I am trying to delete from two mysql tables at once using this function.
public function deleteBusiness($id)
{
$this->db->from("business");
$this->db->join("opening_hours", "business");
$this->db->where("business", $id);
return $this->db->delete(array("business","opening_hours"));
}
It appears to be working correctly, as the correct data is being deleted from both tables, but when I call it with the following...
if($this->businesses_model->deleteBusiness($id)){
$this->session->set_flashdata('flash_message', 'Business Deleted');
} else {
$this->session->set_flashdata('flash_message', 'There was a problem deleting that business');
}
the failed error message is being displayed.
Replace Above code with Following Code let me know if does not work
public function deleteBusiness($id)
{
$this->db->from("business");
$this->db->join("opening_hours", "business");
$this->db->where("business", $id);
$this->db->delete(array("business","opening_hours"));
return $this->db->affected_rows();
}
if($this->businesses_model->deleteBusiness($id) > 0){
$this->session->set_flashdata('flash_message', 'Business Deleted');
} else {
$this->session->set_flashdata('flash_message', 'There was a problem deleting that business');
}
let me know if it does not work
It looks like you are trying to Delete a row from business table and all the rows in the opening_hours related to that business.
Unfortunately your code will not work as CodeIgniter ignores joins when doing Active Record deletes.
Their Documentation does says that you can pass an array to delete method and it will delete from multiple rows
$tables = array('table1', 'table2', 'table3');
$this->db->where('id', '5');
$this->db->delete($tables);
However, please see that it will delete rows from 3 tables where id = 5. Same way in your case it will delete from business and opening_hours where id is say 2. Obviously this is not what you want.
Only option is to use either 2 queries like below or use a Raw SQL query.
$this->db->from("business");
$this->db->where("id", $id);
$this->db->delete('business');
$this->db->from("opening_hours");
$this->db->where("business_id", $id);
$this->db->delete('opening_hours');
Related
I have a database that have two tables 'products' and "specifications". I want to count whose specifications are not in "specifications" table and products have duplicate names.
I have tried: Product::withCount(['specifications'])->has('specifications', '<', '1')->get();
but this is not working, taking too much time also tried with paginate but get no result.
Update 1:
Also please let me know the RAW query for this.
Update 2:
Here is the Product Relation code:
public function specifications()
{
return $this->hasMany('App\Specification');
}
Here is the function I made for deleting duplicate products and there specifications.
public function deleteDuplicateWithCountZero() {
$duplicateProducts = Product::whereIn('name', function ( $query ) {
$query->select('name')->from('products')->groupBy('name')->havingRaw('count(*) > 1');
})->paginate(50);
foreach($duplicateProducts as $duplicateProduct) {
$results = Product::where('name', '=', $duplicateProduct->name)->withCount(['specifications'])->get();
$productCount = count($results);
foreach($results as $result) {
if($result->specifications_count == 0 && $productCount > 1) {
$product = Product::find("$result->id");
Specification::where('product_id', "$product->id")->delete();
$product->delete();
$productCount--;
}
}
}
echo "Complete"; die();
}
Problem: How can I know all products and their specifications are deleted until count query, But count query taking too much time for all data. Please also suggest if I can correct this thing in phpmyadmin with a query.
Since the specification count is always going to be 0, you could hardcode the value in the query. Also, instead of has(), try doesntHave()
Product::query()
->select('*', DB::raw('0 as specifications_count'))
->doesntHave('specifications')
->get();
I have records in a database with three different records in a particular column. I am trying to fetch all the records using Laravel but I am not getting it right after trying with multiple methods and each method is fetching only one record. I would be glad if I get assistance and to also learn from what I am not getting right. Thank you in advance.
Below is the code:
public function setBill()
{
//With the below, I am getting only one record
$FetchData = Students::all();
foreach ($FetchData as $Data) {
dd($Data->class);
}
//With this too, I am getting only one record
$FetchData = Students::get();
foreach ($FetchData as $Data) {
dd($Data->class);
}
//With this as well, I am getting only one record
$FetchData = DB::select('select * from students');
foreach ($FetchData as $Data) {
dd($Data->class);
}
}
What's happening is that dd() is stoping your script execution (dump and die).
If you want to see all fetched records you should do
$FetchData = Students::all();
dd($FetchData);
Otherwise, if you want to dump one record by one
$FetchData = Students::get();
foreach ($FetchData as $Data) {
dump($Data->class);
}
Im using a simple query to pull the users in a table called users.
$users = DB::table('users')->get();
Then using a foreach loop to get the values , for example :
foreach ($users as $user)
{
return $user->email;
}
There is definitely 2 records in the DB Table, but it only returns one line. If i try to query a different table it does the same thing.
If i use the Query Log between the query
DB::enableQueryLog();
$users = DB::table('users')->get();
$result = DB::getQueryLog();
It returns the query and it looks fine
[{"query":"select * from `users`","bindings":[],"time":0.85}]
This table was created within PhpMyAdmin and not using the Artisan Migrate
Of course it so, cause you return from loop, use echo
foreach ($users as $user)
{
echo $user->email;
}
return statement inside the loop will behave like break for your case, this means breaking the loop.
You can use either:
DB::table('users')->select(['email'])->get();
or
DB::table('users')->get(['email']);
But its basics, you can easily find this stuff in docs https://laravel.com/docs/master/
I have some code below which demonstrates a hard-coded example of what I would like to accomplish dynamically.
At a high level, I wish to do something like select * from view_data_$app_state and then get all of the data from that views table into my mustache templates dynamically.
The code I currently must use to group multiple rows of data for a specific column along with the views data is:
<?php
error_reporting(E_ALL);
class Example {
function __construct(){
try {
$this->db = new PDO('mysql:host=localhost;dbname=Example', 'root','drowssap');
}
catch (PDOException $e) {
print($e->getMessage());
die();
}
}
function __destruct(){
$this->db = null;
}
function string_to_array($links_string){
return explode(",", $links_string);
}
function get_view_data(){
$q = $this->db->prepare('select *, GROUP_CONCAT(`links`) as "links" from `view_data_global` ');
$q->execute();
$result = $q->fetchAll(PDO::FETCH_ASSOC);
return $result;
}
}
$Example = new Example();
$result = $Example->get_view_data();
$result[0]["links"] = $Example->string_to_array($result[0]["links"]);
echo json_encode($result);
This gives me the perfect object while
GROUP_CONCAT seems to be doing the trick this way, however I MUST know the column name that will contain multiple rows before writing the query. I am trying to figure out an approach for this and wish to make a custom query + code example that will transform cols with multiple rows of null null and not empty data into an array like above - but return the data.. again like the code above.
Below is an output of the actual data:
[{"id":"1","title":"This is the title test","links":["main","about","store"]}];
How can I replicate this process dynamically on each view table?
Thank you so much SO!
You can use PDOStatement::fetch to retrieve your results, with fetch_style set to PDO::FETCH_ASSOC (some other values will also provide the same information). In this case, the result set will be array indexed by column name. You can access this information with foreach (array_expression as $key => $value)
See the documentation for additional information.
I am trying to figure out why my JOIN is not working on a database query, I have two tables with a user_ID column, but when I return this it returns everything, not just the selected ones per user. What am I messing up any thoughts? Thank you!
function user_apps()
{
$this->db->select('*');
$this->db->from('apps');
$this->db->join('members', 'members.user_ID = apps.user_ID');
$query = $this->db->get();
return $query;
}
Here is an image of the DB tables, and goal is to basically get the urls from the apps table of each user,
http://cl.ly/516bd1e8aae62bd11773
You haven't specified a WHERE clause in your query. At the moment it is returning everything because you only have two users and they both have entries in the 'apps' table.
If you add:
$this->db->where('members.first_name', $first_name);
And pass a first name as a parameter to the function then it will only return results for that user.
function user_apps($first_name)
{
$this->db->select('*');
$this->db->from('apps');
$this->db->join('members', 'members.user_ID = apps.user_ID');
$this->db->where('members.first_name', $first_name);
$query = $this->db->get();
return $query;
}