I have a table
CREATE TABLE table_name
(
EmpId VARCHAR(50),
Name VARCHAR(100)
)
How can I restrict the EmpId column to consist of two letters followed by 3-5 digits? The following are all examples of valid values:
ac236, ak2356, av23695, ak365
I tried using the following check constraint:
ALTER TABLE table_name
ADD CONSTRAINT ck_table_name CHECK (EmpId NOT LIKE'%[^a-zA-Z0-9 ]%')
However, it allows all combinations of letters & digits, such as "23" and "fads":
INSERT INTO table_name
VALUES
('23', 'Test 2'),
('fabs', 'Test 2');
If a value violates the format, I'd like the query to fail and print error message. For example, if 'na23' were inserted as the EmpID, MySQL could say:
Empid should be ab123/ab1234/a12345 format
Initially, I was using MySQL 5.7.11-0ubuntu6-log (which, it turns out, doesn't support CHECK constraints), but have upgraded to MySQL 8.0.17.
Assuming it's MySQL >=8.0.16
check(EmpId regexp '^[a-z]{2}[0-9]{3,5}$')
Related
So I read the other posts but this question is unique. So this SQL dump file has this as the last entry.
INSERT INTO `wp_posts` VALUES(2781, 3, '2013-01-04 17:24:19', '2013-01-05 00:24:19'.
I'm trying to insert this value to the table...
INSERT INTO `wp_posts` VALUES(5, 5, '2005-04-11 09:54:35', '2005-04-11 17:54:35'
it gives me the error, "Column count doesn't match value count at row 1." So I'm lost on the concept of how the column and row apply here.
Doesn't 2781,3 mean row 2781 and column 3? And doesn't 5,5 mean row 5 and column 5?
The error means that you are providing not as much data as the table wp_posts does contain columns. And now the DB engine does not know in which columns to put your data.
To overcome this you must provide the names of the columns you want to fill. Example:
insert into wp_posts (column_name1, column_name2)
values (1, 3)
Look up the table definition and see which columns you want to fill.
And insert means you are inserting a new record. You are not modifying an existing one. Use update for that.
you missed the comma between two values or column name
you put extra values or an extra column name
You should also look at new triggers.
MySQL doesn't show the table name in the error, so you're really left in a lurch. Here's a working example:
use test;
create table blah (id int primary key AUTO_INCREMENT, data varchar(100));
create table audit_blah (audit_id int primary key AUTO_INCREMENT, action enum('INSERT','UPDATE','DELETE'), id int, data varchar(100) null);
insert into audit_blah(action, id, data) values ('INSERT', 1, 'a');
select * from blah;
select * from audit_blah;
truncate table audit_blah;
delimiter //
/* I've commented out "id" below, so the insert fails with an ambiguous error: */
create trigger ai_blah after insert on blah for each row
begin
insert into audit_blah (action, /*id,*/ data) values ('INSERT', /*NEW.id,*/ NEW.data);
end;//
/* This insert is valid, but you'll get an exception from the trigger: */
insert into blah (data) values ('data1');
MySQL will also report "Column count doesn't match value count at row 1" if you try to insert multiple rows without delimiting the row sets in the VALUES section with parentheses, like so:
INSERT INTO `receiving_table`
(id,
first_name,
last_name)
VALUES
(1002,'Charles','Babbage'),
(1003,'George', 'Boole'),
(1001,'Donald','Chamberlin'),
(1004,'Alan','Turing'),
(1005,'My','Widenius');
You can resolve the error by providing the column names you are affecting.
> INSERT INTO table_name (column1,column2,column3)
`VALUES(50,'Jon Snow','Eye');`
please note that the semi colon should be added only after the statement providing values
In my case i just passed the wrong name table, so mysql couldn't find the right columns names.
So I read the other posts but this question is unique. So this SQL dump file has this as the last entry.
INSERT INTO `wp_posts` VALUES(2781, 3, '2013-01-04 17:24:19', '2013-01-05 00:24:19'.
I'm trying to insert this value to the table...
INSERT INTO `wp_posts` VALUES(5, 5, '2005-04-11 09:54:35', '2005-04-11 17:54:35'
it gives me the error, "Column count doesn't match value count at row 1." So I'm lost on the concept of how the column and row apply here.
Doesn't 2781,3 mean row 2781 and column 3? And doesn't 5,5 mean row 5 and column 5?
The error means that you are providing not as much data as the table wp_posts does contain columns. And now the DB engine does not know in which columns to put your data.
To overcome this you must provide the names of the columns you want to fill. Example:
insert into wp_posts (column_name1, column_name2)
values (1, 3)
Look up the table definition and see which columns you want to fill.
And insert means you are inserting a new record. You are not modifying an existing one. Use update for that.
you missed the comma between two values or column name
you put extra values or an extra column name
You should also look at new triggers.
MySQL doesn't show the table name in the error, so you're really left in a lurch. Here's a working example:
use test;
create table blah (id int primary key AUTO_INCREMENT, data varchar(100));
create table audit_blah (audit_id int primary key AUTO_INCREMENT, action enum('INSERT','UPDATE','DELETE'), id int, data varchar(100) null);
insert into audit_blah(action, id, data) values ('INSERT', 1, 'a');
select * from blah;
select * from audit_blah;
truncate table audit_blah;
delimiter //
/* I've commented out "id" below, so the insert fails with an ambiguous error: */
create trigger ai_blah after insert on blah for each row
begin
insert into audit_blah (action, /*id,*/ data) values ('INSERT', /*NEW.id,*/ NEW.data);
end;//
/* This insert is valid, but you'll get an exception from the trigger: */
insert into blah (data) values ('data1');
MySQL will also report "Column count doesn't match value count at row 1" if you try to insert multiple rows without delimiting the row sets in the VALUES section with parentheses, like so:
INSERT INTO `receiving_table`
(id,
first_name,
last_name)
VALUES
(1002,'Charles','Babbage'),
(1003,'George', 'Boole'),
(1001,'Donald','Chamberlin'),
(1004,'Alan','Turing'),
(1005,'My','Widenius');
You can resolve the error by providing the column names you are affecting.
> INSERT INTO table_name (column1,column2,column3)
`VALUES(50,'Jon Snow','Eye');`
please note that the semi colon should be added only after the statement providing values
In my case i just passed the wrong name table, so mysql couldn't find the right columns names.
I created a table in MySql
CREATE TABLE newuser(id VARCHAR(10) PRIMARY KEY,sname VARCHAR(20));
When I INSERT record it works fine
INSERT INTO newuser VALUE('abc123','monika');
But sometimes I don't want to supply id in the INSERT query and sometimes I want to supply. In case I don't supply id MySql automatically generate one.
What can I do to get both below query works?
INSERT INTO newuser VALUE('abc123','monika');
INSERT INTO newuser VALUE('nikita');
'I don't understood ANYTHING' - very new then.
Firstly second insert statement is invalid please review https://dev.mysql.com/doc/refman/8.0/en/insert.html -
'If you do not specify a list of column names for INSERT ... VALUES or INSERT ... SELECT, values for every column in the table must be provided by the VALUES list, SELECT statement, or TABLE statement.'
Secondly uuid is a function in which 'A UUID is designed as a number that is globally unique in space and time.' https://dev.mysql.com/doc/refman/8.0/en/insert.html
You can easily select uuid() to see what it produces.
You will need to increase the id size
If you wish to use it in an insert
insert into users values (uuid(),<sname>);
I wanted to add an entry inside a table in SQL database.
For example I have the following Database
CREATE TABLE `distributor_geneology` (
`distributor_gen_id` bigint(20) NOT NULL,
`user_id` varchar(24) NOT NULL,
`id` bigint(20) NOT NULL,
`sponsor_id` bigint(20) NOT NULL,
`rank` tinyint(4) NOT NULL
);
And I want to add an entry in sponsor_id or say id inside a database.
First, I imported the database in my SQL Workbench then In my SQL Workbench, I ran a command select * from distributor_geneology which gave me
Error Code: 1146. Table 'dba_db.distributor_genelogy' doesn't exist
[Question] How can I create/add Entry for ID (or sponsor ID or any other filed)?
One typical way which data would enter a MySQL database is via an INSERT statement:
INSERT INTO distributor_geneology (distributor_gen_id, user_id, id, sponsor_id, rank)
VALUES
(1, 1, 1, 1, 1);
I am inserting 1 everywhere, but you may alter the tuple with the values you want.
Another way to get data into a table is bulk loading via LOAD DATA.
For your first part of your question which is "Add an entry to inside table"
this operation called insertion in the database and the keyword database used to insert data is insert into
It is possible to write the INSERT INTO statement in two ways:
1- specifies both the column names and the values to be inserted
INSERT INTO table_name (column1, column2, column3, ...)
VALUES (value1, value2, value3, ...);
you can rearrange the columns orders as you want but must the values be the same order of the columns and you can let any column null if you don't want to insert any data in this column but be careful if you have not null column you must insert in you query
in your case, all the columns you have are not null.
2- if you do not need to specify the column names in the SQL query. make sure the order of the values is in the same order as the columns in the table
INSERT INTO table_name
VALUES (value1, value2, value3, ...);
For your second part of your question which is "Error Code: 1146. Table 'dba_db.distributor_genelogy' doesn't exist"
First, ensure you imported the DB correctly and if yes > write try to use DB name in your query.
select * from DB_Name.Table_Name
Edit:
Try this query format
INSERT INTO distributor_geneology (distributor_gen_id, user_id, id, sponsor_id, rank)
VALUES
(10, '10', 10, 10, 10);
please note I put second value between 2 quotes because you are defining the user_id as varchar which means not an integer so we should put it between qouts
I am using the SQL feature phpMyAdmin to add 1 single record into my table. For simplicity, the record will be blank except for the 'symbol' field.
Table structure:
token_id = auto-increment, primary key
symbol = varchar(255)
every thing else is set to allow null entires, so should be irrelevant
I have tried the following queries, but all result in the same error:
unknown column 'symbol' in 'field list'
What I have tried:
INSERT INTO tokens (symbol) VALUES ('XYZ');
INSERT INTO tokens (symbol) VALUES ("XYZ");
INSERT INTO tokens (symbol) VALUES (XYZ);
INSERT INTO tokens.symbol VALUES ('XYZ');
INSERT INTO `tokens`.`symbol` VALUES ('XYZ');
Any suggestions?
Just for reference, trying the INSERT and using all columns and setting them to null results in the same exact error.
The correct format with backticks is
INSERT INTO tokens (symbol) VALUES ('XYZ');
FYI, I tried your first query on my server and worked fine so might be a problem with table structure.