Below I cannot do Group by Date the following figures.
I have tried to put Group By in different lines, but not working.
SELECT SUM(a.NetAmount) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a
I wanted to see:
Days Total Amount
March 1 xxxx
March 2 xxxx
March 3 xxx
MySQL does not use TOP. Use LIMIT:
SELECT ChargeCreatedDate, SUM(netamount)
FROM (SELECT ch.ChargeCreatedDate,
(CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE bt.BalanceTransactionNet * (SELECT e.ExrateValue
FROM Exrate e
WHERE e.ExrateDate < bt.BalanceTransactionCreated AND
e.CurrencyID = bt.BalanceTransactionCurrencyID
ORDER BY ExrateDate Desc
LIMIT 1
)
END) AS NetAmount
FROM Charge ch JOIN
BalanceTransaction bt
ON ch.BalanceTransactionID = bt.BalanceTransactionID
WHERE ch.ChargeCreatedDate BETWEEN '2019-03-01' AND '2019-03-31'
) chtbt
GROUP BY ChargeCreatedDate;
If you happen to be using SQL Server, you can replace the LIMIT 1 with FETCH FIRST 1 ROW ONLY.
The following code will hopefully display what you are looking for
SELECT a.Days AS Days, SUM(cast(a.NetAmount as decimal(16,9))) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount,
ch.ChargeCreatedDate as Days
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a GROUP BY a.Days
This should be sufficient. You need to SELECT the desired value in the query in order to get it to show up. Also when using the SUM() function you need to specify what the group value will be.
Related
I'm stuck at the query where I need to concat IDs of the table. And from that group of IDs, I need to fetch that rows in sub query. But when I try to do so, MySQL consider group_concat() as a string. So that condition becomes false.
select count(*)
from rides r
where r.ride_status = 'cancelled'
and r.id IN (group_concat(rides.id))
*************** Original Query Below **************
-- Daily Earnings for 7 days [Final]
select
group_concat(rides.id) as ids,
group_concat(ride_category.name) as rideType,
group_concat(ride_cars.amount + ride_cars.commission) as rideAmount ,
group_concat(ride_types.name) as carType,
count(*) as numberOfRides,
(
select count(*) from rides r where r.ride_status = 'cancelled' and r.id IN (group_concat(rides.id) )
) as cancelledRides,
(
select count(*) from rides r where r.`ride_status` = 'completed' and r.id IN (group_concat(rides.id))
) as completedRides,
group_concat(ride_cars.status) as status,
sum(ride_cars.commission) + sum(ride_cars.amount) as amount,
date_format(from_unixtime(rides.requested_at/1000 + rides.offset*60), '%Y-%m-%d') as requestedDate,
date_format(from_unixtime(rides.requested_at/1000 + rides.offset*60), '%V') as week
from
ride_cars,
rides,
ride_category,
ride_type_cars,
ride_types
where
ride_cars.user_id = 166
AND (rides.ride_status = 'completed' or. rides.ride_status = 'cancelled')
AND ride_cars.ride_id = rides.id
AND (rides.requested_at >= 1559347200000 AND requested_at < 1561852800000)
AND rides.ride_category = ride_category.id
AND ride_cars.car_model_id = ride_type_cars.car_model_id
AND ride_cars.ride_type_id = ride_types.id
group by
requestedDate;
Any solutions will be appreciated.
Try to replace the sub-query
(select count(*) from rides r where r.ride_status = 'cancelled' and r.id IN (group_concat(rides.id) )) as cancelledRides,
with below to count using SUM and CASE, it will make use of the GROUP BY
SUM(CASE WHEN rides.ride_status = 'cancelled' THEN 1 ELSE 0 END) as cancelledRides
and the same for completedRides
And move to using JOIN instead of implicit joins
Getting an error
Operand should contain 1 column(s)
PK is ID
The table just dumps data in to the table
need to get the earliest date qty and the latest date qty and display on the same column
Any help appreciated
SELECT ebx_r_history.ItemNumber,
(SELECT r.QuantitySold as newqty, r.lastupdate as lu
FROM ebx_r_history r
WHERE ebx_r_history.ItemNumber = r.ItemNumber AND ebx_r_history.SKU = r.SKU
ORDER BY r.LastUpdate ASC
LIMIT 1),
(SELECT r.QuantitySold as newqty, r.lastupdate as lu
FROM ebx_r_history r
WHERE ebx_r_history.ItemNumber = r.ItemNumber AND ebx_r_history.SKU = r.SKU
ORDER BY r.LastUpdate DESC
LIMIT 1)
FROM
ebx_r_history
GROUP BY ebx_r_history.ItemNumber,
ebx_r_history.SKU
ORDER BY ebx_r_history.LastUpdate
This version may offer a simplified and faster alternative for you. The inner query for "AllItems" does both a min and max of the last update on a per-item number/sku basis, although I believe they would be one-in-the-same record.
So now, join that results back to the history data by item/sku and only those that match either the min or max date. If a true date/time, there would expect to only be one anyhow, vs just a date-only. So, since there would be 2 possible records (one for the min, one for the max), I am applying a MAX( IIF( )) for each respective matching the minimum and maximum dates respectively and must retain the group by clause.
Note, if you are dealing with date-only entries, or possibilities of the exact same item/sku and lastupdate are the same to the second, then you would need an approach more towards limit 1 per ascending/descending basis.
SELECT
AllItems.ItemNumber,
AllItems.SKU,
AllItems.MinUpdate,
MAX( IIF( rh.lastupdate = AllItems.MinUpdate, rh.Quantity.Sold, 0 )) as QtyAtMinDate,
AllItems.MaxUpdate,
MAX( IIF( rh.lastupdate = AllItems.MaxUpdate, rh.Quantity.Sold, 0 )) as QtyAtMaxDate
from
( SELECT
r.ItemNumber,
r.SKU,
MIN( r.lastupdate ) as MinUpdate,
MAX( r.lastupdate ) as MaxUpdate
FROM
ebx_r_history r
group by
r.ItemNumber,
r.SKU ) AllItems
JOIN ebx_r_history rh
ON AllItems.ItemNumber = rh.ItemNumber
AND AllItems.SKU = rh.SKU
AND ( rh.lastUpdate = AllItems.MinUpdate
OR rh.lastUpdate = AllItems.MaxUpdate )
group by
AllItems.ItemNumber,
AllItems.SKU
Per another answer where you were only looking to IGNORE items within the most recent 14 days, you can just add a WHERE clause to the inner query similar via
WHERE r.LastUpdate >= CURDATE() - INTERVAL 14 DAY
If your history table has an auto-incrementing ID column, AND the respective transactions have the lastUpdate sequentially stamped, such as when they are added and not modified by any other operation, then you could just apply similar but MIN/MAX of the ID column, then join back TWICE on the ID and just each row ONCE such as...
SELECT
AllItems.ItemNumber,
AllItems.SKU,
rhMin.LastUpdate as MinUpdate,
rhMin.QuantitySold as MinSold,
rhMax.LastUpdate as MaxUpdate,
rhMax.QuantitySold as MaxSold
from
( SELECT
r.ItemNumber,
r.SKU,
MIN( r.AutoIncrementColumn ) as MinAutoID,
MAX( r.AutoIncrementColumn ) as MaxAutoID
FROM
ebx_r_history r
group by
r.ItemNumber,
r.SKU ) AllItems
JOIN ebx_r_history rhMin
ON AllItems.MinAutoID = rhMin.AutoIncrementColumn
JOIN ebx_r_history rhMax
ON AllItems.MaxAutoID = rhMax.AutoIncrementColumn
order by
rhMax.LastUpdated
Try something like this:
SELECT r1.ItemNumber,
(
SELECT r.QuantitySold
FROM ebx_r_history r
WHERE r1.ItemNumber = r.ItemNumber
AND r1.SKU = r.SKU
ORDER BY r.LastUpdate ASC LIMIT 1
) AS earliestDateQty,
(
SELECT r.QuantitySold
FROM ebx_r_history r
WHERE r1.ItemNumber = r.ItemNumber
AND r1.SKU = r.SKU
ORDER BY r.LastUpdate DESC LIMIT 1
) AS latestDateQty
FROM ebx_r_history r1
GROUP BY r1.ItemNumber,r1.SKU
ORDER BY 3
You had a couple of errors. you were getting two columns inside the inner selects, and you had a couple of places where you might get the error for ambiguous column name.
sqlFiddle here
SELECT T1.ItemNumber,
T1.SKU,
T1.Old_QuantitySold,
T1.Old_LastUpdate,
T2.New_QuantitySold,
T2.New_LastUpdate
FROM
(SELECT itemNumber,SKU,QuantitySold as Old_QuantitySold,LastUpdate as Old_LastUpdate
FROM ebx_r_history r
WHERE NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate < r.LastUpdate)
)T1
LEFT JOIN
(SELECT itemNumber,SKU,QuantitySold as New_QuantitySold,LastUpdate as New_LastUpdate
FROM ebx_r_history r
WHERE NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate > r.LastUpdate)
)T2 ON (T2.itemNumber = T1.itemNumber AND T2.SKU = T1.SKU)
WHERE T1.Old_LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND T2.New_LastUpdate >= CURDATE() - INTERVAL 14 DAY
ORDER BY T2.New_LastUpdate;
you can do left join or inner join it's up to you, since T1 will always get earliest records and T2 will always get latest records for the ItemNumber,SKU grouping.
UPDATED TO IGNORE DATA OLDER THAN 14 DAYS
SELECT T1.ItemNumber,
T1.SKU,
T1.Old_QuantitySold,
T1.Old_LastUpdate,
T2.New_QuantitySold,
T2.New_LastUpdate
FROM
(SELECT itemNumber,SKU,QuantitySold as Old_QuantitySold,LastUpdate as Old_LastUpdate
FROM ebx_r_history r
WHERE LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND e.LastUpdate < r.LastUpdate)
)T1
LEFT JOIN
(SELECT itemNumber,SKU,QuantitySold as New_QuantitySold,LastUpdate as New_LastUpdate
FROM ebx_r_history r
WHERE LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND e.LastUpdate > r.LastUpdate)
)T2 ON (T2.itemNumber = T1.itemNumber AND T2.SKU = T1.SKU)
ORDER BY T2.New_LastUpdate;
ignore data older than 14 days sqlFiddle here
If you want to use exact time (14 days ago), you can replace occurences of CURDATE() with NOW()
With below Query I able to see the count(no) of issues for all issueType in JIRA for a given date .
ie.
SELECT count(*), STEP.STEP_ID
FROM (SELECT STEP_ID, ENTRY_ID
FROM OS_CURRENTSTEP
WHERE OS_CURRENTSTEP.START_DATE < '<your date>'
UNION SELECT STEP_ID, ENTRY_ID
FROM OS_HISTORYSTEP
WHERE OS_HISTORYSTEP.START_DATE < '<your date>'
AND OS_HISTORYSTEP.FINISH_DATE > '<your date>' ) As STEP,
(SELECT changeitem.OLDVALUE AS VAL, changegroup.ISSUEID AS ISSID
FROM changegroup, changeitem
WHERE changeitem.FIELD = 'Workflow'
AND changeitem.GROUPID = changegroup.ID
UNION SELECT jiraissue.WORKFLOW_ID AS VAL, jiraissue.id as ISSID
FROM jiraissue) As VALID,
jiraissue as JI
WHERE STEP.ENTRY_ID = VALID.VAL
AND VALID.ISSID = JI.id
AND JI.project = <proj_id>
Group By STEP.STEP_ID;
the result is
Status Count
open 12
closed 13
..... ....
What I'd like to achieve is something like this actually ..where the total count for status open and closed for each day .
Date COUNT(Open) COUNT(Closed)
12-1-2012 12 1
13-1-2012 14 5
The general strategy would be this:
Select from a table of all the days in a month
LEFT OUTER JOIN your table that gets counts for each day
(left outer join being necessary in case there were no entries for that day, you'd want it to show a zero value).
So I think this is roughly what you need (not complete and date-function syntax is probably wrong for your db, but it will get you closer):
SELECT aDate
, COALESCE(SUM(CASE WHEN IssueStatus = 'whateverMeansOpen' THEN 1 END,0)) OpenCount
, COALESCE(SUM(CASE WHEN IssueStatus = 'whateverMeansClosed' THEN 1 END,0)) ClosedCount
FROM
(
SELECT DATEADD(DAY, I, #START_DATE) aDate
FROM
(
SELECT number AS I FROM [SomeTableWithAtLeast31Rows]
where number between 1 and 31
) Numbers
WHERE DATEADD(DAY, I, #START_DATE) < #END_DATE
) DateTimesInInterval
LEFT OUTER JOIN
(
Put your query here. It needs to output two columns, DateTimeOfIssue and IssueStatus
) yourHugeQuery ON yourHugeQuery.DateTimeOfIssue BETWEEN aDate and DATEADD(DAY, 1, aDate)
GROUP BY aDate
ORDER BY aDate
I need to select how many days since there is a break in my data. It's easier to show:
Table format:
id (autoincrement), user_id (int), start (datetime), end (datetime)
Example data (times left out as only need days):
1, 5, 2011-12-18, 2011-12-18
2, 5, 2011-12-17, 2011-12-17
3, 5, 2011-12-16, 2011-12-16
4, 5, 2011-12-13, 2011-12-13
As you can see there would be a break between 2011-12-13 and 2011-12-16. Now, I need to be able say:
Using the date 2011-12-18, how many days are there until a break:
2011-12-18: Lowest sequential date = 2011-12-16: Total consecutive days: 3
Probably: DATE_DIFF(2011-12-18, 2011-12-16)
So my problem is, how can I select that 2011-12-16 is the lowest sequential date? Remembering that data applies for particular user_id's.
It's kinda like the example here: http://www.artfulsoftware.com/infotree/queries.php#72 but in the reverse.
I'd like this done in SQL only, no php code
Thanks
SELECT qmin.start, qmax.end, DATE_DIFF( qmax.end, qmin.start ) FROM table AS qmin
LEFT JOIN (
SELECT end FROM table AS t1
LEFT JOIN table AS t2 ON
t2.start > t1.end AND
t2.start < DATE_ADD( t1.end, 1 DAY )
WHERE t1.end >= '2011-12-18' AND t2.start IS NULL
ORDER BY end ASC LIMIT 1
) AS qmax
LEFT JOIN table AS t2 ON
t2.end < qmin.start AND
t2.end > DATE_DIFF( qmin.start, 1 DAY )
WHERE qmin.start <= '2011-12-18' AND t2.start IS NULL
ORDER BY end DESC LIMIT 1
This should work - left joins selects one date which can be in sequence, so max can be fineded out if you take the nearest record without sequential record ( t2.anyfield is null ) , same thing we do with minimal date.
If you can calculate days between in script - do it using unions ( eg 1. row - minimal, 2. row maximal )
Check this,
SELECT DATEDIFF((SELECT MAX(`start`) FROM testtbl WHERE `user_id`=1),
(select a.`start` from testtbl as a
left outer join testtbl as b on a.user_id = b.user_id
AND a.`start` = b.`start` + INTERVAL 1 DAY
where a.user_id=1 AND b.`start` is null
ORDER BY a.`start` desc LIMIT 1))
DATEDIFF() show difference of the Two days, if you want to number of consecutive days add one for that result.
If it's not a beauty contents then you may try something like:
select t.start, t2.start, datediff(t2.start, t.start) + 1 as consecutive_days
from tab t
join tab t2 on t2.start = (select min(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t4 where t4.start <= t.start and t4.start >= (select max(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t3 where t3.start <= t.start and t3.gap = 1))
where t.start = '2011-12-18'
Result should be:
start start consecutive_days
2011-12-18 2011-12-16 3
The query below gives me a report of items that are out for an equipment rental company. this is a super complicated query that takes almost 20 seconds to run. This is obviously not the correct way to get the data that I'm looking for. I build this query from PHP and add in the start date of 02-01-2011 and the end date of 03-01-2011, the product code (p_code = 1) and product pool (i_pool =1). Those 4 pieces of information are passed to a PHP function and injected into the following sql to return the report I need for a calendar control displaying how many items are out. My question is: Is there any way to simplify or do this better, or run more efficiently, using better joins or a better way to display the individual days.
SELECT DISTINCT reportdays.reportday, count(*)
FROM
(SELECT '2011-02-01' + INTERVAL a + b DAY reportday
FROM
(SELECT 0 a UNION SELECT 1 a UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9 ) d,
(SELECT 0 b UNION SELECT 10 UNION SELECT 20
UNION SELECT 30 UNION SELECT 40) m
WHERE '2011-02-01' + INTERVAL a + b DAY < '2011-03-01'
ORDER BY a + b) as reportdays
JOIN rental_inv as line
ON DATE(FROM_UNIXTIME(line.ri_delivery_dte)) <= reportdays.reportday
AND DATE(FROM_UNIXTIME(line.ri_pickup_dte)) >= reportdays.reportday
LEFT OUTER JOIN rental_in as rent on line.ri_num = rent.ri_num
LEFT OUTER JOIN rental_cancels cancelled on rent.ri_num = cancelled.ri_num
LEFT OUTER JOIN inv inventory on line.i_num = inventory.i_num
LEFT OUTER JOIN product ON inventory.p_code = product.p_code
WHERE rent.ri_extend = 0 -- disregard extended rentals
AND cancelled.ri_num is null -- disregard cancelled rentals
AND inventory.p_code = 1
AND inventory.i_pool = 1
GROUP BY reportdays.reportday
If there is any other information needed, let me know and I'll post it.
You can use:
SELECT DATE(ri_delivery) as day,
count(*) as itemsout,
FROM rental_inv
GROUP BY day;
I'm not sure if you need this or a different thing.
SELECT dates.day, count (*)
FROM rental_inv line
INNER JOIN (SELECT DATE(ri_delivery_dte) as day FROM rental_inv
WHERE ri_delivery_dte >= '2011/02/01'
AND ri_delivery_dte <= '2011/02/28'
GROUP BY day
UNION
SELECT DATE(ri_pickup_dte) as day FROM rental_inv
WHERE ri_pickup_dte >= '2011/02/01'
AND ri_pickup_dte <= '2011/02/28'
GROUP BY day) dates
ON line.ri_delivery_dte <= dates.day and line.ri_pickup_dte >= dates.day
LEFT JOIN rental_cancels canc on line.ri_num = canc.ri_num
LEFT JOIN rental_in rent on line.ri_num = rent.ri_num
WHERE canc.ri_num is null
AND rent.ri_extend = 0
GROUP BY dates.day
to find all days:
SELECT DATE(IFNULL(ri_delivery,ri_pickup)) AS date FROM rental_inv AS dateindex WHERE [YEAR-MONTH-1] <= ri_delivery <= LAST_DAY([YEAR-MONTH-1]) OR [YEAR-MONTH-1] <= ri_pickup <= LAST_DAY([YEAR-MONTH-1]) GROUP BY date HAVING NOT ISNULL(date)
to find items out
SELECT COUNT(id) FROM rental_inv WHERE ri_pickup = [DATE];
to find items in
SELECT COUNT(id) FROM rental_inv WHERE ri_delivery = [DATE];
to find balance
SELECT COUNT(out.id) - COUNT(in.id) FROM rental_inv AS out INNER JOIN rental_inv AS in
ON DATE(out.ri_pickup) = DATE(in.ri_delivery) WHERE out.ri_pickup = [DATE] OR in.ri_delivery = [DATE]
You probably can join up everything but since its procedure its more clear;
I am not sure if this would be the exact answer to your problem but I would do something like this I guess. (I didn't use any SQL editor so u need to check syntax I guess)
SELECT
reportdays.d3 as d,
( COALESCE(outgoing.c1,0) - COALESCE(incoming.c2,0) ) as c
FROM
-- get report dates
(
SELECT DATE(FROM_UNIXTIME(COALESCE(l3.ri_delivery_dte, l3.ri_pickup_dte)) d3
FROM rental_inv l3
WHERE
(l3.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l3.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01'))
OR (l3.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l3.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01'))
GROUP BY d3
) as reportdays
-- get outgoing
LEFT JOIN (
SELECT DATE(FROM_UNIXTIME(l1.ri_delivery_dte)) as d1, count(*) as c1
FROM rental_inv l1
LEFT JOIN rental_cancels canc1 on l.ri_num = canc1.ri_num
LEFT JOIN rental_in rent1 on l.ri_num = rent1.ri_num
WHERE
l1.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l1.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01')
AND canc1.ri_num is null
AND rent1.ri_extend = 0
GROUP BY d1
) as outgoing ON reportdays.d3 = outgoing.d1
-- get incoming
LEFT JOIN (
SELECT DATE(FROM_UNIXTIME(l2.ri_pickup_dte)) as d2, count(*) as c2
FROM rental_inv l2
LEFT JOIN rental_cancels canc2 on l2.ri_num = canc2.ri_num
LEFT JOIN rental_in rent2 on l2.ri_num = rent2.ri_num
WHERE
l2.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l2.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01')
AND canc2.ri_num is null
AND rent2.ri_extend = 0
GROUP BY d2
) as incoming ON reportdays.d3 = incoming.d2