I assume it's possible, cause there is 'foo'.var and it expands to $foo = 'var';, so there has to be some way.
What i'm trying to do is to create a template that does the following:
FooBar.new -> $fooBar = new FooBar();.
The best what I had by far is:
$$$EXPR$ = new $EXPR$();, which behaves like this:
FooBar.new -> $FooBar = new FooBar();.
It's almost what I want, but the variable name is capitalized. I've tried with suggestVariableName taken from Template Macros, but I guess it only works inside live templates or I don't know how to use it for postfix completion.
UPDATE
I've found a really cool plugin, which does what I need. Kudos to the author!
Related
I'm trying to add some lua functionality to my existing conky setup so that repetitive "code" in my conky text can be cleaned up. For example, I have information for each mounted FS, each core, etc. where each row displayed in my panel differs ONLY by one parameter.
My first skeletal, attempt at using lua functions for this seems to run but displays nothing in my panel. I've only found very simple examples to base this on, so I may have made a simple error, but I don't even know how to diagnose it. My code here is modeled after what I HAVE been able to find regarding writing functions, such as this How to implement a basic Lua function in Conky? , but that's about all the depth I've found on the topic except for drawing and cairo examples.
Here's the code added to my conky config, as well as the contents of my functions.lua file
conky.config = {
...
lua_load = '/home/conky-manager/MyConky/functions.lua',
};
conky.text = [[
...
${voffset 5}${lua conky_test 'test'}
...
]]
file - functions.lua
function conky_test(parm1)
return 'result text'
end
What I would expect is to see is "result text" displayed in my panel at the location where that function call appears, but nothing shows.
Is there a log created by conky as it runs, or a way to provide some debug output? Even if I'd made a simple error here, I'd still like to have the ability to diagnose things as my code gets more complex.
Success!
After cobbling info from several articles together, I figured out my basic flaws -
1. Missing a 'conky_main' function,
2. Missing a 'lua_draw_hook_post' to invoke it, and
3. Realizing that if I invoke conky from a terminal, print statements in lua would appear there.
So, for anyone who sees this question and has the same issues, here's the corrected code.
conky.config = {
...
lua_load = '/home/conky-manager/MyConky/functions.lua',
lua_draw_hook_post = "main",
};
conky.text = [[
...
${lua conky_test 'test'}
...
]]
and the proper basics in my functions.lua file
function conky_test(parm1)
return 'result text'
end
function conky_main()
if conky_window == nil then
return
end
end
A few notes:
I still haven't determined if using 'lua_draw_hook_pre' instead of 'lua_draw_hook_post' makes any difference, but it doesn't seem to in this example.
Also, some examples showed actually calling this 'test' function instead of writing a 'main', but the 'main' seemed to have value in checking to see if conky_window existed.
Some examples seemed to state that naming functions with the prefix 'conky_' was required, but then showed examples of calling those functions without the prefix, so I assume the prefix is inferred during the call.
a major note: you should run conky from the directory containing the lua scripts.
In my code I use Registry pattern like that:
$data = Registry::get('classA')->methodOfClassA($param1, param2);
Registry class stores instances of some classes in internal array, so in any place of my code I can call class methods for handy functions like in line above.
But, the problem is that PHP-storm does not autocomplete when I type:
Registry::get('classA')->
And, that is worse, it does not go to declaration of the method "methodOfClassA" when I hover mouse cursor holding mac-button (analogue of control-button on windows)
I suppose, that IDE AI is not so good to recognise cases like that, but maybe there is some tricks to do that in a hard way? hardcoding classes+method names in some file and so on...
At least, I want it to understand to go to method declaration when I click method name...
Any advices?
http://confluence.jetbrains.com/display/PhpStorm/PhpStorm+Advanced+Metadata
This link describes it all -- it is already used by multiple projects/frameworks/code-generation helpers, like Magento, for example (some other can be found mentioned in the comments of the actual ticket).
For other situations you may want to check out DynamicReturnTypePlugin plugin (Settings | Plugins | Browse repositories...) -- have not tried myself and therefore cannot comment how good/fast/laggy it is.
You can always indicate the variable type in two steps:
/** #var $foo MyClass */
$foo = $this->get('MyClass');
$foo->bar(); // autocomplete works
I am trying to call a perl script from my HTML page. The way am trying to do is to call the url of the perl script located on the server.
Here is the piece of code:
HTML:
var fname = "Bob";
var url='http://xxx.com:30000/cgi-bin/abc.pl?title=fname';
window.open(url,"_self");
The way am trying to retrieve it in perl as:
Perl:
print "$ARGV[0]\n";
Now, I have 3 questions:
I think this is the correct way to pass the variables but am not able to print the argument in perl.
If i want to pass another variable lname, how do i append it to the url?
My window.open should open the output in the same window, since it uses the parameter _self. Still it doesn't.
Could anybody point out the problems?
Thanks,
Buzz
No #ARGV contains command line arguments and will be empty.
You need the CGI module
use warnings;
use strict;
use CGI;
my $query = CGI->new;
print $query->param( 'title' );
Edit:
Take a look at dan1111's answer on how to generate HTML and display it in the browser.
In addition to what Matteo said, a simple print statement is not enough to send some output to the browser.
Please see a recent answer I wrote giving a sample CGI script with output.
In regard to your other issues:
Variables are appended to a url separated with &:
var url='http://xxx.com:30000/cgi-bin/abc.pl?title=fname&description=blah';
Based on this question, perhaps you should try window.location.href = url; instead (though that doesn't explain why your code isn't working).
There are two different environments that each pass variables two different ways. The command line can pass variables through the #ARGV and the browser can pass variables through #ENV. It doesn't matter what language you use, those are the arrays that you will have to employ.
Given the fantastic coding guidance PhpStorm offers I am a bit confused regarding the lack of variable name suggestions for variables used in strings.
$variable = "something";
// A:
$variable;
// B:
$str = "$variable";
// C:
$str = "{$variable}";
In case A PhpStorm suggests variables, not in cases B and C though.
As this is a very straightforward feature and Eclipse offers it too, I guess I have to adjust my configuration.
Any ideas?
Works fine in both cases (verified in 2.1.4), however automatic completion is not enabled in order not to distract you from the actual string editing and you have to press Ctrl+Space to invoke code completion:
Clearly I have some mixed up, but I figured that by using something like this in "main.lua":
local module = require("module")
local var = "I should be global?"
printthis()
with module.lua containing something like:
function printthis()
print(var)
end
that printthis(var) would work fine, because now the module.lua code is inside main.lua, no? Instead, printthis has no idea what var is. I read it's good practice to use "local" on Lua variables when possible, but in this case, do I have to make var global or is there a way for module.lua's printthis() function to read var properly?
No. That's not at all how it works.
The Lua interpreter provides one global table, referred to as _G normally, unless you're doing something kinky.
function printthis()
print(var)
end
This translates to, in reality
_G.printthis = function()
_G.print(_G.var);
end
And your code in main is equal to
local module = _G.require("module")
local var = "I should be global?"
_G.printthis()
But when you call printthis- where did _G.var get set? Nowhere. So the variable is nil, like all other accesses to a table where there is nothing at that key.
It might be inconvenient, but it's a much better idea in the long run to pass arguments than to set global variables instead. Once you come to change anything about the program, it's going to be completely impossible to make any changes, as the logic has no structure and you have no idea what happens where without reading every single line of code and understanding it at once. In addition, you can only use each key in one place, because it's a global table- so I sure hope nobody else wanted to use "var" as a variable name and you don't mind your code silently failing because you got a global name wrong.
The other two answers gloss over an important thing: lexical scoping.
This means, roughly, that code can access local variables that are defined where the code is defined. That probably sounds vague, so I'll give an example:
local cheese = 'sandwich'
print(cheese) -- prints sandwich
do -- this begins an anonymous block
local cheese = 22
print(cheese) -- prints 22
end
print(cheese) -- prints sandwich
So what we have here is two different variables: the outer one is "shadowed" by the inner one.
Now, onto functions:
do
local hotdog = 'hot'
function nonsense()
print(hotdog)
end
end
print(hotdog) -- prints nil, since there is no variable called hotdog here
nonsense() -- prints hot
Functions can see the local variables from where they are defined, not from where they are called. This is very important and very useful, once you get the hang of it.
I'm no expert in lua, but shouldn't var be passed as variable. Something like this:
function printthis(var)
print(var)
end
You're missing your var in function header. And you're passing your var in main.lua as an argument to printthis() function.