Integers are marked as dirty attributes no matter what - yii2

I need to check if a model has been updated and what attributes have changed when saving.
I'm using dirtyAttributes and filter intval as the docs suggests.
The values are coming from an API and are type-cast as they come in, so in theory the filter is redundant.
Model rules
public function rules()
{
return [
[['contract_date', 'order_date'], 'integer'],
[['contract_date', 'order_date'], 'filter', 'filter' => 'intval'],
];
}
This is some of the code currently running:
// Add the changed status variables to the job log
$dirty_attributes = array_keys($model->dirtyAttributes);
if($model->save()) foreach ($dirty_attributes as $attribute)
{
$data[$attribute] = $model->getOldAttribute($attribute).' ('.gettype($model->getOldAttribute($attribute)).')'. ' => '. $model->$attribute.' ('.gettype($model->$attribute).')';
}
var_dump($data);
This produces:
["contract_date"]=>
string(44) "1559669638 (integer) => 1559669638 (integer)"
["order_date"]=>
string(44) "1559669638 (integer) => 1559669638 (integer)"
There is probably something obvious I'm missing, but I can understand what.

After saving model all "oldAttributes" are updated to store new values so comparing them like you do makes no sense. If you want to check which attributes have been changed after saving you can override afterSave() method in your model like:
public function afterSave($insert, $changedAttributes)
{
// $changedAttributes -> this is it
parent::afterSave(); // call parent to trigger event
}
or listen for ActiveRecord::EVENT_AFTER_INSERT / ActiveRecord::EVENT_AFTER_UPDATE event where this data is also passed.

Related

Accessing to the `latest` record stored in DB table right after recording it

In Laravel After recording last row to a DB table, can I safely access same recorded data right after recording it by calling latest() queries? Because transactions by other users may occur at the same time, and it may not really be the last record anymore?
Edit:
For example:
Public function StoreNotif($data){
auth()->user()->Notif()->create(store $data here..)
}
Public function SendNotif(){
$data="123";
$this->StoreNotif($data)
event(new Notification(stored Notif instance?));
}
No, you cannot rely on the database to return the record from your current script.
The ->latest() method will always sort the records with the most recent created_at date first.
https://laravel.com/docs/6.x/queries#ordering-grouping-limit-and-offset
But you haven't provided any code or explanation as to why this is a concern. If you just created a new record, why do you need to query it again? You should already have access to an instance of the model.
EDIT: I've made a few edits to demonstrate how you would pass the model from a controller to an event as referenced in the comments. Please post your code if you want more specific help.
SomeController.php
function store()
{
$model = Model::create([
'some_data' => 1
]);
// fire an event with the newly created model
event(new SomeEvent($model));
dd($model);
}
------------------------
Model {
// ...
attributes: [
'id' => 101,
'some_data' => 1
'created_at' => '2019-10-06 12:48:01',
'updated_at' => '2019-10-06 12:48:01',
]
// ...
}
SomeEvent.php
<?php
namespace App\Events;
use App\Model;
use Illuminate\Queue\SerializesModels;
class SomeEvent
{
use SerializesModels;
public $model;
public function __construct(Model $model)
{
$this->model = $model;
// ...
}
}
EDIT: Per your newly added code, you just need to pass the new model back to the original method. You could do something like this.
Public function StoreNotif($data)
{
// add a return statement
return auth()->user()->Notif()->create(store $data here..);
}
Public function SendNotif()
{
$data="123";
// store the returned data to a variable
$model = $this->StoreNotif($data);
// call the event with the model instance
event(new Notification(model));
}
I'm not sure what 'latest' is but I do know that MySQL uses SELECT LAST_INSERT_ID as the query to get the 'per-connection' id of the last inserted item. Under the covers it's using mysql_insert_id so if you are in a language that supports it, you could use that too.

Yii2: Non-Scenario fields are not saved

I'm using different scenario for validation purpose.
The field email is not required in a scenario but if i pass email, it is not getting saved in DB.
Rules in Model:
[['firstname','email'], 'string', 'max' => 256],
Scenario function
public function scenarios() {
$scenarios = parent::scenarios();
$scenarios['insert2'] = ['firstname', 'status'];
return $scenarios;
}
In controller:
$model = new User();
$model->scenario = "insert2";
$model->load($data);
print_r($model);
Print_r returns email with empty
From Yii 2 load() docs:
Note, that the data being populated is subject to the safety check by setAttributes().
Now, setAttributes() signature:
public void setAttributes ( $values, $safeOnly = true )
where $safeOnly set to true means the assignments should only be done to the safe attributes. A safe attribute is one that is associated with a validation rule in the current $scenario.
So email must be included in the scenario.
In Yii2, when you want the rule to be applied on certain scenarios, you can specify the on property of a rule, like the following
public function rules()
{
return [
//rule applied only in scenario 'insert2'
[['first_name','status'], 'required','on' => 'insert2'],
//rule applied in all scenarios
['email','safe'],
//rule applied only in scenario 'insert3'
[['first_name','status','email'], 'required','on' => 'insert3'],
];
}
Now if you specify $model->scenario = "insert2" in controller then first_name and status are required and email if you give any value will get saved because ['email','safe'] rule also applied here.
If you specify $model->scenario = "insert3" in controller then first_name,status and email are now required fields and rule ['email','safe'] also get applied.
Please note you may not use public function scenarios() {.. here
From http://www.yiiframework.com/doc-2.0/guide-structure-models.html#validation-rules

Ignore validation on soft deleted models

I have user table. I created a form with 3 fields:
Username
phonenumber
status
The first two fields are unique. Model rules for those fields look like this:
[['Username', 'phonenumber'], 'required'],
[['Username', 'phonenumber'], 'unique'],
I use soft deletion, so when record is deleted, it actually stays in database but status value will change to 0.
The problem is, if I add a record with existing username it shows an error message like "already added". I need to ignore validation if username have a status with value 0.
Use filter property of UniqueValidator
public function rules()
{
return [
...
['username', 'unique', 'filter' => ['<>', 'status', 0]];
...
];
}
It's better to declare constant instead of 0 (something like const STATUS_DELETED = 0) and user it as self::STATUS_DELETED inside of User class. Also you can use != instead of <>.
The last recommendation will be to use username instead of Username to follow convention of naming database table columns.
Read more about ways of declaring filter in official docs.
The ways of setting filter condition as array is described here.
You can use your own function to decide the given username already exists in active status or not. Use this function in "when" property of your unique validation rule.
Have a look :
public function rules()
{
$check = function($model) {
$existActiveUser = User::model()->findByAttributes(array("username"=>$model->username,"status"=>1));
if($existActiveUser)
return true;
else
return false;
};
return [
['Username', 'phonenumber'], 'required'],
[['Username','phonenumber'],'unique','when'=>$check],
}

Preventing malicious users update data at add action

Here is a basic add action:
public function add()
{
$article = $this->Articles->newEntity();
if ($this->request->is('post')) {
$article = $this->Articles->patchEntity($article, $this->request->data);
if ($this->Articles->save($article)) {
$this->Flash->success('Success.');
return $this->redirect(['action' => 'index']);
} else {
$this->Flash->error('Fail.');
}
}
$this->set(compact('article'));
}
If a malicious user injects at form a field with name id and set the value of this field to 2. Since the user do that the id value will be in $this->request->data so at $this->Articles->patchEntity($article, $this->request->data) this id will be patched and at $this->Articles->save($article) the record 2 will be updated instead of create a new record??
Depends.
Entity::$_accessible
If you baked your models, then this shouldn't happen, as the primary key field will not be included in the entities _accessible property, which defines the fields that can be mass assigned when creating/patching entities. (this behavior changed lately)
If you baked your models, then this shouldn't happen, as the primary key field(s) will be set to be non-assignable in the entities _accessible property, which means that these the fields cannot be set via mass assignment when creating/patching entities.
If you didn't baked your models and haven't defined the _accessible property, or added the primary key field to it, then yes, in case the posted data makes it to the patching mechanism, then that is what will happen, you'll be left with an UPDATE instead of an INSERT.
The Security component
The Security component will prevent form tampering, and reject requests with modified forms. If you'd use it, then the form data wouldn't make it to the add() method in the first place.
There's also the fieldList option
The fieldList option can be used when creating/patching entities in order to specifiy the fields that are allowed to be set on the entity. Sparse out the id field, and it cannot be injected anymore.
$article = $this->Articles->patchEntity($article, $this->request->data, [
'fieldList' => [
'title',
'body',
//...
]
]);
And finally, validation
Validation can prevent injections too, however that might be considered a little wonky. A custom rule that simply returns false would for example do it, you could create an additional validator, something like
public function validationAdd(Validator $validator) {
return
$this->validationDefault($validator)
->add('id', 'mustNotBePresent', ['rule' => function() {
return false;
}]);
}
which could then be used when patching the entity like
$article = $this->Articles->patchEntity($article, $this->request->data, [
'validate' => 'add'
]);

How to do Kohana Validation of $_serialize_column inside ORM

The validation on Kohana ORM is done using rules
function rules()
{
return array(
'username' => array(
array('not_empty'),
array(array($this, 'availability')),
)
);
}
I'm struggling to validate a JSON encoded column using $_serialize_columns.
class Model_Admin extends ORM {
protected $_belongs_to = array();
protected $_has_many = array(
'plans' => array(),
'groups' => array(),
'transactions' => array(),
'logins' => array()
);
protected $_serialize_columns = array('data');
/**
* #param array $data
* #param Validation $validation
*
* #return bool
*/
public function data($data, $validation)
{
return
Validation::factory(json_decode($data, TRUE))
// ... rules ...
->check();
}
public function rules()
{
return array(
'data' => array(
array(array($this, 'data'), array(':value',':validation')
)
);
}
}
the array that gets encoded is:
array(
'name' => '',
'address' => '',
'phone' => '',
'postalcode' => ''
);
the data method receives the json encoded data, because the ORM runs the filters before doing the validation, so I need to convert it back to an associative array, then create a new validation object to check specifically for the content of that array. Because I can't merge Validation rules from another Validation instance
Updated Answer
The use of a second validation object is necessary since save() causes the internal model validation object to be checked. This means that rules added to the validation object being checked from a validation rule will be ignored (Validation->check() imports the rules into local scope before looping).
Since the data itself is technically another object (in the sense of object relationships, it has its own dataset that needs validation) the ideal solution would be to find a way to create a real model that saves the data.
There are numerous other benefits to saving data with proper database column definitions, not least if you need to perform data property lookups, make in-situ changes etc. (which would otherwise require unserializing the data column, potetnailly in all rows).
There are some alternatives, but they feel like kludges to me:
Create a model that represents the data object and add rules to it, using check() to validate the data (problem: will require a lot of maintenance, no real-world table means columns must be manually defined).
Set the data as real columns in the Admin model, and use a filter that will convert it into the data column on set (problem: again, must manually define the columns and exclude the additional columns from the save operation).
I hope this is of some use.
Original Answer
The Kohana ORM save() method permits the inclusion of an "extra" validation object, which is merged into the main ORM validation object namespace.
This is documented briefly here.
If I have understood correctly, I think you are looking to do something like this:
// another script, e.g., a controller
// Create the model
$admin = ORM::factory('Admin');
// $data = the data as an array, before serialization ...
$extra_validation = Validation::factory($data)
// add ->rule() calls here, but DO NOT chain ->check()
;
// Set $data in the model if it is going to be saved, e.g., $admin->data = $data;
// Set other data... e.g., $admin->foo = 'bar';
// Save the model
try {
$admin->save($extra_validation);
}
catch (ORM_Validation_Exception $e)
{
// Manipulate the exception result
}
While in this example you must still create another validation object, you are now able to catch all exceptions in a single block. I would recommend using var_dump() or similar on $e->errors() to check the namespace if you are using i18n messages to provide a human-readable error message. You should find that a namespace called "_external" has been created in the response.