SQL query involving comparison of sets - mysql

Question

Background
Products can be sold as bundles. Following tables are present: products, bundles, bundles_products, orders, orders_products.
An order would be said to "contain" a bundle if it contains all the bundle's products.
Problem
How would one go about counting orders for bundles?
Example
products table
id name
1 broom
2 mug
3 spoon
4 candle
bundles table
id name
1 dining
2 witchcraft
bundles_products table
bundle_id product_id
1 2
1 3
2 1
2 4
orders_products table
order_id product_id
1000 1
1000 3
1001 1
1001 2
1001 3
The query would return the following table:
bundle orders
dining 1
witchcraft 0
Notes
The example intentionally misses the orders table as it is not relevant what it contains.
Of course, this could be approached imperatively, by writing some code and gathering the data, but I was hoping there is a declarative, SQL way of querying for this kind of things?
One idea I had was to use a GROUP_CONCAT to concatenate all the products of a bundle and somehow compare that with products of each order. Still, a long way from clear.

Answer 1

One way is to use two Derived Tables (subqueries). In first subquery, we will fetch the total number of unique products for every bundle. In the second subquery, we will fetch the total products in an order, for a combination of order and bundle.
We will LEFT JOIN them on bundle_id as well as matching the total count of products per bundle in them. Eventually, we will do a grouping on bundle, and count the number of orders matching successfully.
SELECT dt1.id AS bundle_id,
dt1.name AS bundle,
Count(dt2.order_id) AS orders
FROM (SELECT b.id,
b.name,
Count(DISTINCT bp.product_id) AS total_bundle_products
FROM bundles AS b
JOIN bundles_products AS bp
ON bp.bundle_id = b.id
GROUP BY b.id,
b.name) AS dt1
LEFT JOIN (SELECT op.order_id,
bp.bundle_id,
Count(DISTINCT op.product_id) AS order_bundle_products
FROM orders_products AS op
JOIN bundles_products AS bp
ON bp.product_id = op.product_id
GROUP BY bp.bundle_id,
op.order_id) AS dt2
ON dt2.bundle_id = dt1.id
AND dt2.order_bundle_products = dt1.total_bundle_products
GROUP BY dt1.id,
dt1.name
SQL Fiddle DEMO

Answer 2

Here's the brief example, which lacks some parts, I omitted because I don't know precise database structure. Logic is such:
Temp table is generated, which consists of 3 rows - order, count of
products related to bundle, count of products in bundle
Then we select only orders from this table in which we have those last two
variables equal
select count(order_id) from orders
left join(
select count(*) from bundles_products as bundle_amount,
sum(case when orders_products in (
select names from bundles_products where bundle_id='1') then 1 else 0) as order_total,
orders.order_id
left join product on bundle_products.product_id = products.product_id
left join orders on products.product_id = orders_products.product_id
where bundle_products.bundle_id ='1'
) as my_table
on orders.order_name = my_table.orders
where my_table.bundle_amount = my_table.order_total
Edit: I posted this as a response to previous version of the question, without detailed explanation.
Edit2: fixed query a bit. It can be starting point. Logic is still the same, you can get amount of orders for each bundle_id using it