Show data from JSON in UITableView - mysql

Question

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I get the data and print it. Maybe the code is not correct I'm just new into swift, but I don't have any errors in Xcode. There's something missing but I just don't know what.
import UIKit
class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {
struct Class: Codable {
let first_name: String
let last_name: String
let email: String
enum CodingKeys: String, CodingKey {
case first_name = "first_name"
case last_name = "last_name"
case email = "email"
}
}
#IBOutlet weak var tableview: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
let url = URL(string: "https://x.de/x.php")
URLSession.shared.dataTask(with: url!, completionHandler: {(data, response, error) in
guard let data = data, error == nil else { print(error!); return }
let decoder = JSONDecoder()
let classes = try! decoder.decode([Class].self, from: data)
for myClass in classes {
print(myClass.first_name)
print(myClass.last_name)
print(myClass.email)
}
}
).resume()
}
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
tableview.reloadData()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
//return myarray.count
return 1
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "groupCell", for: indexPath) as UITableViewCell
return cell
}
}

Answer 1

Several issues
Your view controller is missing dataSource, an Array that holds list of users
Update the array (dataSource) once remote data is received
Reload UITableView once the array (dataSource) changes, using tableView.reloadData()
Within numberOfRowsInSection return the number of array elements dataSource.count
UITableView.dequeueReusableCell(withIdentifier:for:) requires that you register a cell class or xib using tableview.register method
Lastly, instead of underscores, as first_name, use camelCase variable naming convention, as firstName
struct User: Codable {
let firstName: String
let lastName: String
let email: String
enum CodingKeys: String, CodingKey {
case firstName = "first_name"
case lastName = "last_name"
case email = "email"
}
}
class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {
#IBOutlet weak var tableview: UITableView!
private var dataSource = [User]() {
didSet {
self.tableview.reloadData()
}
}
override func viewDidLoad() {
super.viewDidLoad()
self.tableview.register(UITableViewCell.self, forCellReuseIdentifier: "groupCell")
self.tableview.dataSource = self
self.tableview.delegate = self
let url = URL(string: "https://example.com/users.php")
URLSession.shared.dataTask(with: url!, completionHandler: { [weak self] (data, response, error) in
guard let data = data, error == nil else {
print(error?.localizedDescription ?? "An error occurred")
return
}
// Within `dataTask` we are on background thread, we must update our UITableView on main thread
DispatchQueue.main.async {
self?.dataSource = try! JSONDecoder().decode([User].self, from: data)
}
}).resume()
}
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
tableview.reloadData()
}
func numberOfSections(in tableView: UITableView) -> Int {
return 1
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return dataSource.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "groupCell", for: indexPath)
let user = self.dataSource[indexPath.row]
cell.textLabel?.text = user.firstName
return cell
}
}
Above code yields

Answer 2

In the cellForRowAt func you have to do something like that :
cell.textLabel?.text = myarray[indexPath.row]
because the text of myarray should be displayed at a label or whatever