Multiple Inserts in one sql statement in C - mysql

Question

I want to insert 6406 recods into a table in one swoop without having to prepare and execute individual records. (fastest). In the code below, I want "i" to change for every insert
Ive tried everything
for( int i = 0; i < 6406 ; i++)
{
sprintf( query, "INSERT INTO table1"
"(table_id, curr_id, cur_ref_id) "
"VALUES (%d,%d,%d)",
table_id,
i,
table_id);
//assemble query
DBH->prepare(query);
}
DBH->execute();
Inset prepare failed for table1

Answer 1

My memory of the MySQL C API is a bit fuzzy, but IIRC it should look something like:
MYSQL_STMT* stmt = mysql_stmt_init(MYSQL *mysql);
mysql_stmt_prepare(stmt,
"INSERT INTO table1 (table_id, curr_id, cur_ref_id) VALUES (?,?,?)",
len_of_previous_argument);
MYSQL_BIND params[3];
memset(params, 0, sizeof(params));
params[0].buffer_type = MYSQL_TYPE_LONG;
params[1].buffer_type = MYSQL_TYPE_LONG;
params[2].buffer_type = MYSQL_TYPE_LONG;
params[0].buffer = &table_id;
params[2].buffer = &table_id;
mysql_bind_param(stmt, params);
mysql_autocommit(conn, 0);
for ( int i = 0; i < 6406 ; i++) {
params[1].buffer = &i;
mysql_stmt_execute(stmt);
}
mysql_commit(conn);
mysql_stmt_close(stmt);
You'll obviously want to throw in some error handling, but this should give you the basic idea.
It might be faster to only have one parameter and encode the table_id values in the query string instead, but I'm lazy and you obviously know how to do that already (snprintf should have "(%d,?,%d)", then pass the result to mysql_stmt_prepare, then the params array will only be a single item).