:
Here is a good translations for any date part to string formatting:
// create date time 2008-03-09 16:05:07.123
DateTime dt = new DateTime(2008, 3, 9, 16, 5, 7, 123);
String.Format("{0:y yy yyy yyyy}", dt); // "8 08 008 2008" year
String.Format("{0:M MM MMM MMMM}", dt); // "3 03 Mar March" month
String.Format("{0:d dd ddd dddd}", dt); // "9 09 Sun Sunday" day
String.Format("{0:h hh H HH}", dt); // "4 04 16 16" hour 12/24
String.Format("{0:m mm}", dt); // "5 05" minute
String.Format("{0:s ss}", dt); // "7 07" second
String.Format("{0:f ff fff ffff}", dt); // "1 12 123 1230" sec.fraction
String.Format("{0:F FF FFF FFFF}", dt); // "1 12 123 123" without zeroes
String.Format("{0:t tt}", dt); // "P PM" A.M. or P.M.
String.Format("{0:z zz zzz}", dt); // "-6 -06 -06:00" time zone
Furthermore, you asked about quarters. I don't think it is as easy but here is something I stole from another answer.
Build DateTime extensions:
Normal Quarter:
public static int GetQuarter(this DateTime date)
{
return (date.Month + 2)/3;
}
Financial Year Quarter (This case is for quarters that start on April 1):
public static int GetFinancialQuarter(this DateTime date)
{
return (date.AddMonths(-3).Month + 2)/3;
}
Integer division will truncate decimals, giving you an integer result. Place methods into a static class and you will have an extension method to be used as follows:
Row.calendarQuarter = Row.[your Date Column].GetQuarter()
Row.fiscalQuarter = Row.[your Date Column].GetFinancialQuarter()
In SQL Server, one method is:
select datename(month, datefromparts(2000, 1, 1))
The first "1" is the column for the month. The year is arbitrary.
following steps:
create variable with datetime datatype and assigned value.
used MONTH function in ssis to extract month number and assigned to new variable with integer data type: #[User::newdata]= MONTH( #[User::dbdate])
finally used if else condition which manually compare all 12 months
(code available:1)
I am pulling XML data from a 3rd party application using SQL Server 2008 (which I only have read-only access to the DB) and it stores the day or days of the week a job is supposed to run in one of those XML fields.
SQL uses a recursive day code of Sunday=1, Monday=2, Tuesday=4, Wednesday=8, Thursday=16, Friday=32, Saturday=64.
I am pulling the day from this XML field like the following.
case
when (job.SJDefn.value('(schedules/schedule/name)[1]', 'varchar(30)') ) like '%Week%'
then job.SJDefn.value('(/schedules/schedule/recurring/date/week/day_of_week)[1]', 'int')
else 0
end as JDOW,
I was originally utilizing the this to determine the current date of the week as but the values were obviously not compatible.
DATEPART(dw, getdate()) AS CDOW, -- Sun 1 Mon 2 Tue 3 Wed 4 Thu 5 Fri 6 Sat 7`
So I moved to:
case DATEPART(dw, getdate())
when 1 then 1 -- Sunday (1=1)
when 2 then 2 -- Monday (2=2)
when 3 then 4 -- Tueday (3=4
when 4 then 8 -- Wednesday (4=8)
when 5 then 16 -- Thursday (5=16)
when 6 then 32 -- Friday (6=32)
when 7 then 64 -- Saturday (7=64)
else NULL
end as CDOW,
The challenge is that it is an easy translation when the job just runs one day of a week.. but what about Monday/Wednesday/Friday well that is 42 which is an aggregate of the days Monday (2) + Wednesdays (8) + Friday (32).
I could translate this to text like in this question and do a string compare to a temp table but that seems inefficient.
I know that there is a table that can be built like this code to build a comparison table and I've checked the SQL Server Agent documentation (which this isn't but it is quite similar.
It seems like all possible combinations for Sunday - Saturday are basically a bitmap ranged from 1-127.. such as 42 = 0010 1010 which could be an on/off values for each day (first position always 0, 127 = 0111 111) and with that.
Position 1 = Always 0 ; binary 0000 0000
Position 2 = Sunday 1 ; binary 0000 0001
Position 3 = Monday 2 ; binary 0000 0010
Position 4 = Tueday 4 ; binary 0000 0100
Position 5 = Wednesday 8 ; binary 0000 1000
Position 6 = Thursday 16 ; binary 0001 0000
Position 7 = Friday 32 ; binary 0010 0000
Position 8 = Saturday 64 ; binary 0100 0000
I am thinking about how to potentially use a bitwise & operator but it compares the entire bit for an exact match and not a single position as I understand it so not thinking it will accomplish exactly what I want.
What I want is if the current day is in the schedule I get a true / false result from the comparison. I don’t care about interpreting the values into plain English.. For example if the string was 0011 1110 (Monday - Friday), then if the current day value is the equivalent of 0000 0010 (Monday) I be get true. If it was Sunday (0000 0001) it would be false if the reference was that 0010 1110.
I would really think there is a much simpler way of simply checking if the current day falls into the configuration in a few lines vs. building a temporary table to compare against.
So my question: given the information above, is there a simple function / query that I can execute to compare the two and return a boolean result (0/1 or Y/N) if the the current day matches the schedule?
This will give you a 1/0 result for the current date given a schedule bitmap:
declare #Today as Date = GetDate();
-- Assuming that ##DateFirst is correctly set:
declare #DoW as Int = DatePart( weekday, #Today );
-- Shift a bit to the appropriate position.
declare #Mask as Int = Power( 2, #DoW - 1 );
-- Sample schedule bitmap.
declare #Schedule as Int = 42;
-- Sign is used to convert the result of the bitwise-and to a 0 or 1.
-- Any positive value, indicating the corresponding bit is set, will return 1.
-- If there is no match, the result will be zero.
select #Today as Today, #DoW as Dow, #Mask as Mask, #Schedule as Schedule,
Sign( #Schedule & #Mask ) as IsScheduledToday;
As a professor once said, "you're always off by one in this business." It may need a tweak, but should be close.
It's a little difficult to tell exactly what you're trying to do here. You've explained the problem, but didn't provide any desired output. Since you have read-only access, however, I assume you're only interested in querying the data.
However, if you have an integer like 42, and you want to test bitwise if the bit for Monday is set (that is, 2's place), then you do this:
42 & 2 = 2
If you want to display days of the week you could do something like:
SELECT
CASE WHEN JDOW & 1 = 1 THEN 'U' ELSE '' END
+ CASE WHEN JDOW & 2 = 2 THEN 'M' ELSE '' END
+ CASE WHEN JDOW & 4 = 4 THEN 'T' ELSE '' END
+ CASE WHEN JDOW & 8 = 8 THEN 'W' ELSE '' END
+ CASE WHEN JDOW & 16 = 16 THEN 'R' ELSE '' END
+ CASE WHEN JDOW & 32 = 32 THEN 'F' ELSE '' END
+ CASE WHEN JDOW & 64 = 64 THEN 'S' ELSE '' END AS scheduled_days
FROM (VALUES (42),(84),(96), (4)) UnnamedTable (JDOW)
If you want you could create another table:
CREATE TABLE BitwiseWeekDay (
code tinyint primary key not null,
day_name nvarchar(10) not null,
day_short_name nvarchar(4) not null,
day_code nvarchar(1) not null
)
INSERT INTO BitwiseWeekDay VALUES
(1,'Sunday','Sun','U'),
(2,'Monday','Mon','M'),
(4,'Tuesday','Tue','T'),
(8,'Wednesday','Wed','W'),
(16,'Thurday','Thur','R'),
(32,'Friday','Fri','F'),
(64,'Saturday','Sat','U')
SELECT u.JDOW,
b.code,
b.day_name
FROM (VALUES (42),(84),(96), (4)) u (JDOW)
INNER JOIN BitwiseWeekDay b
ON u.JDOW & b.code = b.code
ORDER BY u.JDOW, b.code
But, I don't really know what you're looking for.