Hibernate Native Query fails but SQL Query works - mysql

Question

I have this query using hibernate:
#Query(value = "BEGIN SET #rank = 1; CREATE TEMPORARY TABLE IF NOT EXISTS results "
+ "SELECT User.userId, User.username, #rank FROM User WHERE User.username = :searchString ;"
+ "SET #rank = 2; INSERT INTO results (SELECT User.userId, User.username, #rank FROM Following "
+ "JOIN User ON Following.followsId = User.userId " + "JOIN UserProfile ON UserProfile.userProfileId = User.userProfileId "
+ "WHERE Following.userId = :userId AND User.username LIKE :searchString "
+ "ORDER BY UserProfile.followsCount DESC); "
+ "SET #rank = 3; INSERT INTO results (SELECT User.userId, User.username, #rank FROM User "
+ "JOIN UserProfile ON UserProfile.userProfileId = User.userProfileId "
+ "WHERE User.username LIKE :searchString ORDER BY UserProfile.followsCount DESC); "
+ "SELECT User.* FROM results JOIN User ON User.userId = results.userId ORDER BY #rank DESC LIMIT 50; "
+ "DROP TEMPORARY TABLE results; END;", nativeQuery = true)
List<User> findLike(#Param("searchString") String searchString, #Param("userId") Long userId);
When I run it, i'm told that it could not extract the result set (by JUNIT) and in the console
16:32:24.554 [main] ERROR o.h.e.jdbc.spi.SqlExceptionHelper - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SET #rank = 1; CREATE TEMPORARY TABLE IF NOT EXISTS results SELECT User.userId, ' at line 1
I turned hibernate.show_sql=true and even ran the query that was logged to the console using mysqlworkbench and it works.
Note that this query is running in a interface that is defined as such:
public interface IUserJpaDao extends JpaRepository<User, Long>, JpaSpecificationExecutor<User>
Any ideas why it works in MySqlWorkbench and not in hibernate?