Syntax Error : replacing TYVAR with SEMICOLON CPN Tools - cpn-tools

Syntax Error Image
Syntax Error Image
What is meant by TYVAR here and how can it be resolved such that there is error in parsing it?


To resolve the above problem we use the TILDE ( ` or ~ ) symbol rather than ( ' ) this quotes symbol.

Related

Syntax error or access violation on MySQL geometry data type

I am working with datatype geometry on MySQL. I try to query from the page. I got the error.
How to fix? Could you please help?
Error here:
"An exception occurred while executing '
SELECT t.`road_id`, t.`road_ref_num`, t.`chainage`, t.`road_name`,
ST_AsGeoJSON(ST_Transform(t.`road_wkt`, ?::int)) as geom
FROM gis_ruralroads_t1 t
WHERE (t.road_ref_num LIKE ?)
AND (ST_Transform(ST_SetSRID(ST_MakeBox2D(ST_Point(?, ?),
ST_Point(?, ?)), ?), ST_Srid(t.`road_wkt`)) && t.`road_wkt`
)
with params [32648,
"%0806T1001%", 5579.905, 1088581.723, 1029359.857, 1650396.77,
32648]
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '::int)) as geom FROM gis_ruralroads_t1 t WHERE (t.road_ref_num LIKE '%0806T1001%' at line 1"
Best,
Loy

It is pointing right at ::int. MySQL does not have any syntax like that. Simply remove those 5 characters.
In general, you can trust that an integer will be correctly substituted, even if quotes are added:
ST_Transform(t.`road_wkt`, ?)
turns into this after substitution:
ST_Transform(t.`road_wkt`, '32648')
The apostrophes won't hurt.

MySQL replace QUOTE

I need to replace &quote; in a string. I tried to do this:
SET `title` = REPLACE( `title`, '"', '' )
but it gives me a parsing error.
This is the error:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''&quot)' at line 1
Server version: 5.5.57-cll - MySQL Community Server (GPL)
How do I do this?

Your query should work, but it seems like the error is from another query. Anyhow:
Try this:
UPDATE tbl_name
SET
field_name = REPLACE(field_name,
string_to_find,
string_to_replace)
WHERE
conditions;
Example:
UPDATE bbb_sefurls
SET
metatitle = REPLACE(metatitle,
'&quote;',
'');
No need for a condition

This is simple approach but it replaces all the " in string.
UPDATE dummy_tab SET metatitle =REPLACE(metatitle,'/"','') WHERE metatitle LIKE '%"'

If I'm to read your error 100% as written... you have the word quote spelled wrong some where.
...for the right syntax to use near ''&quot)'
notice in your error it shows no "e" There for your replace statement would also NOT catch this.
Or more closely looking at the image you posted... you are replacing
&quote(semicolon)
with
''
But the error says it is finding the string
&quote)
somewhere in your query... Which would seem to be invalid.
Search your code for
&quot)

MySQL/NODEJS INSERT variable starting with a number

From an API i need to save this variable item.preview_urls.3d_viewer
But why i get invalid syntax with that? I think thats the "3" in the name... thats showing pink color in my sublime text but how can i use that variable from the api?
Thats the REPLACE INTO (INSERT) for my table
REPLACE INTO `item` (item_preview_3D) VALUES ('+ pool.escape(item.preview_urls.3d_viewer) + ')'
Its in Javascript (js)
But i get everytime invalid syntax, cause i think there is a "3" in the variable name
How can i get it run?
I dont have access to the api i call
The error
pool.query('REPLACE INTO `item` (item_preview_3D) VALUES ('+ pool.escape(item.preview_urls.3d_viewer) + ')', function(ee, rr) {});
SyntaxError: Invalid or unexpected token
The code works with other api variables, thats only this 3d_viewer
The sql Table is only item_preview_3D with VARCHAR(255)
I get this error when starting the node! Not when executing the query!

SQL ERROR - Error sql syntax

I am getting an error that I dont know how to deal with.
I am running the same code without issue for another column but for this column it refuses to work.
SELECT * FROM Players WHERE Character = 'momo' // This one wont work
SELECT * FROM Players WHERE Class = 'Fighter' // this one works
Character is a VARCHAR and Class is TEXT. I have tried changing Character to TEXT and I still get the same issue. The value 'momo' exists in the table.
ERROR: Couldn't connect to server. SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= ''' at line 1
Edit:
I am editing this incase someone find this and wants to know how it was fixed. User by the name of ueerdo Pointed out that I should use quotations and when I did, it worked. So I started looking into why it happened and I found out the SQL reserves Character for something else so it is something that I can't use unless it is in quotations.

It is best to delimit identifiers to prevent possible collision with reserved words and keywords.
SELECT * FROM `Players` WHERE `Character` = 'momo'

MySQL Error 1064 - 'Define Function' Syntax

I am barely learning MySQL (moving from SQLite). I am trying to create a custom function within the MySQL command line client, but am hitting errors that I can't correct - and can't find answers to online. My first function began as this:
CREATE FUNCTION myDatabase.LCASE_ASCII_VALUE_AT(
unparsedLine VARCHAR(1024),
linePos int
) RETURNS int DETERMINISTIC
return ASCII( LCASE( RIGHT( CHAR_LENGTH(unparsedLine) - linePos + 1) ) );
I got this error:
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') )' at line 10
Any pointers on where my syntax went wrong? I suspected these, but they didn't fix the problem:
Perhaps MySQL does not like compound statements like return ASCII( LCASE( .... But even after manually unraveling the statement, I still got the same error (but on a line in the newly unraveled statement - I leave out the unraveled statement to save space).
Perhaps the DELIMITER $$ [function definition] END $$ DELIMITER ; business is mandatory - but that didn't fix the error, and MySQL documentation gives an example of a one-line function where DELIMITER is not needed. (the 'hello' function at https://dev.mysql.com/doc/refman/5.0/en/create-procedure.html)
EDIT: Added that I am creating this function within MySQL command line client.

right requires two arguments, the string itself and the number of characters. You've only given the character count.
Try this instead:
return ASCII( LCASE( RIGHT( unparsedLine, CHAR_LENGTH(unparsedLine) - linePos + 1) ) );
Also, you may find that substr is a better option since there's no need to calculate the argument to right in that case, something like:
return ASCII( LCASE( SUBSTR( unparsedLine, linePos, 1 ) ) );