I have two React Components, Open and Save. The Save component contains an saveButton. The Open component contains an openButton, along with a stopButton and executeButton that shows up depending on the state of the component. I want my Open and Save components to be lined up next to each other, on the same row:
<div style={{display:'flex', flexDirection:'row}}>
<Save></Save>
<Open></Open>
</div>
The initial state looks like this:
The state where all four buttons show look like this:
Remember that Execute and Stop are part of the same Open component that contains the Open button. How can I align the components so that the Save/Open buttons are aligned all the way to the left, and the Execute/Stop buttons are aligned all the way to the right?
For clarification, I want the buttons formatted like this:
Save Open ------------all whitespace here--------------- Execute Stop
Edit: Here is the (very simplified) code for the components
// Save
<Button>Save</Button>
//Open
this.state = { executeFlag: false, stopFlag: false}
render(){
let stop;
let execute;
if(this.state.stopFlag) stopButton = <Button>Stop</Button>;
if(this.state.executeFlag) executeButton = <Button>Execute</Button>;
return(
<div>
<Button>Open</Button>{execute}{stop}
</div>
);
}
In your css maybe you could try setting the width of the buttons to 50% each and margin to zero. I believe flex will display on the same row as long as they can fit.
There are a few ways to do that... It really depends on the structure of your component and not just the control buttons. Here is a sample structure I usually use for something similar in plain HTML CSS for your reference
.container {
display: flex;
}
.component-b {
flex-grow: 1;
display: flex;
justify-content: space-between;
}
.sub-menu{
display: flex;
justofy-content: flex-end;
}
.button {
background: #1E88E5;
padding: 0.5rem 1rem;
margin: 0.5rem;
}
<div class="container">
<div class="component-a button">
Save
</div>
<div class="component-b">
<div class="button">
Open
</div>
<div class="sub-menu">
<div class="button">
Execute
</div>
<div class="button">
Stop
</div>
</div>
</div>
</div>
One way of achieving this is by wrapping two components set in one div and then wrapping all in div and using flex properties
<div style={{
display:'flex'
justifyContent:'space-between',
aligItems:'center'
}}
>
<div style={{display:'flex', flexDirection:'row',justifyConetent:'space-around'}}>
<Save></Save>
<Open></Open>
</div>
<div style={{display:'flex', flexDirection:'row',justifyConetent:'space-around'}}>
<Execute></Execute>
<Stop></Stop>
</div>
</div>
Related
I'm trying to create a Navigation field for my website, and I would like my buttons to be underneath each other with a white line in between. I have managed to get this part working by adding two line breaks next to the button, as seen here:
<button id = "next" onclick="next()">
Volgende
</button><br><br>
I'm wondering if it's possible to have them show up like this, but if I hide the button, have the other buttons jump up, so they fill the gap and jump back down when the button becomes visible again.
Thanks in advance!
Don't use line breaks for layout. That's a misuse of their purpose, which is to break text.
Just put your buttons in block-level (or inline-block level) containers, like divs. Obviously you'd hide and show the containers, not the buttons.
.button-container:not(:first-child) {
border-top: 1px solid red;
padding-top: 4px;
margin-top: 4px;
}
<div id="next-btn-container" class="button-container">
<button id="next" onclick="next()">Volgende</button>
</div>
<div id="other-btn-container" class="button-container">
<button id="other" onclick="next()">Volgende</button>
</div>
<div id="another-btn-container" class="button-container">
<button id="another" onclick="next()">Volgende</button>
</div>
<br> is not a good practice for cross-browser perspective, kindly use the standard way by using margin and display:block property of css.
So your html will be like:
<button class="mb-20px d-block" id = "next" onclick="next()">
Volgende
</button>
And add below line in your css
.mb-20px { margin-bottom: 20px; }
.d-block { display: block; }
I have found how to make it work.
Instead of using
document.getElementById("button").style.visibility = 'hidden'
I have now used
document.getElementById("button").style.display = 'none'
This makes the buttons fill the gaps when they're hidden.
I am in the process of making my own website, and I am making it out of pure HTML. I encountered in the making of the page, as I will describe below.
Here's my code for reference :-
<head>
<style>
img {
display: block;
margin-left: auto;
margin-right: auto;
}
</style>
<style>
.sideDiv {
border: 1px outset black;
background-color: white;
text-align: center;
width: 120;
height: 400;
}
</style>
<style>
.mainDiv {
border: 1px outset black;
background-color: white;
text-align: left;
width: 400;
height: 300;
}
</style>
<img src="AyushLogo.png" alt="logo" height="9.2%" width="9.2%" style="float:left">
<br>
<a><button>About Me</button></a>
<a><button>Games</button></a>
<a><button>My Blog</button></a> <br><br>
<hr>
</head>
<body>
<div class="sideDiv">
</div>
<div class="mainDiv">
<p>Hi,<br>My name is Ayush Bhatt.<br><br>I love to code and remake old games. You can view some of my games by clicking on the 'Games' button on the top bar.</p>
</div>
</body>
</html>
The output looks like this :-
I wanted the tag with the "mainDiv" properties to appear at the side of the one with the "sideDiv" properties, but it just doesn't want to.
PS : I want to use only HTML as long as possible
An important thing about <div> tags is that they are known as "block-level" elements, which in particular means that they always start on a new line and take up the full width available, regardless. With this in mind,
writing
<div class="sideDiv"></div>
<div class="mainDiv">
...
</div>
should result in a div with class sideDiv and width as defined in the class, and then a new div with class mainDiv started on a new line, as block-level elements do by default, though note that this is simultaneously also because the div with class sideDiv takes up the remaining width on the page as a block-level element (though its content width is as described in the class, it being a block-level element is a bit like it "reserving" the rest of the width even though its content only uses the amount defined), so the next element (block level or inline) can only start on at least the next line.
If you want to circumvent this behavior, there are many ways to do it. One is by using an external tool like bootstrap, as pointed out by another answer, but my favorite is to simply use flex box. This can be done for your code in this way
<div style="display: flex; flex-direction: row;">
<div class="sideDiv"></div>
<div class="mainDiv">
...
</div>
</div>
A method that directly overwrites the block-level property would be to set the style display: inline-block; for both divs, to prevent either from starting on a new line or taking up the whole available width by default. (Just one isn't enough, if you only set it on the first one, the second still starts on a new line by default, and if you only set it for the second one, the first still takes up all available width by default). However, this causes the element to be treated completely as an inline element besides the fact that block-level height and width can be applied, and can be strange/difficult to maneuver as a result. It is often easier to just use a flex box. Code for this would be
<div class="sideDiv" style="display: inline-block;"></div>
<div class="mainDiv" style="display: inline-block;">
...
</div>
However, note that <p> is also a block-level element, so directly substituting in your original code in the mainDiv div would still cause it to skip a line before displaying. Again, it is usually easier, more modern, and better looking to just use a flex box.
Edit: Added the detail about block-level elements taking up all available width, and fixed the incorrect initial method that changed the display property to overwrite the block-level property by setting display: inline;. This can work, but it will ignore the heights and widths of the <div>s.
try using bootstrap , it deals with layout perfectly , here is an example :
<div class="container">
<div class="row">
<div class="col-md-6">
this is the left section
</div>
<div class="col-md-6">
this is the right section
</div>
</div>
</div>
for more details check :
https://getbootstrap.com/docs/5.0/layout/grid/
NOTE : you will need to include bootstrap and jQuery libs , check for online tutorial to start using bootstrap
I'm working in a project where we have implemented ng-bootstrap and I'm now working on the toast-component and to it more suitible for our company.
What I'm trying to achive right now is to make a button inside of the toast to be on the far right while the text will be on the left. Right now the button comes directly after the text, which leaves a lot of space to the right of the button.
In the documentation (https://ng-bootstrap.github.io/#/components/toast/overview) they say:
We provide a dedicated ngb-toasts CSS class you could use, or write your own styles in case some specificities would be needed.
However per my understanding is that it only styles the toast it self and not the things inside of it, which is what I want to do.
I'm trying to achive this by adding in flexbox
SCSS
.toast {
display: flex;
flex-direction: row;
justify-content: space-between;
.text,
button {
align-self: center;
}
}
HTML
<ngb-toast *ngFor="let toast of toastService.toasts" [class]="toast.classname" class="toast">
<ng-template [ngIf]="isTemplate(toast)" [ngIfElse]="text" class="text">
<ng-template [ngTemplateOutlet]="toast.textOrTpl"></ng-template>
</ng-template>
<ng-template #text class="text">
<span>
{{ toast.textOrTpl }}
</span>
</ng-template>
<button class="btn ml-2" [class]="toast.classname" (click)="toastService.remove(toast)">
{{toast.button}}
</button>
</ngb-toast>
When I build the application and runs it, I can see in the browsers devtool that ng-bootstrap has added a new div with class="toast-body".
First question I have is why does it get added and for what reason?
This new div then contains my text and my button, which means that the they aren't affected by my flexbox that I added in the (now parentclass to toast-body).
I tried to address this issue in a simple way by adding in the newly created div in my style.css as well.
SCSS
.toast {
& >.toast-body {
display: flex;
flex-direction: row;
justify-content: space-between;
.text,
button {
align-self: center;
}
}
}
Sadly this approach doesn't work, the styles aren't hitting <div class="toast-body">.
What do I need to change / do in order to get the result I want?
How can I make sure that my styles trigger <div class="toast-body"> and the content inside of the div?
I want to hide an anonymous-child div which has a child-div also. I want also to display the anonymous div by clicking on div#child2.
I don't have any authority to change/add/remove ids or classes.
So I did this:
<div id="parent">
<!-- the anonymous div which I want to hide and display by clicking on div#child-2 -->
<div>
<div id="Container1" >
<div id="Container1">
<object>.....</object>
</div>
</div>
</div>
<div onclick="appear()" id="child-2">
<div id="child-of-child"></div>
</div>
</div>
CSS
div#parent div:first-child {
display: none;
}
Javascript
<script type="text/javascript">
function appear() {
document.getElementById("Container1").document.display="block !important";
}
</script>
The problem is that this type of css has affected the div#child-of-child and div#Container1 because the css reffering to every first child of any div.
So, my first question is:
How can I hide the anonymous div without having any effect to another div and display that later by clicking on div#child-2.
Second:
In this type of javascript code the styling of "block !important" works as it is?
Third:
The div#child2 doesn't have any content by itself. It includes another div which has content. If I set on div#child2 an event like onclick="appear()"; it works?
Forth:
In case that there is no way to avoid any effect to other divs is there any way to display the anonymous div and div#Container1?
Try this to only hide the first child within the #parent div:
div#parent div:first-child div:first-child {
display: none;
}
EDIT
To make Container1 appear afterwards, do the following in js (notice: I removed `!important' as I don't believe that is allowed, removing it made the code work - you can try it out below through the Fiddle link):
function appear() {
document.getElementById("Container1").style.display="block";
}
FIDDLER
I am trying to create a bootstrap accordion for my app. I also have background color in its parent element. My problem is that when I expand my accordions, it extends the height of my page and the background color doesn't cover the extended area.
my html
<div id='wrapper>
<accordion id='accordion' close-others="false">
<accordion-group>
<accordion-heading >
<h2 class='title'>Title 1</h2>
</accordion-heading>
<div id="first" class="panel-collapse collapse in">
//contents...
</div>
</accordion-group>
//I have 5 to 6 accordion group.
</accordion>
</div>
CSS:
//I used height:100% and it looks fine when the page first loaded but not after //user //expand all the accordion.
#wrapper{
background-color: red;
height: 100%;
display: block;
}
Can anyone help me about it? Thanks a lot!
Looking through the documentation I noticed you could catch the event shown.bs.collapse which
is fired when a collapse element has been made visible to the user
(will wait for CSS transitions to complete).
So you could try something like:
$('#myCollapsible').on('shown.bs.collapse', function () {
document.getElementById('wrapper').style.backgroundColor="red";
})
Edit: if that does not work try show.bs.collapse