MySQL Attendance Calculation - mysql

Question

Here i have table attendances
I need result as shown below
How can i achieve this in mysql without using any programming language
Sql File is Attendances.sql

Answer 1

We can try a pivot query approach, aggregating by user and date:
SELECT
user_id,
DATE(date_time) AS date,
TIMESTAMPDIFF(MINUTE,
MAX(CASE WHEN status = 'IN' THEN date_time END),
MAX(CASE WHEN status = 'OUT' THEN date_time END)) / 60.0 AS hours
FROM yourTable
GROUP BY
user_id,
DATE(date_time);
The caveats of this answer are many. It assumes that there would be only one IN and OUT entry, per user, per day. If a period could cross over dates, then my answer might not generate correct results. Also, if an IN or OUT value be missing, then NULL would be reported for the hours value.

Answer 2

I have Achieve it my self by creating a mysql function and view
Mysql View
CREATE OR REPLACE VIEW `view_attendances` AS
SELECT
`a`.`id` AS `a1_id`,
`a`.`user_id` AS `user_id`,
CAST(`a`.`date_time` AS DATE) AS `date`,
`a`.`date_time` AS `in`,
`a2`.`id` AS `a2_id`,
`a2`.`date_time` AS `out`,
(TIMESTAMPDIFF(SECOND,
`a`.`date_time`,
`a2`.`date_time`) / 3600) AS `hours`
FROM
(`attendances` `a`
JOIN `attendances` `a2` ON (((`a`.`is_confirm` = 1)
AND (`a`.`status` = 'IN')
AND (`a2`.`id` = FN_NEXT_OUT_ATTENDANCE_ID(`a`.`user_id`, `a`.`date_time`, `a`.`status`))
AND (a2.status = 'OUT')
AND (CAST(`a`.`date_time` AS DATE) = CAST(`a2`.`date_time` AS DATE)))))
Mysql Function
CREATE FUNCTION `fn_next_out_attendance_id`( _user_id INT, _attendance_date_time DATETIME, _status VARCHAR(10) ) RETURNS int(11)
BEGIN
DECLARE _id INT(11);
SELECT
id INTO _id
FROM
attendances
WHERE
is_confirm = 1
AND user_id = _user_id
AND date_time > _attendance_date_time
AND `status` <> _status
ORDER BY
date_time ASC LIMIT 1 ;
RETURN if (_id IS NULL, 0, _id);
END