how to get particular json value in swift - json

Question

I want the size value in json object but the problem is I'm getting whole json data i want only size value to print
here is my json
[{
size = {
height = 20
width = 10
},
number = 100
}]
here is my code
do{
let Json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers)
//print(Json as Any)
guard let newValue = Json as? [[String: Any]] else {
print("invalid format")
return
}
print(newValue)
}catch {
print("Response Not Found.")
}

Answer 1

Please learn to read JSON, it's pretty easy, there are only two collection types:
[] is array, Swift [Any] but in almost all cases [[String:Any]], accessed with index subscription.
{} is dictionary, Swift [String:Any], accessed with key subscription
Never use the mutableContainers option in Swift, it has no effect at all.
if let json = try JSONSerialization.jsonObject(with: data!) as? [[String:Any]] {
for item in json {
if let size = item["size"] as? [String:Any] {
print(size["height"], size["width"])
}
}
}
And variable names are supposed to start with a lowercase letter.
PS: You have to cast the type of height and width. The output – which is actually not JSON – is ambiguous, you cannot see if the value is String or Int

Answer 2

You just need to extract size from newValue . Try this
do {
let Json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers)
guard let newValue = Json as? [[String: Any]],
let size = newValue[0]["size"] as? [String:Any] else {
return
}
print(size)
}
catch {
print("Response Not Found.")
}

Answer 3

guard let newValue = Json as? [[String: Any]] else {
print("invalid format")
return
}
print(newValue["size"])
or if you want height & width
var sizeDict = newValue["size"] as! [String:Any]
print("Width - \(sizeDict["width"])")
print("Width - \(sizeDict["height"])")