How to get results from Udemy Api with search? - json

Question

I want use udemy api in my website with search field in api.
Udemy gives my this url:
/api-2.0/courses/?search=mysql
which when I use I'm getting an empty array in my results.
However, when I use this url:
/api-2.0/courses/
It works fine, and I'm getting 1000 rows of course details..
Please help me out with the search option, how do I make it work?
<?php
echo "API testing is going on\n";
function callAPI($method, $url, $data){
$curl = curl_init();
switch ($method){
case "POST":
curl_setopt($curl, CURLOPT_POST, 1);
if ($data)
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
break;
case "PUT":
curl_setopt($curl, CURLOPT_CUSTOMREQUEST, "PUT");
if ($data)
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
break;
default:
if ($data)
$url = sprintf("%s?%s", $url, http_build_query($data));
}
// OPTIONS:
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, array( 'Accept:
application/json, text/plain, */*',
'Content-Type: application/json;charset=utf-8',
'Authorization: xxx',
));
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
// EXECUTE:
$result = curl_exec($curl);
if(!$result){die("Connection Failure");}
curl_close($curl);
return $result;
}
$URL="https://www.udemy.com/api-2.0/courses?search=mysql',auth=
('xxclientidxx','xxclientsecretxx')'";
$get_data = callAPI('GET',$URL,false);
$response = json_decode($get_data, true);
$file_json=$response['results'];
$fp=fopen('results.json','w');
fwrite($fp,json_encode($response));
fclose($fp);
echo '<br>';
print_r($response['results']);
?>

Answer 1

It would be good if you can check the API docs available from Udemy. Swagger API platform seems available for them.
Please check the URL for the courses API: https://www.udemy.com/developers/affiliate/methods/get-courses-list/