How to separe these values? - mysql

Question

I've been trying to do this around 2 hours and my brain is about to explode.
I have a table called DEPARTMENTS and a column called TOTAL_ROOMS but each DEPARTAMENT have their own room size but I don't know how to show the total rooms of each department.
It should look something like this
DEPARTMENT NAME || TOTAL DEPARTMENTS || TOTAL DEPARTMENTS WITH ONE ROOM || TOTAL DEPARTMENTS WITH TWO ROOMS || TOTAL DEPARTMENTS WITH THREE ROOMS
EXAMPLE A || 10 || 5 || 3 || 2
EXAMPLE B || 8 || 2 || 4 || 2
I Have tried using a WHERE , IN, DISTINCT function but I'm not very professional doing this (I'm still learning) :/ This is what I've done and the column name about rooms size is TOTAL_ROOMS and I'm trying to SUM every ROOM that has "1 room size" then SUM every ROOM that has "2 room size" and shows the result :/
SELECT TOWER.EDI_NAME_TOWER AS "DEPARTMENT NAME",
COUNT(DEPARTAMENT.NRO_DEPARTAMENT) AS "TOTAL DEPARTMENTS"
FROM DEPARTAMENT
JOIN TOWER
ON DEPARTAMENT.ID_TOWER= TOWER.ID_TOWER
GROUP BY TOWER.EDI_NAME_TOWER;

Answer 1

I am not clear what your data looks like so here's a guess where conditional aggregation (sum(case when...)) is used to separate the columns.
drop table if exists t,t1;
create table t (ID_TOWER int,NRO_DEPARTAMENT int);
create table t1(id_tower int, EDI_NAME_TOWER varchar(3));
insert into t values
(1,1),(1,1),(1,1),(1,1),(1,1),(1,2),(1,2),(1,2),(1,3),(1,3),
(2,1),(2,1),(2,1),(2,1),(2,2),(2,2),(2,3),(2,3),(2,3),(2,3);
insert into t1 values
(1,'aaa'),(2,'bbb');
SELECT TOWER.EDI_NAME_TOWER AS "DEPARTMENT NAME",
count(DEPARTAMENT.NRO_DEPARTAMENT) AS "TOTAL DEPARTMENTS",
sum(case when DEPARTAMENT.NRO_DEPARTAMENT = 1 then 1 else 0 end) '1 room',
sum(case when DEPARTAMENT.NRO_DEPARTAMENT = 2 then 1 else 0 end) '2 room',
sum(case when DEPARTAMENT.NRO_DEPARTAMENT = 3 then 1 else 0 end) '3 room'
FROM t DEPARTAMENT
JOIN t1 TOWER
ON DEPARTAMENT.ID_TOWER= TOWER.ID_TOWER
GROUP BY TOWER.EDI_NAME_TOWER;
+-----------------+-------------------+--------+--------+--------+
| DEPARTMENT NAME | TOTAL DEPARTMENTS | 1 room | 2 room | 3 room |
+-----------------+-------------------+--------+--------+--------+
| aaa | 10 | 5 | 3 | 2 |
| bbb | 10 | 4 | 2 | 4 |
+-----------------+-------------------+--------+--------+--------+
2 rows in set (0.00 sec)
If this is not what your data looks like please add sample data as text to the question. If you have more rooms keep adding aggregations, if that becomes unmanageable consider dynamic sql.

Answer 2

Thanks for the answers and sorry for the delay.
#P.Salmon you gave me an idea but i tried and i even failed… This is what i need to show
IMAGE
this is my code
SELECT EDIFICIO.EDI_NOMBRE_EDIFICIO AS "NOMBRE EDIFICIO",
COUNT(DEPARTAMENTO.NRO_DEPARTAMENTO) AS "TOTAL DEPTOS",
SUM(TOTAL_DORMITORIOS) AS "TOTAL DEPTOS 1 DORMITORIO", -- fix
COUNT(TOTAL_DORMITORIOS) AS "TOTAL DEPTOS 2 DORMITORIO", -- fix
COUNT(TOTAL_DORMITORIOS) AS "TOTAL DEPTOS 3 DORMITORIO", -- fix
COUNT(TOTAL_DORMITORIOS) AS "TOTAL DEPTOS 4 DORMITORIO", -- fix
COUNT(TOTAL_DORMITORIOS) AS "TOTAL DEPTOS 5 DORMITORIO" -- fix
FROM DEPARTAMENTO
JOIN EDIFICIO ON DEPARTAMENTO.ID_EDIFICIO= EDIFICIO.ID_EDIFICIO
GROUP BY EDIFICIO.EDI_NOMBRE_EDIFICIO
ORDER BY EDI_NOMBRE_EDIFICIO;
I'm pretty sure it can be done using SUM ! and i was trying this but i don't know how to sum every value and show the result final per department
SELECT ID_EDIFICIO, NRO_DEPARTAMENTO, TOTAL_DORMITORIOS
FROM DEPARTAMENTO
WHERE TOTAL_DORMITORIOS IN (1,2,3,4,5);
EDIT ---- THANKS P.Salmon i just figured out the code
SUM(CASE WHEN TOTAL_DORMITORIOS = '1' THEN 1 ELSE 0 END) AS "TOTAL DEPTOS 1 DORMITORIO",
This sum every room per department!