I have a button in html that i want to make a search bar appear when clicked and make it disappear when clicked a second time. I already know how to do the first one but i don't know how to to do the second one.
Looks like you are asking for a toggle switch, on/off or true/false state. Simply declare a local variable in your component and set it false initially. Change it once the button is clicked -
<button (click)="onClick()">
<div *ngIf="showSearchbar">this is searchbar</div>
showSearchbar: boolean;
onClick() {
this.showSearchbar = !this.showSearchbar;
}
Related
Here is the link for an example of the issue I will attempt to describe. In the chips autocomplete example, click the text box to select a new fruit.
Now, before clicking anywhere else, click again on the text box as you did before.
This should result in no options showing up. The issue here is that the user must either begin keying in a new selection or first click another element in the window before matchip will show the options to choose from. I am wondering if there is a way to fix this issue. I would like a user to be able to choose a selection from the list and then immediately click the text box as they had before and make a new selection.
I'm using mat-chip-list inside an outer *ngFor iterating over a FormArray.
Here is what I'have done. It's pretty efficient :
<input
#validatorInput
#operationTrigger="matAutocompleteTrigger"
[formControl]="contactCtrl"
[matAutocomplete]="auto"
[matChipInputFor]="chipList"
(blur)="contactCtrl.setValue(''); validatorInput.value='';"
(click)="contactCtrl.setValue(''); validatorInput.value=''; operationTrigger.openPanel()">
The trick is
Always clear your html input and your (shared) formControl with an empty and not null value each time the blur and click events occur.
Do NOT do this 'clear' on the input focus event. (Because when you delete the last chip, the input is auto-focus and you will have the famous Expression has changed after it was checked.
Call operationTrigger.openPanel(); when the user click on the input
Setting contactCtrl.setValue(''); allows your autocomplete panel to be automatically opened when you call operationTrigger.openPanel()
Setting validatorInput.value=''; is just a way to properly sync your formControl with the html input to ensure a good UX/UI behavior.
Inside my formArray, the formControl is the same for all the inputs but it does not matter since the user can only manipulate one input at a given time
Since you didn't post your code and you mention the example on the material site I'm going to do it as a fork of the stackblitz example they have on their site.
But this will allow you to open the autocomplete panel again despite having had the cursor there and choosing an option previously.
// Using MatAutocompleteTrigger will give you access to the API that will allow you to
// to open the panel or keep it open
...
#ViewChild(MatAutocompleteTrigger, {static: false}) trigger: MatAutocompleteTrigger;
...
ngAfterViewInit() {
fromEvent(this.fruitInput.nativeElement, 'click')
.pipe(
tap(() => {
this.trigger.openPanel()
})
).subscribe()
}
Link to the full stackblitz:
https://stackblitz.com/edit/angular-sb38ig
I have a custom element that I just want to show when I click a button. Then, when I click that button, I want to do something like...:
<my-element [hidden]="switchHidden()"></my-element>
... so if it's in false, it now will be true, and viceversa. A very typical approach.
But I don't know how I can pass to my function "switchHidden()" the value of the "hidden" attribute. How can I do this, so I can check whether it is true or false?
Thank you!
Don't use hidden attribute, use:
<my-element *ngIf="switchHidden"></my-element>
http://angularjs.blogspot.ba/2016/04/5-rookie-mistakes-to-avoid-with-angular.html
PLUNKER Demo
Just have a variable in your component that is a boolean for when you want to show and hide it.
let showElement: Boolean = true;
Then when you want to toggle it on/off with a button put this in the click.
<button (click)="showElement = !showElement">Toggle</button>
and that will flip the value of showElement every time the user clicks the button. So if showElement is true, when the user clicks the button it will make showElement false and thus hidding your element. Vise versa for when showElement is false, the user clicks the button making it true and thus showing your element.
I have a question about making input fields required before being able to click a input button (not submit button). My code below only will send out the requirement notice after a submit button is click.
I have my form split into 3 div's with 'next' buttons in between which conditionally displays the next div. How do I make the input field to be required before the 'next' button brings up the next div portion of my form?
You should post the html for your question. It is missing. That being said, look into the blur event that gets trigger everytime an input loses focus. You could add the logic to display an error to the user and disable the next button.
http://www.w3schools.com/jquery/event_blur.asp
You have two main options:
FIRST OPTION
You could disable your button like so: <input id="but" type="button" disabled>, and then, you could set your field onchange method to enable the button i. e. <input type="text" onchange="changed();"> and in your script,
function changed(){
if(1 == 1){ // custom test
document.getElementById("but").disabled = false;
}
}
SECOND OPTION
In your button handler, verify your textfield is filled i. e.
function butHandler(){
if(document.getElementById("textfield").value !== "") {
// do your actions
}
}
I was wondering how to make a link, that when clicked it would open 2
links: One would open in a new tab instantly Second one would open in
a new window after a minute or so.
I also want to embed this in a website like weebly.
This is an edit to make things simpler -
linky
two opens one click
This sounds very spammy and not recommended but if you were to do it, I would do it a separate function rather than in line in the onclick html attribute.
Try the below. It will give a 5 second time gap between links.
function openPage1() {
window.open(url1);
window.setTimeout(openPage2,5000);
}
function openPage2() {
window.open(url2);
}
// Just call openPage1 from your button click handler
openPage1();
I'm using the code bellow to change the color of button on rollover and rollout and clicked. I have following issues in this
1. The color did not changed when button is clicked.
2. Button wont work after once clicked.
pages.gotoAndStop("home");
// list of button instance names
var previousClicked:DisplayObject;
var buttonsss:Array = [home, menudown.about, menudown.portfolio, menudown.clients, menudown.pricing, menudown.contact];
for each ( var mc:MovieClip in buttonsss)
{
mc.buttonMode = true;
mc.mouseChildren = false;
mc.addEventListener(MouseEvent.MOUSE_UP, onClick);
mc.addEventListener(MouseEvent.ROLL_OVER, rolloverEffect);
mc.addEventListener(MouseEvent.ROLL_OUT, rolloutEffect);
}
function onClick(e:MouseEvent):void
{
pages.gotoAndStop(e.target.name);
e.currentTarget.mouseEnabled = false;
TweenLite.to(e.currentTarget,2,{tint:0x666666, ease:Strong.easeOut});
TweenLite.to(previousClicked,2,{tint:null , ease:Strong.easeOut});// set the previous clicked to null tint
previousClicked.addEventListener(MouseEvent.ROLL_OUT, rolloutEffect);// restore the Roll_Over effect
previousClicked = DisplayObject(e.target); // update the last clicked button
e.target.removeEventListener(MouseEvent.ROLL_OUT, rolloutEffect);
}
function rolloverEffect(e:MouseEvent):void{
TweenLite.to(e.currentTarget,2,{tint:0x666666, ease:Strong.easeOut});
}
function rolloutEffect(e:MouseEvent):void{
//should change tint to null just when its enabled, but its changing always (enabled or disabled)
TweenLite.to(e.currentTarget,2,{tint:null , ease:Strong.easeOut});
}
How I have always done this is with the built in buttons instead of doing it with code.
If you click window up in the top bar then click on components (near the bottom) it will bring up a little window then if you expand the user interface folder and drag and drop from the button item. Then with that button on the stage if you double click on it you will go into the edit symbol screen and it will have pictures of each state that the button and if you double click on the state you want then you can visually edit that version of the button.
Hope this helped.
Note: I first started with flash pro-cs5.5 and your tag says flash-cs5 I don't know for sure if that function is available or not in 5.
I am unfamiliar with Tweenlite, but I'm guessig that what it does in this case is simply change the color, am I right? If so, I'd suggest creating the color changes on your timeline and using framelabels combined with gotoAndStop to create the different effects. This should also solve your problem concerning the button not working after it has been clicked once.