cannot parse json to xml using xmltodict.unparse when converting json list - json

Question

Trying to do this using xmltodict.unparse:
I have this structure in json:
"organisations": [
{"organisation": "org1"},
{"organisation": "org2"},
{"organisation": "org3"}
]
But comes out like this in xml:
<organisations><organisation>org1</organisation></organisations>
<organisations><organisation>org2</organisation></organisations>
<organisations><organisation>org2</organisation></organisations>
I wanted like this:
<organisations>
<organisation>org1</organisation>
<organisation>org2</organisation>
<organisation>org2</organisation>
</organisations>
Im using xmltodict.unparse
def dict_to_xml(d, pretty_print=False, indent=DEFAULT_INDENT, document_root="root"):
if len(d.keys()) != 1:
d = {
document_root: d
}
res = xmltodict.unparse(d, indent=indent, short_empty_elements=True)
if pretty_print:
res = pretty_print_xml(res).strip()
return res
Anyone know what to do without hacking xmltodict??
thanks

Answer 1

I don't much about XML, but I got curious about this question and noticed:
Lists that are specified under a key in a dictionary use the key as a tag for each item.
https://github.com/martinblech/xmltodict#roundtripping
My approach was to reverse engineer the result you're after:
expected = '''
<organisations>
<organisation>org1</organisation>
<organisation>org2</organisation>
<organisation>org2</organisation>
</organisations>
'''
print(json.dumps(xmltodict.parse(expected), indent=4))
output:
{
"organisations": {
"organisation": [
"org1",
"org2",
"org2"
]
}
}
And "round tripping" that, gives the result you're after:
reverse = {
"organisations": {
"organisation": [
"org1",
"org2",
"org2"
]
}
}
print(xmltodict.unparse(reverse, pretty=True))
output:
<?xml version="1.0" encoding="utf-8"?>
<organisations>
<organisation>org1</organisation>
<organisation>org2</organisation>
<organisation>org2</organisation>
</organisations>
HTH!