I'm trying to subtract now() - the created datetime field from 30 days to get the days remaining as a datetime field, mysql gives me an error for this sort of thing.
SELECT id, created, INTERVAL 30 DAY - CURRENT_DATE - created as timeleft FROM tablename
Use the Date add function to subtract 30 days like this.
SELECT DATE_ADD(current_date, interval -30 day);
Return the difference in days between two date values:
SELECT DATEDIFF(current_date, "2017-06-15");
You can use the combination of these functions to achieve the desired result.
In mysql you should translate the datetime to unix_timestamp to calculate the difference between the two days
SELECT id, created, 30 - (unix_timestamp(CURRENT_DATE) - unix_timestamp(created )) / 3600/24 as timeleft FROM tablename
For example, if i have search string "2017-12-14" then i need to find all rows that matches 7-day range: "%-12-11", "%-12-12", "%-12-13", "%-12-14", "%-12-15", "%-12-16", "%-12-17".
Is it possible to do with MySql only?
To select same day cross years you can use following trick.
get the list of last 7 days/1 week NOW() - INTERVAL 1 WEEK
get the DAYOFYEAR of that days
search the database for all values of the same day in year
.
SELECT * FROM timevalues
WHERE DAYOFYEAR(timefield) IN (
SELECT DAYOFYEAR(timefield)
FROM timevalues
WHERE DATE(timefield) BETWEEN NOW() - INTERVAL 1 WEEK AND NOW()
)
;
Note: Leap year is not taken into calculation!
According to my brief investigation according to the leap year it would be easier to extend the SQL query with tolerance of 1 day, ie to use - INTERVAL 8 DAY instead of 7 and then control the validity of the day outside the database during processing the data in a loop.
Yes, it is possible.
The function you are looking for is +/- INTERVAL expr unit. See MySQL Date and Time Functions
So to get 7 days back use - INTERVAL 7 DAY:
SELECT *
FROM tablename
WHERE DATE(timefield) BETWEEN '2017-12-14' - INTERVAL 7 DAY AND '2017-12-14'
According to your example would be enough to use -INTERVAL 1 WEEK:
SELECT *
FROM tablename
WHERE DATE(timefield) BETWEEN '2017-12-14' - INTERVAL 1 WEEK AND '2017-12-14'
And List of all possible units
MICROSECOND SECOND MINUTE HOUR DAY WEEK MONTH QUARTER YEAR
SECOND_MICROSECOND MINUTE_MICROSECOND MINUTE_SECOND HOUR_MICROSECOND
HOUR_SECOND HOUR_MINUTE DAY_MICROSECOND DAY_SECOND DAY_MINUTE DAY_HOUR
YEAR_MONTH
How to get 7 days before today date in mysql using query?
I want output like this example:-
Date Day
13/2/2016 Saturday
14/2/2016 Sunday
15/2/2016 Monday
16/2/2016 Tuesday
17/2/2016 Wednesday
18/2/2016 Thursday
19/2/2016 Friday
Note: There is no such table in mysql for date showing. I think using like CURDATE() function in mysql something like that.
The question was edited to clarify there are no tables.
MySQL (to my knowledge) has no sequence generator, and in order to prevent a procedure here's a trick you can use to generate a list of dates.
SELECT DATE(NOW() - INTERVAL n DAY) AS date,
DAYNAME(NOW() - INTERVAL n DAY) AS day
FROM (
SELECT 0 n
UNION SELECT 1
UNION SELECT 2
UNION SELECT 3
UNION SELECT 4
UNION SELECT 5
UNION SELECT 6
) q
ORDER BY day ASC
;
Note that this is a very cumbersome approach, imagine what a range of more dates would look like. If you need this for a one-shot operation, it'll be fine, if you are going to use this on a regular basis, you may want to create a procedure for it.
The table based answer (perhaps useful to others)
MySQL supports the DATE_ADD and DATE_SUB functions, which allows you to subtract an INTERVAL. Internally this is optimised to the following syntax, which you may find more flexible
SELECT *
FROM table
WHERE field >= NOW() - INTERVAL 7 DAY;
Most 'time units' are supported (MINUTE, HOUR, WEEK, etc) and you can replace the NOW() part with a field name too.
The DATE_ADD manual has some examples on how to use INTERVAL.
Basic syntax:
date + INTERVAL expr unit
date - INTERVAL expo unit
And implementation examples:
mysql> SELECT '2008-12-31 23:59:59' + INTERVAL 1 SECOND;
-> '2009-01-01 00:00:00'
mysql> SELECT INTERVAL 1 DAY + '2008-12-31';
-> '2009-01-01'
mysql> SELECT '2005-01-01' - INTERVAL 1 SECOND;
-> '2004-12-31 23:59:59'
I'm trying to get an mysql query similar to date_trunc in psql.
Unfortunate Mysql do not have date_trunc function and I found I can use extract instead in Mysql.
What I want to do is write a script which i will run let say 10 minutes past each hour but I want to only select data from begin of an hour till end of this hour.
For example I will run script 12:10 and I want to display data from 11:00:00 till 11:59:59.
In PSQL query would look like that:
SELECT *
FROM data
WHERE time > ( date_trunc('hour',now()) - interval '1 hour' )
AND time <= ( date_trunc('hour',now()) ) ORDER BY time;
I was trying to use extract in similar fashion but I have no rows returned or error :/
Query below returns for example some narrowed data but it's like 2 hours each day from day one when database was started not last hour only:
SELECT *
FROM data
WHERE extract(hour from cr_date) between extract(hour from now()) - interval 1 hour)
AND extract(hour from now())
ORDER BY cr_date;
Any ideas how this can be achieved? or what I'm doing wrong in this query?
Hour is only an integer, so it's finding any matches between , for example, 9 and 10, regardless of the date.
I would recommend
select * FROM data
where cr_date >= date(now()) + INTERVAL hour(now())-1 HOUR
and cr_date <= date(now()) + INTERVAL hour(now()) HOUR
date(now()) returns midnight, and hour(now()) returns the number of hours since midnight
so, at 11:10 am, it should result in a results between midnight + 10 hours (10 am) and midnight + 11 hours (11 am)
I want to get first day of every corresponding month of current year. For example, if user selects '2010-06-15', query demands to run from '2010-06-01' instead of '2010-06-15'.
Please help me how to calculate first day from selected date. Currently, I am trying to get desirable using following mysql select query:
Select
DAYOFMONTH(hrm_attendanceregister.Date) >=
DAYOFMONTH(
DATE_SUB('2010-07-17', INTERVAL - DAYOFMONTH('2010-07-17') + 1 DAY
)
FROM
hrm_attendanceregister;
Thanks
Is this what you are looking for:
select CAST(DATE_FORMAT(NOW() ,'%Y-%m-01') as DATE);
You can use the LAST_DAY function provided by MySQL to retrieve the last day of any month, that's easy:
SELECT LAST_DAY('2010-06-15');
Will return:
2010-06-30
Unfortunately, MySQL does not provide any FIRST_DAY function to retrieve the first day of a month (not sure why). But given the last day, you can add a day and subtract a month to get the first day. Thus you can define a custom function:
DELIMITER ;;
CREATE FUNCTION FIRST_DAY(day DATE)
RETURNS DATE DETERMINISTIC
BEGIN
RETURN ADDDATE(LAST_DAY(SUBDATE(day, INTERVAL 1 MONTH)), 1);
END;;
DELIMITER ;
That way:
SELECT FIRST_DAY('2010-06-15');
Will return:
2010-06-01
There is actually a straightforward solution since the first day of the month is simply today - (day_of_month_in_today - 1):
select now() - interval (day(now())-1) day
Contrast that with the other methods which are extremely roundabout and indirect.
Also, since we are not interested in the time component, curdate() is a better (and faster) function than now(). We can also take advantage of subdate()'s 2-arity overload since that is more performant than using interval. So a better solution is:
select subdate(curdate(), (day(curdate())-1))
This is old but this might be helpful for new human web crawlers XD
For the first day of the current month you can use:
SELECT LAST_DAY(NOW() - INTERVAL 1 MONTH) + INTERVAL 1 DAY;
You can use EXTRACT to get the date parts you want:
EXTRACT( YEAR_MONTH FROM DATE('2011-09-28') )
-- 201109
This works well for grouping.
You can use DATE_FORMAT() function in order to get the first day of any date field.
SELECT DATE_FORMAT(CURDATE(),'%Y-%m-01') as FIRST_DAY_CURRENT_MONTH
FROM dual;
Change Curdate() with any other Date field like:
SELECT DATE_FORMAT(purchase_date,'%Y-%m-01') AS FIRST_DAY_SALES_MONTH
FROM Company.Sales;
Then, using your own question:
SELECT *
FROM
hrm_attendanceregister
WHERE
hrm_attendanceregister.Date) >=
DATE_FORMAT(CURDATE(),'%Y-%m-01')
You can change CURDATE() with any other given date.
There are many ways to calculate the first day of a month, and the following are the performance in my computer (you may try this on your own computer)
And the winner is LAST_DAY(#D - interval 1 month) + interval 1 day
set #D=curdate();
select BENCHMARK(100000000, subdate(#D, (day(#D)-1))); -- 33 seconds
SELECT BENCHMARK(100000000, #D - INTERVAL (day(#D) - 1) DAY); -- 33 seconds
SELECT BENCHMARK(100000000, cast(DATE_FORMAT(#D, '%Y-%m-01') as date)); -- 29 seconds
SELECT BENCHMARK(100000000, LAST_DAY(#D - interval 1 month) + interval 1 day); -- 26 seconds
I'm surprised no one has proposed something akin to this (I do not know how performant it is):
CONCAT_WS('-', YEAR(CURDATE()), MONTH(CURDATE()), '1')
Additional date operations could be performed to remove formatting, if necessary
use date_format method and check just month & year
select * from table_name where date_format(date_column, "%Y-%m")="2010-06"
SELECT LAST_DAY(date) as last_date, DATE_FORMAT(date,'%Y-%m-01') AS fisrt_date FROM table_name
date=your column name
The solutions that use last_day() and then add/subtract a month and a day are not interchangeable.
Example:
date_sub(date_add(last_day(curdate()), interval 1 day), interval 3 month)
always works for any supplied number of months you want to go back
date_add(date_sub(last_day(now()), interval 3 month), interval 1 day)
will fail in some cases, for instance if your current month has 30 days and the month you're subtracting back to (and then adding a day) has 31.
date_add(subdate(curdate(), interval day(?) day), interval 1 day)
change the ? for the corresponding date
This works fine for me.
date(SUBDATE("Added Time", INTERVAL (day("Added Time") -1) day))
** replace "Added Time" with column name
Use Cases:
If you want to reset all date fields except Month and Year.
If you want to retain the column format as "date". (not as "text" or "number")
Slow (17s):
SELECT BENCHMARK(100000000, current_date - INTERVAL (day(current_date) - 1) DAY);
SELECT BENCHMARK(100000000, cast(DATE_FORMAT(current_date, '%Y-%m-01') as date));
If you don't need a date type this is faster:
Fast (6s):
SELECT BENCHMARK(100000000, DATE_FORMAT(CURDATE(), '%Y-%m-01'));
SELECT BENCHMARK(100000000, DATE_FORMAT(current_date, '%Y-%m-01'));
select big.* from
(select #date := '2010-06-15')var
straight_join
(select * from your_table where date_column >= concat(year(#date),'-',month(#date),'-01'))big;
This will not create a full table scan.