I have a problem with Eloquent, how to show the sum of products with 0 purchase price.
my model invoice and method products
public function products()
{
return $this->belongsToMany(Product::class)->withPivot('quantity', 'product_name', 'net_unit_price', 'gross_unit_price', 'purchase_price');
}
my model products and method invoice
public function invoices()
{
return $this->belongsToMany(Invoice::class);
}
and I need sum - net_unit_price from invoices sold in this month for eg
$sellMonthReplace = $user->invoices()
->with(['products' => function ($query) {
$query->wherePivot('purchase_price', '=', '0');
}])
->whereNull('parent_id')
->where('incoming', '=', '0')
->whereNull('is_proforma')
->where('sell_date', '>', $now->format('Y-m-01'))
->sum('net_value');
but this isn't working.
this below work well but is raw SQL and I don`t know how do it in eloquent
select SUM(invoice_product.net_unit_price*invoice_product.quantity)
from homestead.invoices
join homestead.invoice_product on invoice_product.invoice_id = invoices.id
where invoices.sell_date > 2019-03-01
and invoices.incoming = 0
and invoices.parent_id is null
and invoices.is_proforma is null
and invoice_product.`purchase_price` = 0
anybody could help me? thank you in advance
Did you try to cut your query short to make sure that your relations are working?
Also is the $user variable filled properly ?
What does a dump of the $sellMonthReplace return to you?
Related
I have a query of MySQL but I need to convert it into an eloquent model laravel 8. The query is given below,
$query = "SELECT group_id FROM `chat_histories` join chat_group on chat_group.id = chat_histories.group_id where chat_group.is_group = 1 and chat_histories.created_at BETWEEN '$startDate' and '$endDate' and chat_histories.deleted_at is null group by group_id";
$query = "select count(group_id) as total_chat_thread from ($query) total_chat";
DB::select($query);
So far i have done this,
ChatHistory::leftJoin('chat_group', 'chat_group.id', '=', 'chat_histories.group_id')
->selectRaw('count(*) as totals')
->where('chat_group.is_group', 1)
->whereBetween('chat_histories.created_at', [$startDate, $endDate])
->groupBy('chat_histories.group_id')
->count('totals');
But this returns a list, but I need that count of the list. That means it's showing 22 rows, I need that 22 as return.
My Model ChatHistory relation with ChatGroup
public function chatGroup() {
return $this->belongsTo(ChatGroup::class, 'group_id', 'id');
}
My Model ChatGroup relation with ChatHistory
public function chatHistory() {
return $this->hasMany(ChatHistory::class,'group_id','id');
}
Please help to convert it into an eloquent model query
Thanks in advance.
If you have the model Group with a relation history hasMany. it should be like this.
$groupCount = ChatGroup::whereHas('chatHistory', function ($historyQB) use($startDate,$endDate) {
$historyQB->whereBetween('created_at', [$startDate, $endDate])
->whereNull('deleted_at');
})->count();
You dont need the whereNull, if the model ChatHistory has softDelete enabled.
Maybe you should consider using Models, it would be much easier/cleaner
Something like that should work
DB::table('chat_histories')->select('group_id')->join('chat_group', 'chat_group.id', 'chat_histories.group_id')->where('chat_groups.is_group', 1)->whereBetween('chat_histories.created_at', $startDate, $endDate)->whereNull('chat_histories.deleted_at')->groupBy('group_id')->count();
I have User and UserComplains Models.
I like to retrieve users that have UserComplains more than 2 times in the last 24 hours.
users:
id
user_complains:
complained_id ->ref-> users.id
created_at
this is what I tried and it is working:
$users = User::select('users.*')->join('user_complains' , 'users.id' , '=' , 'user_complains.complained_id')
->whereRaw("(
select count(*) from `user_complains`
where `user_complains`.`complained_id` = `users`.`id`
and `user_complains`.`created_at` > ?) >= ?" , [now()->subHours(24), 2])
->groupBy("users.id")
->get();
the above code is fine and is working, but I wonder is there a better way to do that?!
For something like this you can use whereHas(). :
$users = User::whereHas('*relationship*', function ($query) {
$query->where('created_at', '>=', now()->subDay(1));
}, '>', 2)->get();
As mentioned in the documentation, you can pass additional checks as the 3rd and 4th param so in this case you want to say where the user has more that 2 user_complains.
NB You will need to replace *relationship* with the actual name of the relationship.
You can do the following:
User::whereHas('complaints', function($query) {
$query->where('created_at', '>=', '2020-04-26');
}, '>', 2)->get();
In order for this to work though you need to have set up a relationship between your User and UserComplaint models.
class User extends Model
{
public function complaints()
{
return $this->hasMany(UserComplaint:class);
}
}
I have two tables employees and customers , i've gave the schema below.
Customers('id' , 'username', 'location');
Employees('id' , 'EmployeeID' , 'CustomerID', 'location');
Currently I can use a query to retrieve customers details like the below query , note this is when the user is logged into the system hence the Auth::
$customerQuery1 = DB::table('customer')
->where('id', '!=', Auth::id())
->where('item', '=' , Auth::customer()->recommendation)
->get();
Each Employee has many customers ,I want other customers to see other customer items so i have attach the CustomerID field which is a foreign key and relates to the id field within the Customer table.
I've tried something like the below however I think I may need a join query but i'm unsure.
$query2 = DB::table('Customer','Employee')
->select('username')
->where(['EmployeeID' => Auth::id(), 'CustomerID' => 'id'])
->get();
$query2 = DB::table('Customer')
->select('username')
->join('Employee', 'Customer.id', '=', 'Employee.CustomerID')
->where(['EmployeeID' => Auth::id(), 'CustomerID' => 'id'])
->get();
I am then returning the values to my blade file like the below
return view ('pages.dashboard')
->with('query1',$query1)
and then Im using php indentation within my blade file to return the users data
#foreach ($query1 as $Userfound)
{{ $Userfound->username}}</p>
#endforeach
Actual Query needed in plain english
so I need to select a customer , where CustomerID == id
NOTE: id is from the customers table, CustomerID stored in the Employees table.
You can create Models using Laravel, for example:
Employee.php
public function customers()
{
return $this->hasMany('App\Customer');
}
Customer.php
public function employee()
{
return $this->belongsTo('App\Employee');
}
Which you can access like so:
$customer = Customer::where('id',Auth::user()->id)->firstOrFail();
or
$employee = Employee::where('id',Auth::user()->id)->firstOrFail();
And to see an employee's customers:
$employee->customers()->get();
Or to see the other customers of $customer's employer:
$customer->employee()->customers()->get();
Could anybody tell me what error I might have in my laravel query, basically what I want is to list the records of a table whose id is not related in another table. I did it in Mysql with this query: SELECT * FROM item WHERE NOT EXISTS (SELECT null FROM qualifications WHERE grades.item_id = item.id AND qualifications.user_id = 2);
but now I need to do this same query in laravel, I tried it this way:
codigo
and what I get is this syntax error that I do not know how to solve anymore:
error
I am very grateful to anyone who can tell me what I am doing wrong, or in what form I make that query in Laravel.
You can also rewrite your query as left join like
SELECT i.*
FROM item i
LEFT JOIN qualifications q ON q.item_id = i.id AND q.user_id = 2
WHERE q.item_id IS NULL
In query builder you can write it as
DB::table('item as i')
->select('i.*')
->leftJoin('qualifications as q', function ($join) use($user_id) {
$join->on('q.item_id', '=', 'i.id')
->on('q.user_id', '=', $user_id);
})
->whereNull('q.item_id')
->get();
Another approach which i suggest you to go with, is setup your relations and models and do it with eloquent way
class Item extends Model
{
public function qualifications()
{
return $this->hasMany(\App\Models\Qualification::class, 'item_id');
}
}
class Qualification extends Model
{
public function qualifications()
{
return $this->belongsTo(Item::class, 'item_id');
}
}
And then you can use Querying Relationship Absence
Item::whereDoesntHave('qualifications', function ($query) use($user_id) {
$query->where('user_id', '=', $user_id);
})->get();
I am losing my head over this query. I really need assistance on this one:
SELECT COUNT(*) FROM customers
WHERE (SELECT count(*) FROM customerEmails WHERE email = :email) > 0
OR (SELECT count(*) FROM customerPhoneNumbers WHERE phoneNumber = :cellphone) > 0
OR cellphone = :cellphone
OR email = :email
I don't know if what should be eloquent code for this. TIA!
You can use Eloquent's whereHas (just above that anchor a little) method to conditionally load Customers depending on their relationships with other entities. Assuming you have a model called Customer, you could try:
$count = Customer::whereHas('customerEmails', function ($query) use ($email){
$query->where('email', $email);
})
->orWhereHas('customerPhoneNumbers', function ($query) use ($cellphone){
$query->where('phoneNumber', $cellphone);
})
->orWhere('cellphone', $cellphone)
->orWhere('email', $email)
->count();