hey i have looked at quite a few articles now but i think my knowledge hinders me from adapting any example so here i am, hoping you can help:
What i want: Have an eloquent query which looks in 2 tables
What i have:
$myProfile = \App\User::with('friends')->where('friend_type','2')->get();
is my wished for result.
In my User Model i have the following:
public function friends()
{
return $this->hasMany(Friend::class);
}
and in my friends model:
public function user()
{
return $this->belongsTo(User::class);
}
also what i have tried, too:
$myProfile = \App\User::with(['friends'])->where('friend_type','2')->get();
or
$myProfile = \App\User::with('friends')->where('friends.friend_type',2)->get();
but the error i receive remains the same:
Column not found: 1054 Unknown column 'friends.friend_type' in 'where clause' (SQL: select * from `users` where `friends`.`friend_type` = 2 and `users`.`deleted_at` is null)
thanks very much in advance
If you want to select all users whose friend_type is 2 then you should use whereHas. It would be like
\App\User::whereHas('friends', function($q){
$q->where('friends.friend_type',2)
})->get();
I think the following would to the trick:
User::with(['friends' => function ($query) {
$query->where('friend_type', 2);
}])->get();
Related
In Laravel 9 I am trying to add the result of a subquery to a query(for lack of better wording) and I am stuck. More concretely, I am trying to load all products and at the same time add information about whether the current user has bought that product.
Why do I want to do this?
I am currently loading all products, then loading all bought products, then comparing the 2 to determine if the user has bought a product, but that means extra queries which I would like to avoid. Pretend for the sake of this question that pagination doesn't exist(because when paginating the impact of those multiple queries is far diminished).
There is a many to many relationship between the 2 tables users and products, so these relationships are defined on the models:
public function products()
{
return $this->belongsToMany(Product::class);
}
and
public function users()
{
return $this->belongsToMany(User::class);
}
What I have tried so far:
I created a model for the join table and tried to use selectRaw to add the extra 'column' I want. This throws a SQL syntax error and I couldn't fix it.
$products = Product::query()
->select('id', 'name')
->selectRaw("ProductUser::where('user_id',$user->id)->where('product_id','products.id')->exists() as is_bought_by_auth_user")
->get();
I tried to use addSelect but that also didn't work.
$products = Product::query()
->select('id', 'name')
->addSelect(['is_bought_by_auth_user' => ProductUser::select('product_id')->where('user_id',$user?->id)->where('product_id','product.id')->first()])
->get();
I don't even need a select, I actually just need ProductUser::where('user_id',$user?->id)->where('product_id','product.id')->exists() but I don't know a method like addSelect for that.
The ProductUser table is defined fine btw, tried ProductUser::where('user_id',$user?->id)->where('product_id','product.id')->exists() with hardcoded product id and that worked as expected.
I tried to create a method on the product model hasBeenBoughtByAuthUser in which I wanted to check if Auth::user() bought the product but Auth wasn't recognized for some reason(and I thought it's not really nice to use Auth in the model anyway so didn't dig super deep with this approach).
$products = Product::query()
->select('id', 'name')
->addSelect(\DB::raw("(EXISTS (SELECT * FROM product_user WHERE product_users.product_id = product.id AND product_users.user_id = " . $user->id . ")) as is_bought_by_auth_user"))
->simplePaginate(40);
For all attempts $user=$request->user().
I don't know if I am missing something easy here but any hints in the right direction would be appreciated(would prefer not to use https://laravel.com/docs/9.x/eloquent-resources but if there is no other option I will try that as well).
Thanks for reading!
This should do,
$id = auth()->user()->id;
$products = Product::select(
'id',
'name',
DB::raw(
'(CASE WHEN EXISTS (
SELECT 1
FROM product_users
WHERE product_users.product_id = products.id
AND product_users.user_id = '.$id.'
) THEN "yes" ELSE "no" END) AS purchased'
)
);
return $products->paginate(10);
the collection will have purchased data which either have yes or no value
EDIT
If you want eloquent way you can try using withExists or withCount
i.e.
withExists the purchased field will have boolean value
$products = Product::select('id', 'name')->withExists(['users as purchased' => function($query) {
$query->where('user_id', auth()->user()->id);
}]);
withCount the purchased field will have count of found relationship rows
$products = Product::select('id', 'name')->withCount(['users as purchased' => function($query) {
$query->where('user_id', auth()->user()->id);
}]);
I have the following query join in MySQL.
left join the_fields as tf on
tf.tf_kode = x.tf_kode
and tf.is_payed is not null
I tried to convert to laravel query builder like this:
->leftJoin('the_fields as tf', function ($j) {
$j->on('tf.tf_kode', '=', 'x.tf_kode');
$j->on('tf.is_payed','!=', null);
})
But it shows the error unknown column '' on clouse.
Please help. Thanks!
->on method arguments are columns and operators, You cant pass where condition in it.
You can use this:
->leftJoin('the_fields as tf', function ($j) {
$j->on('tf.tf_kode', '=', 'x.tf_kode')->whereNotNull('tf.is_payed');
});
Hope this helps you
So i have a pivot table like the following :
match id
player id
score
And i want to query to get the number of wins/losses for a given user id. (wins based on user id with the highest score for a game)
In sql i would write this like :
SELECT user_id, score
from match_user matchu1
where score = (select max(score) from match_user matchu2 where matchu1.match_id = matchu2.match_id)
How would i express this query in laravel, or is there a better method of doing this that i am missing ?
There are multiple ways to achieve this. The easiest and cleaniest way to me is defining
a relationship with pivot.
class Match extends Model
{
public function players()
{
return $this->belongsToMany(User::class, 'match_user')->withPivot('score');
}
public function winner()
{
return $this->players
->sortByDesc(function ($player) {
return $player->pivot->score;
})
->first();
}
}
Then you can simply get the winner by saying:
$match->winner();
This is to answer your true intention of asking this question, which is to get the number of wins for a single user, as you commented on my answer. The following the the best solution that I can think of for now:
class Match extends Model
{
public function scopeWonBy($query, User $user)
{
return $query->selectRaw('matches.id, max(match_user.score) AS max_store, match_user.player_id AS player_id')
->join('match_user', 'matches.id', '=', 'match_user.match_id')
->groupBy('matches.id')
->having('player_id', $user->id);
}
}
Later on, you can say:
$matches = Match::wonBy($user);
$count = Match::wonBy($user)->count();
I'm not going to write your query for you as I don't want to provide an untested solution but the following code example should give you a good idea of how to implement subqueries with the query builder.
$q->where('price_date', function($q) use ($start_date)
{
$q->from('benchmarks_table_name')
->selectRaw('min(price_date)')
->where('price_date', '>=', $start_date)
->where('ticker', $this->ticker);
});
Controller
$r = \App\User::whereIn('id', $user_ids)->withPosts($category_id)->get();
User model
public function scopeWithPosts($query, $category_id)
{
return $query->with('posts')->where('category_id', $category_id);
}
I have been at this for too many hours now.
I am trying to use with() along with an query scope to add an extra filter to the relationship.
However it gives me the error " category_id not existing in users table"? What am I missing?
Laravel 6
The problem you are experiencing is that you are expecting the with('posts') function to return a query that is relative to the Posts ORM model. It won't, it will still return a reference to the original query. What you will find is that the with function returns $this, so you'll always get the original query.
What you are attempting is a SQL query to find the User, followed by another SQL query to get all the Post records of that user, with those posts filtered by category. So
SELECT * FROM Users WHERE id=?;
SELECT * FROM Posts WHERE user_id = ? AND category_id = ?
To do that in the Eloquent relationship, you need to subquery, like so:
return $query->with(['posts' => function ($q) use ($category_id) {
$q->where('category_id', $category_id);
}]);
Please comment if you need further info and I'll edit my answer.
I have a mysql query like this:
select result.*, rank_text.text
from cache_user_challenge_result result
left join rank_text on result.rank
between rank_text.rank_from and rank_text.rank_to
Now I want to change this to eloquent for my laravel project, I tried this but it's not work:
$this->select(
"{$this->table}.user_id",
'rank_text.text'
)
->leftJoin('rank_text', "{$this->table}.rank")
->whereBetween("{$this->table}.rank", ['rank_text.rankFrom', 'rank_text.rankTo'])
->first();
Can you tell me what's wrong with this?
Thank you very much!
Update:
After a lot of hours, I change my query to this:
$this->select(
"{$this->table}.user_id",
'rank_text.text'
)
->leftJoin('rank_text', function($query) {
$query->whereBetween("{$this->table}.rank", ['rank_text.rank_from', 'rank_text.rank_to']);
})
->get();
But it's only can get user_id, not the text.
Try to create cache_user_challenge_result model Like
class CacheUserChallengeResult extends Model {
protected $table = 'cache_user_challenge_result';
public function scopeGetCacheUserRank()
{
return static::select(DB::raw('cache_user_challenge_result.*,rank_text.text'))->leftJoin('rank_text', function($join) {
$join->on('cache_user_challenge_result..rank', '=', 'rank_text.rank')->whereBetween('cache_user_challenge_result.rank',['rank_text.rankFrom', 'rank_text.rankTo']);
});
}
}
In Controller You can call like this
CacheUserChallengeResult::getCacheUserRank()->get();
It will provide you the collection for the rank you desire, also you can pass param for which rank you want in range