How to update columns in a table for specific rows? - mysql

Question

I want to update my columns for rows specified by WHERE command, but I want to update my field in a way that it extracts number part of the string from each specified field, multiplies that with a number (that I will specify) and give number output in all those specific fields extracted by WHERE command in that column.
For example, assume I want to update all my fields in a column which are like (5.6 AUD/1000, 4.5 AUD/1000, 9.7 AUD/1000), so I want to first identify fields ending with /1000 and update only those fields in the column by multiplying the number part of the string (which is 5.6, 4.5, 9.7) with any number (let's say 10). I want that other fields on the column remains unchanged.
SELECT * from sorted WHERE Column8 REGEXP '/1000$';
gives me all the specific fields that I wish to update. But I want to update them in the way I specified above, which is that I want to extract number part from the string and multiply that with a number and update those fields only.
I am able to extract all the fields with the condition I mentioned, I'm facing difficulty in update these fields in the column.
SELECT * from sorted WHERE Column8 REGEXP '/1000$';
SELECT CAST(Column8 AS UNSIGNED)*10 FROM sorted
wHERE
column8 REGEXP '/1000$';
The above code gives me required updated fields, but I want them reflected in my column.
I expect my output to be a column where only those fields ending with '/1000' should get updated in a way that the number part of the string is multiplied with 10.

Answer 1

I have casted the varchar field named string to decimal type and multiplied with static value 10 . I have checked in sql server.
DECLARE #temp TABLE
(
string NVARCHAR(50)
)
INSERT INTO #temp (string)
VALUES
('5.6 AUD/1000'),
('4.5 AUD/1000'),
('9.7 AUD/1000')
select cast(left(string, patindex('%[^0-9./]%', string) - 1) As decimal(18,2))* 10
from #temp