I have date with timestamp eg: 2019-05-06 00:00:00
I want this date without timestamp
output: 2019-05-06
use date() function
select date("2019-05-06 00:00:00" )
You can do it in this way in MySQL
SELECT CONVERT("2019-05-06 00:00:00", date);
In MSSQL same can be done in this way
select convert(varchar, your_date, 23)
You can get help from here
You can use the MySQL function DATE_FORMAT()
DATE_FORMAT(%Y-%m-%d)
More information is here
Related
I get a datetime field, that's currently in the query as:
SELECT DATE_FORMAT(x.date_entered, '%Y-%m-%d') AS date FROM x ORDER BY date ASC
What I want to do is to subtract 3 hours from that date (GMT issues), but I can't do it in PHP as PHP only knows the date part, not the time.
mySQL has DATE_SUB():
SELECT DATE_SUB(column, INTERVAL 3 HOUR)....
but would it not be better to try and sort out the underlying time zone issue instead?
Assuming you have some timezone issue and know source and destination timezone, you could convert it like so
SELECT DATE_FORMAT(CONVERT_TZ(x.date_entered, 'UTC', 'Europe/Berlin'),
'%Y-%m-%d') AS date
FROM x ORDER BY date ASC;
Normal select query.
Once applied DATE_ADD() function in MySQL
select lastname,
date_add(changedat, interval -24 hour) as newdate
from employee_audit;
lastname and changedat is field name and employee_audit is table name.
I have date in database like 2019-05-02 12:14:20 and field name is created_date Now i want to get record with created date like 2019-05-02 12:14. Don't want to check seconds.
I've tried with separating time but it won't work could you please suggest some solution which we can achieve in single mysql query.
Thanks in advance
You can use DATE_FORMAT to check a specific part of datetime to a string:
SELECT *
FROM table_name
WHERE DATE_FORMAT(created_date, '%Y-%m-%d %H:%i') = '2019-05-02 12:14'
demo on dbfiddle.uk
I want to change the format of column ENROLLED_ON "yyyy-mm-dd" to "mmm-yy". Please help.
ENROLLED_ON | ENROLLED_ON
------------| ------
yyyy-mm-dd | mmm-yy
Please try
SELECT DATE_FORMAT(enrolled_on, '%b-%y') AS enrolled_on
FROM my_table
;
For info on MySQL date and time functions and the DATE_FORMAT function in particular, please see: MySQL 5.7 Reference Manual: 13.7 Date and Time Functions
update
table_name
set enrolled_on = DATE_FORMAT(enrolled_on,'%b-%Y');
This is an update query for your column.
You can use DATE_FORMAT option which is inbuilt keyword of MySQL. Use it as:
SELECT DATE_FORMAT(CURDATE(), '%d/%m/%Y')
SELECT DATE_FORMAT(column_name, '%d/%m/%Y') FROM tablename
or using this, you can get date in any format you want
SELECT DATE_FORMAT(date_field, '%d/%m/%Y')
On my database under the t_stamp columns I have the date for example
2013-11-26 01:24:34
From that same column I only want to get the date
2013-11-26
How can i do this? Thank You!
You can use date(t_stamp) to get only the date part from a timestamp.
You can check the date() function in the docs
DATE(expr)
Extracts the date part of the date or datetime expression expr.
mysql> SELECT DATE('2003-12-31 01:02:03');
-> '2003-12-31'
You can convert that time in Unix timestamp by using
select UNIX_TIMESTAMP('2013-11-26 01:24:34')
then convert it in the readable format in whatever format you need
select from_unixtime(UNIX_TIMESTAMP('2013-11-26 01:24:34'),"%Y-%m-%d");
For in detail you can visit link
To get only date from timestamp in MySQL just use DATE_FORMAT(datetime, '%Y-%m-%d'):
SELECT DATE_FORMAT('2013-11-26 01:24:34', '%Y-%m-%d');
> 2013-11-26
$date= new DateTime($row['your_date']) ;
echo $date->format('Y-m-d');
Dates are stored in DB as such: "2011-05-26 11:00:00" in a datetime field. I'd like to find all rows where the date is greater than the first of this month, ie: 2011-05-01 09:00:00
The date formats in the DB can not be changed. What MySQL function can I use to convert the date in the DB to a format that can handle comparison? I'm guessing the best format for "first of the month" is a unix timestamp?
The time values in the dates are always present but only office hours, so from 09:00 to 17:00.
If it's stored in a DATETIME field, just query on WHERE date > '2011-05-01 09:00:00'.
$firstDayOfMonth = date( 'Y-m-d H:i:s', mktime(0,0,0,date('n'),1,date('Y'));
$query = "SELECT * FROM `table` WHERE `date` >= '$firstDayOfMonth'";
Something like this perhaps?
$oDateTime = new DateTime();
$sQuery = "SELECT * FROM table WHERE date >= ".$oDateTime->format("Y-m")."-01 09:00:00";
Compare to the datetime directly:
WHERE date_field >= '2011-05-01 00:00:00'
DATETIME fields can filtered just like integer fields, example:
SELECT * FROM `table` WHERE `date` > '2011-05-01 09:00:00'
In case you really want to convert to Unix timestamps, have a look at the UNIX_TIMESTAMP function.
You can use TIMESTAMPDIFF function in MySQL to compare time,
FROM_UNIXTIME function to format Unix timestamp as date.
More mysql data and time functions and examples are available in MySQL Reference Manual date and time function .
I think that you can solve it, something like this:
firstly, create first day of month in mysql format in php
$firsDay = date('Y-m-d 00:00:00', strtotime(date('Y-m').'-01 00:00:00'));
and then, use it in the query
select * from something where date >= $firsDay