MySQL Add interger of multiple columns together as result [duplicate] - mysql

I have a table with 3 columns (A,B,C). I want to select some rows from the table and then the MySQL to return a single row having the values added on each column.
A B C
1. 2 2 2
2. 4 4 4
3. 6 7 8
MySQL should return in this case, if I select all the three rows:
A B C
1. 12 13 14

select sum(A),sum(B),sum(C) from mytable where id in (1,2,3);

select
sum(a) as atotal,
sum(b) as btotal,
sum(c) as ctotal
from
yourtable t
where
t.id in (1, 2, 3)

Try this:
select sum(a), sum(b), sum(c)
from your_table

Related

sql-Select rows with same id but different value in another column

Input:
Column A
Column B
1
A
1
B
1
C
2
A
2
B
3
A
3
B
3
c
4
A
5
A
5
B
6
A
Output
ColumnA
4
6.
for columnA for every first of values is A, i need to fetch columnA those values have only A not in B,C
You can use a correlated subquery with NOT EXISTS to exclude column A values that have matching rows with the disallowed values in column B.
SELECT columnA
FROM yourTable AS t1
WHERE columnB = 'A'
AND NOT EXISTS (
SELECT *
FROM yourTable AS t2
WHERE t1.columnA = t2.columnA
AND t2.columnB IN ('B', 'C')
)

MySQL Count distinct values from one column

I have a table having three columns:
A B C
1 2 2
2 2 2
3 1 1
4 1 2
I want the count of those values which have C equal to 2 but with distinct values of B
So in this case for C = 2, count = 2 (B=2 and B=1)
I used the following command:
Select count(*) from mytable where C=2 group by (B)
but it yields:
count(*)
3
I have tried using "distinct" but it can't be use to select from one column
Have you tried
SELECT COUNT(DISTINCT B) FROM mytable WHERE C = 2;
Use sub query like this:
Select count(*) from (
select distinct B where c=2
)

Mysql Query to Merge 3 tables into 1 Table

TO Plot Each Input table I have Separate query, need to apply functionality on that queries and want to create Single query for Output Table
Select Distinct Names, SUM(count) from
(Select Query table 1
union
Select Query table 2
union
Select Query table 3) table group by Names;
this query Not adding count properly Niether Sorting Names properly Whats wrong with this ?
Input Table 1 :-
Names count
bob 3
pol 4
Input Table 2 :-
Names count
bob 5
0 - name may be missing here neglect this entry
Input Table 3 :-
Names count
james 4
pol 7
bob 1
Expected output table :-
Names count
bob 9
pol 11
james 4
You can use UNION and them sum of those.
select sum(a), sum(b) from
(select 2 as a, 1 as b
union select 3 as a, 6 as b
union select 4 as a, 1 as b) as b
Try this query
select `Name`,sum(`Count`) total from ( select `Name`,`Count` from `table1` union all select `Name`,`Count` from `table2` union all select `Name`,`Count` from `table3` ) tot group by `Name`
May this help you.

Insert rows from one table to another but only those rows that have no duplicates

I've seen this, this, this, this and this but my question is different.
I have a Table1:
id c a b rc bid
1 12 4 6 35 4
2 12 4 6 67 7
3 12 4 6 88 8
4 23 4 7 49 3
5 23 5 8 59 8
Table2 also has the same columns but does not have bid column.
A row is considered a duplicate if it has the same values of columns c, a and b. So rows 1, 2 and 3 are considered duplicates because they have 12, 4 and 6.
I want to insert rows of Table1 to Table2, but only those rows that are not duplicates. Which means that rows 1, 2 and 3 won't get inserted to Table2. Only rows 4 and 5 will get inserted because they have no duplicates.
So Table2 will look like this after the inserts:
id c a b rc
1 23 4 7 49
2 23 5 8 59
I know I can get which rows have no duplicates using this query:
select distinct c,a,b,count(*) from Table1 group by c,a,b having count(*) > 1
But am not able to figure out how to insert these to Table2 because the insertion requires specific columns to be specified.
Tried something like this which obviously doesn't work:
insert into Table2 (c, a, b, rc) select distinct c,a,b,count(*) from Table1 group by c,a,b having count(*) > 1
You can use also not in in subselect
INSERT INTO Table2(c, a, b, rc, bid)
SELECT c, a, b, rc, bid
FROM Table1 t1
WHERE (c,a,b) not in ( SELECT c,a,b
FROM Table1 t2
GROUP BY c, a, b
HAVING COUNT(*) > 1
)
You can use NOT EXISTS to exclude duplicate rows:
INSERT INTO Table2(c, a, b, rc, bid)
SELECT
c, a, b, rc, bid
FROM Table1 t1
WHERE NOT EXISTS(
SELECT 1
FROM Table1 t2
WHERE
t2.c = t1.c
AND t2.a = t1.a
AND t2.b = t1.b
HAVING COUNT(*) > 1
)
The HAVING COUNT(*) > 1 will check if there are duplicates.
insert into table2 (c,a,b,rc)
select c,a,b,rc from table1
where id in (select distinct id
from Table1 group by c,a,b having count(*) = 1)
There are many ways to do that. You have already got so many correct answers. Here, I am giving the query based on the way you approached.
INSERT INTO Table2 (c, a, b, rc)
SELECT
c,
a,
b,
rc
FROM
Table1
GROUP BY c, a, b
HAVING count(*) = 1;

MySQL sum elements of a column

I have a table with 3 columns (A,B,C). I want to select some rows from the table and then the MySQL to return a single row having the values added on each column.
A B C
1. 2 2 2
2. 4 4 4
3. 6 7 8
MySQL should return in this case, if I select all the three rows:
A B C
1. 12 13 14
select sum(A),sum(B),sum(C) from mytable where id in (1,2,3);
select
sum(a) as atotal,
sum(b) as btotal,
sum(c) as ctotal
from
yourtable t
where
t.id in (1, 2, 3)
Try this:
select sum(a), sum(b), sum(c)
from your_table