This is an example of a meta tag from which I want to get the pub_date:
<meta name="parsely-page" content='{"title":"Article title","link":"https:\/\/site.com\/category\/article","type":"post","section":"category","image_url":"","author":null,"pub_date":"2009-03-01T14:17:14+00:00","post_id":"article_6463676334","tags":[]}' />
The xpath to get the entire content would be:
//meta[#name="parsely-author"]/#content
Is it possible to get the values of dict keys using xpath?
With XPath 3.1 you can do
//meta[#name="parsely-author"]/parse-json(#content)?pub-date
Sadly, it's very likely that you are using an XPath processor that only supports XPath 1.0 in which case you won't be able to use this unless you find a different processor.
With XSLT 1.0:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vQ">"</xsl:variable>
<xsl:template match="/">
<xsl:value-of select=
'substring-before(substring-after(//meta[#name="parsely-page"]/#content,
concat($vQ, "pub_date", $vQ, ":", $vQ)), $vQ)'/>
</xsl:template>
</xsl:stylesheet>
When this transformation is performed on this XML document (your meta tag):
<meta name="parsely-page"
content='{"title":"Article title","link":"https:\/\/site.com\/category\/article","type":"post","section":"category","image_url":"","author":null,"pub_date":"2009-03-01T14:17:14+00:00","post_id":"article_6463676334","tags":[]}' />
the wanted result is produced:
2009-03-01T14:17:14+00:00
We can write a single XPath 1.0 expression that evaluates to the wanted string, however we will have to escape quotes and apostrophes in order to avoid errors for their being nested, if unescaped:
substring-before(substring-after(//meta[#name="parsely-page"]/#content,
'"pub_date":"'),
'"')
Verification using XSLT 1.0:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vQ">"</xsl:variable>
<xsl:template match="/">
<xsl:value-of select=
'substring-before(substring-after(//meta[#name="parsely-page"]/#content,
'"pub_date":"'),
'"')'/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied to the same XML document (above), it evaluates the single XPath 1.0 expression and outputs the wanted, correct result:
2009-03-01T14:17:14+00:00
Related
I'm trying to transform an XML document to be in single-line and wrap it in a one-element JSON. Using XSLT 1.0
The problem is, XSL generates double quotes in the xmlns definitions so the resulting JSON is invalid.
This is my input:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<otm:Transmission xmlns:otm='http://xmlns.oracle.com/apps/otm/transmission/v6.4' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'>
<otm:TransmissionHeader/>
<otm:TransmissionBody>
<otm:GLogXMLElement>
<otm:Invoice>
<otm:Payment>
<otm:PaymentHeader>
<otm:DomainName>CompanyX</otm:DomainName>
<otm:TransactionCode>EX</otm:TransactionCode>
<otm:InvoiceDate>
<otm:GLogDate>20220414000000</otm:GLogDate>
</otm:InvoiceDate>
</otm:PaymentHeader>
</otm:Payment>
</otm:Invoice>
</otm:GLogXMLElement>
</otm:TransmissionBody>
</otm:Transmission>
This is what I'm getting:
{"jsonElement":"<otm:Transmission xmlns:otm="http://xmlns.oracle.com/apps/otm/transmission/v6.4" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><otm:TransmissionHeader/><otm:TransmissionBody><otm:GLogXMLElement><otm:Invoice><otm:Payment><otm:PaymentHeader><otm:DomainName>CompanyX</otm:DomainName><otm:TransactionCode>EX</otm:TransactionCode><otm:InvoiceDate><otm:GLogDate>20220414000000</otm:GLogDate></otm:InvoiceDate></otm:PaymentHeader></otm:Payment></otm:Invoice></otm:GLogXMLElement></otm:TransmissionBody></otm:Transmission>"}
The XSL that I use:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:otm='http://xmlns.oracle.com/apps/otm/transmission/v6.4'>
<xsl:output method="text" indent="no" suppress-indentation="otm:Transmission"/>
<xsl:strip-space elements="*" />
<xsl:template match="/">
{"jsonElement":"<xsl:apply-templates select="*"/>"}
</xsl:template>
<xsl:template match="#* | *">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
As you can see, the JSON is invalid due to double quotes in the xmlns definitons.
I tried several approaches and I am not able to get rid of the double quotes. In the input, they are single quotes but XSL is generating them differently.
What would be the best approach to have a valid JSON result?
The XML in the JSON has to be 1:1 copy of the input but transformed into a single line and I can only use XSLT 1.0
An XSLT 1.0 processor is going to reject the suppress-indentation attribute, and it's going to output the text of the source document without markup. Like #MartinHonnen, I don't see how any XSLT processor can give you the output you claim to be getting.
In XSLT 3.0 you can do
<xsl:output method="json">
<xsl:template match="/">
<xsl:map key="'jsonElement'"
select="serialize(., map{'method':'xml'})"/>
</xsl:template>
I have a variable containing non-numerical values, and I need to completely remove duplicate entries from this string using XSLT:
$string = a,b,c,c,d,d,e,f,g
needs to become: $newstring = a,b,e,f,g
An alternative option would be to compare the two variables and ignore/remove the overlapping entries.
$stringA = a,c
$stringB = a,b,c,d,e,f
needs to become:
$newstring = b,d,e,f
Concatenating the variables is straightforward but I need the opposite of that!
Please help,
XSLT is designed to process XML, not strings. XSLT 1.0 in particular is a poor tool for manipulating text.
IMHO, the best way to proceed here is to convert the problem to XML first. If you're using libxslt (as xsltproc does), this is quite easy to do using an extension function:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:str="http://exslt.org/strings"
extension-element-prefixes="str">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="stringA">a,c,g</xsl:param>
<xsl:param name="stringB">a,b,c,d,e,f</xsl:param>
<xsl:variable name="setA" select="str:tokenize($stringA, ',')" />
<xsl:variable name="setB" select="str:tokenize($stringB, ',')" />
<xsl:template match="/">
<test>
<xsl:for-each select="$setA[not(.=$setB)] | $setB[not(.=$setA)]">
<xsl:value-of select="."/>
<xsl:if test="position()!=last()">,</xsl:if>
</xsl:for-each>
</test>
</xsl:template>
</xsl:stylesheet>
Result:
<?xml version="1.0" encoding="UTF-8"?>
<test>g,b,d,e,f</test>
In the html output file from an XSLT process (using saxon9he), there have been 155 occurrences of xmlns:fn="http://www.w3.org/2005/xpath-functions" inserted into a variety of tr elements
The part of xsl that uses xpath-functions is
<xsl:if test="(string(#hideIfHardwareIs)='') or (not(fn:matches(string($input_doc//inf[#id='5'), string(#hideIfHardwareIs), 'i')))">
unless I am reading it wrong, matches takes 3 arguments, a string, another string and then a flag in which case this is case-insensitive.
What I don't undestand is that the tr elements that are showing up with the xmlns arent close to the portion or xsl that the matches() function is done at.
The XSL file I am working with is 2100 lines and the XML file it parses is 12800 lines. So I don't think I can share it easily. I've inherited this and need to (at this time) maintain it.
What are somethings i can look for within the XSL that would insert the xmlns into the html output?
Those functions do not need to be prefixed.
Remove the xmlns:fn="http://www.w3.org/2005/xpath-functions" from your xsl:stylesheet and remove the fn: prefix from the xpath functions.
Examples:
XML Input
<foo>test</foo>
XSLT 2.0 #1
<xsl:stylesheet version="2.0" xmlns:fn="http://www.w3.org/2005/xpath-functions"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:if test="fn:matches(.,'^t')">
<bar><xsl:value-of select="."/></bar>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Output
<bar xmlns:fn="http://www.w3.org/2005/xpath-functions">test</bar>
XSLT 2.0 #2
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:if test="matches(.,'^t')">
<bar><xsl:value-of select="."/></bar>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Output
<bar>test</bar>
How to modify the below xsl to process parameters whose value is tags. Instead of using w:p and w:pPr/w:pStyle/#w:val i will be passing them as args
Actual XSl:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml"
>
<xsl:param name="styleName"/>
<xsl:output method="text"/>
<xsl:template match="w:p"/>
<xsl:template match="w:p[w:pPr/w:pStyle/#w:val[matches(., concat('^(',$styleName,')$'),'i')]]">
<xsl:value-of select="."/><xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
Required XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml">
<xsl:param name="styleName" select="'articletitle'"/>
<xsl:param name="para" select="'//w:p[w:pPr/w:pStyle/#w:val[matches(.,concat('^(',$styleName,')$')]]'"/>
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:for-each select="$para">
<xsl:value-of select="."/><xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
NOTE: You should get used to give information about which version of xslt and which processor you are using. In this case, the answer is valid only if you are using XSLT 2.0
This is not a complete answer, but you can start by looking at this approach:
Try using local-name and in-scope-prefixes (only available in XSLT 2.0) to match a node dynamically.
Here you have an example template to replace your empty template:
<xsl:template match="*[local-name()=substring-after($para,':') and in-scope-prefixes(.)[.=substring-before($para,':')]]"/>
For the second part of the expression ($parastyle), I can only think about writing your own function to evaluate it dynamically.
I'll try to post an example of such a function later on.
I fugured out the problem in my coding, is in second line,
<xsl:param name="para" select="'//w:p[w:pPr/w:pStyle/#w:val[matches(.,concat('^(',$styleName,')$')]]'"/>
Since i have given the quotes in select attribute the value has been considered as string instead of xpath expression.
I'm starting using XSLT and write this scipt:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="utf-8" />
<xsl:template match="span[#class='thumb']" >
Link: <xsl:value-of select="$base" /><xsl:value-of select="a/#href" />
</xsl:template>
<xsl:template match="/">
Base href: <xsl:value-of select="$base" />
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
And using this command:
xsltproc --html --param base "'http://example.com'" lista.xslt test.html
I need to get list of Links, but I get whole page on output. What's wrong? How can I get it works?
There are some default templates which are unseen here. The really easy way to resolve it is to just explicitly limit to the span elements you're matching as below. Otherwise, you can override the default templates.
<xsl:template match="/">
Base href: <xsl:value-of select="$base" />
<xsl:apply-templates select="//span[#class='thumb']" />
</xsl:template>
There's a default template that matches essentially everything if you let it. Your 4th last line calls that template.
That's part of the problem. The rest can probably be taking care of by matching just the stuff you're looking for, directly in the top-level template.