I've got a working query on my laravel project. Is there a way to optimize or shorten this code?
$transaction = DB::connection('mysql')->table('pwn_transaction')
->join('pwn_transaction_has_details', 'pwn_transaction.ticket_number', '=', 'pwn_transaction_has_details.pwn_transaction_ticket_number')
->join('pwn_transaction_details', 'pwn_transaction_has_details.pwn_transaction_details_id', '=', 'pwn_transaction_details.id')
->join('pwn_transaction_has_transaction_items', 'pwn_transaction.ticket_number', '=', 'pwn_transaction_has_transaction_items.pwn_transaction_ticket_number')
->join('pwn_branch_has_transaction', 'pwn_transaction.ticket_number', '=', 'pwn_branch_has_transaction.pwn_transaction_ticket_number')
->join('pwn_transaction_has_customers', 'pwn_transaction.ticket_number', '=', 'pwn_transaction_has_customers.pwn_transaction_ticket_number')
->join('pwn_customers', 'pwn_transaction_has_customers.pwn_customers_id', '=', 'pwn_customers.id')
->groupBy('ticket_number')
->get();
First, you need to read Laravel eloquent
Eg.
Simple code with Transaction model in your controller
$transaction = Transaction::get();
You can use Eloquent Relationship in your model
Transaction Model
public function items()
{
return $this->hasOne(TransactionItem::class); //based on your model and relationship
}
Retrieve with relationship Constraining Eager Loads
$transaction = Transaction::with('items)->get();
Laravel use mysql as default connection or based on your config/database.php file
If you want to use multiple databases you can use something like that
Define below line in your Transaction Model
protected $connection = 'your-connection-name';
Based on your comment
Make sure you define proper relationship in Transaction model
Transaction::with('hasDetails', 'details', 'branch', 'hasCustomers', 'customer')
->groupBy('ticket_number')
->where('ticket_number', $request->pawnTicket) //assume ticket_number column is inside the transactions table
->get();
Related
How to avoid foreach-loop because Laravel query builder is used to get a single record detail.
When I tried without foreach-loop, the following error occurred "Property [name] does not exist on this collection instance".
Controller
public function show(Student $student)
{
$result = DB::table('students')
->select('*')
->where('id', "=" ,$student['id'])
->get();
foreach($result as $studentData){}
return view('student.show', ['studentData' => $studentData]);
}
Blade View
{{ $studentData->name}}
->get() always returns a Collection, even if there's only one match. If you only want the first record, you can use ->first() instead.
Do you really have to use raw queries? I assume Student is a Laravel Model, in that case, you should be able to use Student::find($id) to get the model directly.
Is there any way to get relational data ( one to many relation records ) using joins in laravel without creating different records in collection :
Example:
$orders = DB::table('orders')
->join('users', 'users.id', '=', 'orders.users_id')
->join('order_items', 'order_items.order_id', '=', 'orders.id')
->select('users.*', 'order_items.*')
->get();
So here what's happening is that its creating 6 records if order has 6 items but i want something like single records in which it has array or collection where are order items are listed.
Output I want is generally of this order:
Collection {# ▼
#items: array:[▼
0 => {
+'id':1,
...,
+ 'items: [
//here i want all the records of relation order items
]
}
]
}
Is there any way to achieve this result without using with() or load() and just only with joins or raw queries?
You should try this:
$orders = DB::table('orders')
->select('users.*', 'order_items.*')
->leftJoin('users', 'users.id', '=', 'orders.users_id')
->leftJoin('order_items', 'order_items.order_id', '=', 'orders.id')
->get();
This answer is speculative, but perhaps you want to report a single row for each user, with a CSV list of order items:
$orders = DB::table('orders AS o')
->join('users AS u', 'u.id', '=', 'o.users_id')
->join('order_items AS oi', 'oi.order_id', '=', 'o.id')
->select('u.id', DB::raw('GROUP_CONCAT(oi.name) AS orders'))
->groupBy('u.id')
->get();
If there's no reason stopping you from using the Eloquent, is the best way for working with databases.
The Eloquent ORM included with Laravel provides a beautiful, simple
ActiveRecord implementation for working with your database
Here is the Documentation Eloquent: Getting Started
The model relationship made easy in laravel, you can get you want as following:
The User model relationships:
//user orders
public function orders() {
return $this->hasMany('App\Order');
}
The Order model relationships:
//order items
public function items() {
return $this->hasMany('App\OrderItem');
}
//order owner
public function user() {
return $this->belongsTo('App\User');
}
The OrderItem model relationships:
//order
public function order() {
return $this->belongsTo('App\Order');
}
Here is a quick example of how you may get the order's items
$orders = User::find($id)->orders
foreach($orders as $order) {
$orderItems = $order->items;
}
you can make the collection the way you prefer, but strongly recommend using Eloquent Resources, since most apps these days expecting JSON responses.
My query is the following:
select employe.id, employe.nam, users.name, users.name_user
from employe
left join users
on users.name = employe.id
it is a query to two tables: employe, users.
How can I pass it to my controller? Am I new to laravel..
I assume the user to employee is a One to One relation.
Did you setup the relation in both models?
If so you can do the following in your controller:
$employees = Employee::with('user')->all();
This will load all employees and the related user.
Question is the users.name a foreign key on the employee.id?
Thats a bit strange, i recommend using id's on both models (autoIncrement).
Laravel use a MVC pattern, a good practice is use a Model for your employe table
I recomend you to use an Eloquen Model, so, your query will look like this:
Employe::select('employe.id', 'employe.nam', 'users.name', 'users.name_user')
->leftJoin('users', 'users.name', 'employes.id')
->get();
You can easily maintain this kind of query with Eloquent relationships.
Add this method on your employee model
public function user(){
return $this->hasOne('App\User','name','id');
}
Add this method on your user model
public function Employee(){
return $this->belongsTo('App\Employee','id','name');
}
Add line on your controller
$employees = Employee::with('user')->all();
In my model Questions I have simple relation to Standpoint
public function standpoints_byrel()
{
// return $this->hasMany('App\Models\Standpoint');
return $this->hasMany('App\Models\Standpoint', 'question_id');
}
Now,
I have yet another model Userattitude (tableuser_attitudes`) which allow users to upvote and downvote Standpoints.
I am able to list Standpoints, which were voted by a given user:
$user_attitudes = Userattitude::join('entitystandpoints', function ($q) use($questionid,$user) {
$q->where('user_attitudes.item_type', '=', 'entitystandpoint');
$q->on('user_attitudes.item_id', '=', 'entitystandpoints.id');
$q->where('entitystandpoints.question_id', '=', $questionid);
$q->where('user_attitudes.creator_id','=', $user);
})
->select('user_attitudes.*')
->get();
TO DO
Now I try to list all standpoints, which were NOT voted by the given user.
I have no idea how to do it using Eloquent.
Any help appreciated.
edit
condition to meet:
if an user votes up or down, a new model Userattitude is created. Therefore Standpoint models not down- or upvoted have nothing to join. still, in the Userattitude there are two fields for upvoting : 'attitude' and 'importance'. often one of them is null
Try with a left join where the left parameter of the join is null.
Something like this (but please check the syntax out, I'm not an Eloquent expert):
$user_attitudes = Userattitude::leftJoin('entitystandpoints', function ($q) use($questionid,$user) {
$q->where('user_attitudes.item_type', '=', 'entitystandpoint');
$q->on('user_attitudes.item_id', '=', 'entitystandpoints.id');
$q->where('entitystandpoints.question_id', '=', $questionid);
$q->where('user_attitudes.creator_id','=', $user);
})
->whereNull('entitystandpoints.id')
->select('user_attitudes.*')
->get();
Let me know.
I have two models Category and Transaction the table structures are like this
Categories:
id,category_name,..
and
Transactions:
id,category_id,amount..
The relation is
Category hasMany transactions
public function transactions()
{
return $this->hasMany('App\Transaction');
}
Transactions blongsTo Category
public function category()
{
return $this->belongsTo('App\Category', 'category_id');
}
I want to retrieve all data of transaction table which are sorted by category name.
Most importantly I want to get it using the eloquent method.
I have tried eager load which I think doesn't work on the belongsTo relationship.
Here is the code I have used for the eager load.
$transactions = Transaction::with(['category' => function ($query) {
$query->orderBy('category_name', 'asc');
}])->paginate(10);
So far I can achieve this by writing a query like below, but I'd like to use the eloquent method.
$transactions = Transaction::select(DB::raw('transactions.*'))
->leftJoin(DB::raw('(select id,category_name from categories) as categories'), 'categories.id', '=', 'transactions.category_id')
->orderBy('category_name', 'asc')
->paginate(10);
It'd be nice if someone can help me with this. Thank You.
Note: I am using Laravel 5.1
You have to provide the method name that defines the relationship, in your case this is category.
$transactions = Transaction::all()->with('category')->group_by('category.name')->get();
$transactions = Transaction::with('categories')->group_by('category.name')->get();
$cs = Course::where(['courses.active' => 1])
->whereHas('course_dates', function ($join) use ($now) {
$join->where('course_dates.start_date_time', '>', $now);
$join->orderBy('course_dates.start_date_time', 'asc');
})
->whereHas('category', function ($join) use ($cat_slug) {
$join->where('categories.url_slug', '=', $cat_slug);
})
->whereHas('language', function ($join) use ($cat_slug) {
$join->where('languages.string_id', '=', strtoupper(App::getLocale()));
})
->with(['course_dates' => function($q){
$q->orderBy('course_dates.start_date_time', 'desc');
}])
->join('course_dates' ,'course_dates.course_id', '=', 'courses.id')
->orderby('course_dates.start_date_time')
->limit(7)
->get();
To return Eloquent models ordered by related model (hasMany) column, I had to join the tables and then orderBy, still get the models, but correctly ordered by course_date.start_date_time.
Laravel 5.7, I don't think there is a cleaner solution (at least after few hours of tinkering and searching the web).