I need to create a mysql query that should get only one row result from two tables.
I have a table called users and a table called users_sports.
SELECT * FROM users WHERE id = 71
SELECT user_sport_sport FROM users.sports WHERE user_sport_user = 71
I would need a query result in only one row that has all users values from table users and all user_sport_sport values for a specific user.
For example: id=71, username="mike2"...sport1="Basketball",sport2="Soccer".
EDIT tb_user_sports
Table users
Table tb_sports
You can use group_concat to fetch all the sports for that user id
select u.name, GROUP_CONCAT(ts.sport_name) sports from users u
join tb_user_sports tus ON tus.user_sport_user = u.id
left join tb_sports ts ON ts.id_sport = tus.user_sport_sport
where u.id = 72
group by u.id
Source: https://dev.mysql.com/doc/refman/8.0/en/group-by-functions.html#function_group-concat
For alias: link1 and link2
Related
I am wondering if I can have join between two tables but on different columns? Let me explain because it is different with most of the cases that I've seen...
I have a table for all the messages between users and each user has a unique user id. so In the first table I have:
Tx User Id .......... Rx. User Id .......... Date ............ Message
and in user tables I have
user Id .............. User name
Can I have a join query that gives me
Tx User "Name" ........... Rx. User "Name: ....... Date ....... Message
The problem is that in my join apparently I can only define
SELECT messages.* users.name
FROM messages JOIN
users
ON messages.RxId = users.id OR messages.TxId = users.id
which is only 1 field, but as I explained above I need 2 field as Rx user name and Tx. User Name based on which id in my messages table is matched.
Thanks a lot in advanced.
You want two joins. And for this you need to learn about table aliases (a good thing):
SELECT m.*, urx.name, utx.name
FROM messages m LEFT JOIN
users urx
ON m.RxId = urs.id LEFT JOIN
users utx
ON m.TxId = utx.id;
I have two tables activity_log and user_followers. I have to join these two tables and get the activity of a user with the user activity that he is following (let's say user_id 6 is following user_id 4). But the below query only returning the activity of the user having the id of 6. I want to get the activity of the user with the id of 6 plus the activity of the user he is following.
Query
SELECT activity_log.*
FROM activity_log
join user_followers ON activity_log.user_id = user_followers.follow_id
AND activity_log.user_id = 6;
activity_log:
user_followers:
Sounds like you want user_id 6's activity plus activity of users he's following. That would be:
SELECT activity_log.*
FROM activity_log
LEFT OUTER JOIN user_followers
ON activity_log.user_id = user_followers.follow_id
WHERE (activity_log.user_id = 6 OR ISNULL(user_followers.user_id,0) = 6);
The LEFT OUTER is used in case user_id 6 has no followers.
i'm running into a complex problem, the data in a db has three tables.
First_DB
-- default_users
id username email password
1 Timbog Timbog#mail.com vads7y3kkjdfa
2 Marta Marta#mail.com vads7y3kkjdfa
-- default_album
album_id album_name default_user_id
1 Name_Tim 1
3 Katarina 2
-- default_album_img
img_id image_file album_id
3 1320229733.jpg 1
4 3320229733.jpg 3
Second_DB
--users
user_id user_name user_email user_pass user_image
1 Timbog Timbog#mail.com vads7y3kkjdfa 1320229733.jpg
2 Marta Marta#mail.com vads7y3kkjdfa 3320229733.jpg
The approach i used to solve this problem is to first fetch all data by inner join, should i use full outer join and insert the required field to my table, the following query is actual by which i'm trying to make it wor:
INSERT INTO bbpin.users ( user_name, user_pin, user_email, user_password, user_img)
SELECT default_users.username, default_users.bb_pin, default_users.email, default_users.password
FROM bbmpins_pins.default_users
INNER JOIN bbmpins_pins.default_album_images
ON default_album_images.album_id = default_users.id;
i miss the thing how do i compare two table's id in this join maybe? or this query is all wrong by approach?
By two tables which are sepearte in First_DB there could be multiple record how do we trunk them to last entry only ?
Thanks
It looks like you are attempting to retrieve all rows from the default_users table. And along with each row, also return the corresponding row(s) from default_album table. And along with that, the corresponding row(s) from default_album_img table.
Given the example data, a query using inner joins would return the specified result:
SELECT u.id AS user_id
, u.username AS user_name
, u.email AS user_email
, u.password AS user_pass
, i.image_file AS user_image
FROM default_users u
JOIN default_album a
ON a.default_user_id = u.id
JOIN default_album_img i
ON i.album_id = a.album_id
That query will work for the example data.
But, if there is a row in default_user which doesn't have a matching row in default_album, then an inner join won't return that row:
-- default_users
id username email password
3 branstark bran#winterfell warg2
Or, if there are two or more rows in default_album that match a given user, then the query will return two copies of the row from default_user...
-- default_album
album_id album_name default_user_id
1 Tim2 1
Without a specification of what is to be returned in those cases, we can't recommend a query.
I don't see anything wrong with your current approach using a JOIN but could modify it a bit to be more readable and also you will have to join the relation table
INSERT INTO bbpin.users (user_id, user_name, user_pin, user_email, user_password, user_img)
SELECT du.id,
du.username,
du.bb_pin,
du.email,
du.password,
dai.image_file
FROM bbmpins_pins.default_users du
JOIN bbmpins_pins.default_album da ON du.id = da.default_user_id
INNER JOIN bbmpins_pins.default_album_images dai
ON dai.album_id = da.album_id;
I am trying to pull both owner and editby. Both of those fields are INT. Inside a simple table, for example:
users:
user_id user_name
-----------------
2 johnny
3 mecca
doc:
owner content editby
----------------------
2 misc 3
SQL:
SELECT doc.owner, doc.content, doc.editby, users.user_name
FROM doc
LEFT JOIN
users
ON
users.user_id = doc.owner
WHERE
doc_id = $id
I can grab owner user_name, but I am not sure how to obtain editby on the same table. How do I go about pulling the different user names for different id fields multiple times?
Join the users table twice with different aliases
SELECT doc.owner, doc.content,
e.user_name as editor,
o.user_name as owner
FROM doc
LEFT JOIN users o ON o.user_id = doc.owner
LEFT JOIN users e ON e.user_id = doc.editby
WHERE doc_id = $id
I am having a hard time understanding joins on mySQL, and I cannot find any similar example to work with.
Suppose I have two tables: users and users_info.
in users I have id, email and password fields while, in users_info I have all their information, like name, surname, street, etc.
so, if I am getting a user like this:
SELECT * FROM users WHERE id = 43
and their information like this:
SELECT * FROM users_info WHERE id = 43
I will basically get 2 results, and 2 tables.
I understand now that I need to use join so that they are all together, but I just can't figure out out.
Any help?
It seems like both tables users and user_info are related with each others by the column id therefore you need to join them using this column like this:
SELECT
u.id,
u.email,
u.password,
i.name,
i.surname,
i.street
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id;
This will only select the fields id, email, ... etc. However, if you want to select all the columns from both the tables use SELECT *:
SELECT *
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id;
If you want to input the id and get all of these data for a specific user, add a WHERE clause at the end of the query:
SELECT *
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id
WHERE u.id = 43;
For more information about JOIN kindly see the following:
Join (SQL)From Wikipedia.
Visual Representation of SQL Joins.
Another Visual Explanation of SQL Joins.
Here's an example
SELECT * FROM users u
INNER JOIN users_info i
ON u.id=i.id
this means, you are joining users table and users_info table
for example
users
id name
---- -------
1 abc
2 xyz
users_info
id email
--- ------
1 abc#aaa.com
2 xyz#aaa.com
the query will return
id name email
--- ----- -------
1 abc abc#aaa.com
2 xyz xyz#aaa.com
Here's a nice tutorial
You can also do:
SELECT users.*, users_info.*
FROM users, users_info
WHERE users.id = users_info.id AND users.id = 43;
This means:
"Get me all the columns from the users table, all the columns from the users_info table for the lines where the id column of users and the id column of users_info correspond to each other"