SELECT * FROM `continue_paper`JOIN `questions`
WHERE `questions`.q_id IN
`continue_paper`.cp_qu_id AND `continue_paper`.cp_id=1
in your code you need a set of values for the IN clause in your case you have not so you should use =
SELECT *
FROM continue_paper
JOIN questions ON questions.q_id =continue_paper.cp_qu_id
AND continue_paper.cp_id=1
and you could use a ON clause instead of where
It's usually good practice to use JOIN with comparison operators.
I would join the tables using the foreign/primary keys, then filter it with IN if needed.
Specifically, I would approach it this way:
SELECT * FROM `continue_paper` JOIN `questions`
WHERE `questions`.q_id =
`continue_paper`.cp_qu_id AND `continue_paper`.cp_id=1
Related
SELECT SUM(T.KDV) AS TOTALKDV
FROM (SELECT *
FROM pharmana_urun_db.general_Table, pharmana_Hareket_db.general_Table
WHERE pharmana_urun_db.general_Table.Barkod = pharmana_Hareket_db.general_Table.Barkod AND pharmana_Hareket_db.general_Table.EczaneID = '".$pharmacy_id"') AS T
GROUP BY T.Kategori
1060 - Duplicate column name 'Barkod',
how can I avoid this?
(SELECT *
FROM pharmana_urun_db.general_Table, pharmana_Hareket_db.general_Table
This selects two columns with the same name Barkod
You need to use the explicit join syntax as Jens suggested
Nice explanation here
Learn to use proper JOIN syntax. Don't use subqueries unnecessarily.
You should write this query as:
SELECT SUM(T.KDV) AS TOTALKDV
FROM pharmana_urun_db.general_Table gt1 JOIN
pharmana_Hareket_db.general_Table gt2
USING (Barkod)
WHERE gt2.EczaneID = '".$pharmacy_id"'
GROUP BY Kategori;
You should also learn to use parameters to pass values into SQL queries, rather than munging query strings. I also suspect that you should be including Kategori in the SELECT.
Really trying to figure out, why SQL query doesnt go through. I assume the structure is a bit wrong, but cant figure out where exactly. The references to tables are all correct.
SELECT tap_questionnaires.id,
tap_questionnaires.NAME,
tap_questionnaires.active,
tap_useranswers_ip.questionnaire_id,
Count(tap_useranswers_ip.ip)
FROM tap_questionnaires
LEFT JOIN tap_useranswers_ip
ON tap_questionnaires.id = tap_useranswers_ip.questionnaire_id
WHERE author_email = admin#admin.com
If you use count you need to use group by for the other columns in your select clause.
SELECT TAP_questionnaires.id, TAP_questionnaires.name, TAP_questionnaires.active, TAP_useranswers_ip.questionnaire_id, COUNT(TAP_useranswers_ip.ip) FROM TAP_questionnaires LEFT JOIN TAP_useranswers_ip on TAP_questionnaires.id=TAP_useranswers_ip.questionnaire_id WHERE author_email="admin#admin.com"
group by TAP_questionnaires.id, TAP_questionnaires.active
I think TAP_questionnaires.name it's not necessary because I suppose it depends on TAP_questionnaires.id. TAP_useranswers_ip.questionnaire_id is the same value as TAP_questionnaires.id
Hope that helps!
I think this version is clearer:
SELECT q.id, q.name, q.active, COUNT(a.ip)
FROM TAP_questionnaires q LEFT JOIN
TAP_useranswers_ip a
ON on q.id = a.questionnaire_id
WHERE author_email = 'admin#admin.com'
GROUP BY q.id, q.name, q.active;
Notes:
You need a GROUP BY.
You need single quotes around the string constant.
Table aliases make the query easier to write and to read.
There is no reason to include a.questionnaire_id. You already have q.id.
I have a SQL query that i would like to write with Magento's collection methods but i don't know how to.
I know that i have to use the getSelect() and joinLeft() methods, but don't know how to put a select inside a left join.
The query is :
SELECT
p.photo_id,
p.photo_name,
s.step_id,
s.step_name
FROM Photo p
LEFT JOIN (
SELECT
photo_id, MAX(step_id) AS max_step_id
FROM photoStep
GROUP BY photo_id
) ps
ON ps.photo_id = p.photo_id
LEFT JOIN Steps s
ON s.step_id = ps.max_step_id
I think that your best option here would be to try to avoid using the subquery. So I would start by reworking the SQL query and then use the functions groupByField & addExpressionFieldToSelect.
->groupByField('photo_id')
->addExpressionFieldToSelect("max_step_id", 'MAX({{step_id}})', 'step_id')
I have a query which looks like this
$db->query("SELECT A.page_id, A.page_name FROM user_likes_pages as A , user_likes as B WHERE A.page_id = B.page_id AND B.country_id = ".$user_reg." ");
The thing is, I want to select a column from user_likes. Do I have to make a join or I can do it in different way. Thank you.
You have a join in your query, but it is implicit. You should write the query as:
SELECT ulp.page_id, ulp.page_name, ul.<whatever>
FROM user_likes ul JOIN
user_likes_pages ulp
ON ul.page_id = ulp.page_id
WHERE ul.country_id = ".$user_reg."
In addition to adding the explicit join syntax, I also changed the table aliases so they are abbreviations of the table name. This makes it easier to read the query and avoid mistakes.
You select B.columnname. You don't need a join, because you have the A.page_id = B.page_id.
I'm trying to use the following query, and if it only has one having statement it works as expected. If I add the second having statement it does not work.
SELECT candidate.first_name,
candidate.last_name,
qualification.code,
property.value AS funding_band_value,
qualification.funding_band,
property.value AS qualification_level_value,
qualification.qualification_level_id
FROM candidate_qualification, candidate, qualification, property
WHERE candidate_qualification.candidate_id=candidate.id and
candidate_qualification.qualification_id=qualification.id
HAVING funding_band_value = (select property.value from property where qualification.funding_band=property.id) and
HAVING qualification_level_value = (select property.value from property where qualification.qualification_level_id=property.id)
Could someone explain why this doesn't work and how I should do this.
HAVING acts similarly to WHERE or GROUP BY. You reference it once to start using it and combine multiple statements with AND or OR operators. An in depth look at the query parser might give you a more explicit answer.
You don't need HAVING here, just use AND so it is part of your WHERE clause.
The subqueries are not necessary, those tables are already joined.
Something like this should be closer to what you want:
SELECT c.first_name,
c.last_name,
q.code,
p.value AS funding_band_value,
q.funding_band,
p.value AS qualification_level_value,
q.qualification_level_id
FROM candidate_qualification cq
INNER JOIN candidate c ON cq.candidate_id=c.id
INNER JOIN qualification q ON cq.qualification_id=q.id
INNER JOIN property p ON q.funding_band=p.id
and q.qualification_level_id=p.id