I want to retrieve values from a table with figures formatted in float. The decimal places range up to thirteen. I only want to retrieve the rows whose values only have exactly 2 decimal places. How do I do this?
Expected output:
[45.678, 56.236656457, 89.23, 100.89] ==> [89.23, 100.89]
You can use select Length(123.12 % 1) - 2 to get the length of the values after the decimal.
select (123.12 % 1) returns 0.12 so you always know that you have 0. in your result set, you can then get the length of your value minus the two characters and only select the rows where length = 2.
Related
I am in SQL Workbench and want my output to include 4 decimal places. I have tried different combinations of casting 'sessions', 'transactions', and 'cvr' as DECIMAL as well as using ROUND, and I can't seem to get the output I'm looking for. 'sessions' and 'transactions' are both in NUMERIC(19,2) format.
Ideally, I want to stay away from casting to float to avoid losing precision.
select cast((transactions/sessions) as decimal(10,5)) as cvr
from(select name
,sum(cast(sessions as decimal(10,5))) as sessions
,sum(cast(transactions as decimal(10,5))) as transactions
How to get output with 4 decimal places
SELECT FORMAT(123.456789, 4) as col
123.4567
SELECT FORMAT(123.456, 4) as col
123.4560
I need to export some customer balances from a table and import to another. However the customer_ID column is not fixed and need to be, the values are anywhere from 3 to 5 digits (eg.322…4144…11833).
I would like to export the data with the customer_ID and customer_bals to a csv where the values in the customer_id column are fixed to 9 digits all starting with a constant 405 at the beginning of each value. Such as eg. 405000322…405004144 and 405011833.
How would I write this query in MySQL Workbench?
Use the LPAD function to add leading zeroes, and CONCAT() to concatenate the fixed prefix.
CONCAT('405', LPAD(customerID, 6, '0'))
I need round up the numbers of a complete table of mysql with a funtion leaving the two decimals to zero?
e.g.:
from 75,55 to 86,00
from 75,45 to 75,00
All the prices of a complete table changed a few decimal and I do not know how it happened.
Can anybody help me?
You can simply use Round(X, D) function. From Docs:
Rounds the argument X to D decimal places. The rounding algorithm
depends on the data type of X. D defaults to 0 if not specified. D can
be negative to cause D digits left of the decimal point of the value X
to become zero.
Try:
SELECT ROUND(75.45, 2);
-- Fetches 75.00
SELECT ROUND(75.55, 2);
-- Fetches 76.00
Now, it seems that you want to Update all the values of a particular column, by rounding them to two decimal places. You can do the following:
UPDATE your_table_name
SET your_column_name = ROUND(your_column_name, 2);
-- It will round all the values to 2 decimal places.
"UPDATE your_table_name SET your_column_name = ROUND(your_column_name, 2);" not work for me. I dont know.
¡SOLUTION! = TABLE > ESTRUCTURE > NAME COLUMN > length/values > remove decimal.
All number round up in my row (column). Them I put decimal again. All my fields it's ok.
Hey is there any way to create query with simple formula ?
I have a table data with two columns value_one and value_two both are decimal values. I want to select this rows where difference between value_one and value_two is grater then 5. How can i do this?
Can i do something like this ?
SELECT * FROM data WHERE (MAX(value_one, value_two) - MIN(value_one, value_two)) > 5
Example values
value_one, value_two
1,6
9,3
2,3
3,2
so analogical difs are: 5, 6, 1, 1 so the selected row would be only first and second.
Consider an example where smaller number is subtracted with a bigger number:
2 - 5 = -3
So, the result is a difference of two numbers with a negation sign.
Now, consider the reverse scenario, when bigger number is subtracted with the smaller number:
5 - 2 = 3
Pretty simple right.
Basically, the difference of two number remains same, if you just ignore the sign. This is in other words called absolute value of a number.
Now, the question arises how to find the absolute value in MySQL?
Answer to this is the built-in method of MySQL i.e. abs() function which returns an absolute value of a number.
ABS(X):
Returns the absolute value of X.
mysql> SELECT ABS(2);
-> 2
mysql> SELECT ABS(-32);
-> 32
Therefore, without worrying about finding min and max number, we can directly focus on the difference of two numbers and then, retrieving the absolute value of the result. Finally, check if it is greater than 5.
So, the final query becomes:
SELECT *
FROM data
WHERE abs(value_one - value_two) > 5;
You can also do complex operations once the absolute value is calculated like adding or dividing with the third value. Check the code below:
SELECT *
FROM
data
WHERE
(abs(value_one - value_two) / value_three) + value_four > 5;
You can also add multiple conditions using logical operators like AND, OR, NOT to do so. Click here for logical operators.
SELECT *
FROM
data
WHERE
((abs(value_one - value_two) / value_three) + value_four > 5)
AND (value_five != 0);
Here is the link with various functions available in MySQL:
https://dev.mysql.com/doc/refman/5.0/en/mathematical-functions.html
No, you would just use a simple where clause:
select *
from data
where abs(value_one - value_two) > 5;
I an using MySQL database and I have a table called fertilizer_storage which is using both plus and minus values. It has 4 columns uria,TSP,MOP and TDM
I am using double as data type and getting sum of each column using follwing syntax,
SELECT SUM(uria),SUM(TSP),SUM(MOP),SUM(TDM) FROM `fertilizer_storage` WHERE `branch_ID`=1
The problem is for some columns I get unwanted floating points of 15 while all columns are containing numbers up to 4 floating points.
7.666900000000002
7.666900000000002
9.6109
9.9924
when I changed numbers in first two columns as other two it gives the correct answer. what should I do to correct this.
You can use ROUND(X, D):
Rounds the argument X to D decimal places. The rounding algorithm
depends on the data type of X. D defaults to 0 if not specified. D can
be negative to cause D digits left of the decimal point of the value X
to become zero.
SELECT Round(Sum(uria), 4),
Round(Sum(tsp), 4),
Round(Sum(mop), 4),
Round(Sum(tdm), 4)
FROM `fertilizer_storage`
WHERE `branch_id` = 1
See it in action