Can animation only be applied to 'absolute' positioned elements? - html

I am trying to animate an object using DOM and struggling to animate the element when its CSS property position is not set to "absolute". Here is my code below:
I create a circle HTML element and try to move it in 45 degrees. Is there any way to animate an HTML element object that is not positioned absolute?
x = 10;
function on_click() {
var myCurvyMovement = document.getElementById("circle");
myCurvyMovement.style.left = 0.5 * x;
myCurvyMovement.style.top = 1 + x
x += 10;
}
#circle {
position: absolute;
width: 100px;
height: 100px;
background: red;
-moz-border-radius: 50px;
-webkit-border-radius: 50px;
border-radius: 50px;
}
/* Cleaner, but slightly less support: use "50%" as value */
#divBox {
position: static
}
<body>
<button style="display:block" onclick="on_click()">Move the box</button>
<div id="circle">
</div>
</body>

I wouldn't consider left/right in order to do animation. As you have noticed, it won't work in all the cases as it need positionned elements. Even when using positionned element you won't have the same behavior between relative, absolute and fixed because each one will have its own reference for top/left.
For such case better consider transform that you can apply to any element (shouldn't be an inline element) and the reference of the movement will be the same for all. You will also have better performance.
x = 10;
function on_click() {
var myCurvyMovement = document.getElementById("circle");
myCurvyMovement.style.transform = "translate(" + (0.5 * x)+"px,"+(1 + x)+"px)";
x += 10;
}
#circle {
width: 100px;
height: 100px;
background: red;
border-radius: 50px;
transition:0.5s all; /*to have a smooth movement*/
}
<body>
<button style="display:block" onclick="on_click()">Move the box</button>
<div id="circle">
</div>
</body>

You forgot to concatenate the "px" to set the x and y positions
x = 10;
function on_click() {
var myCurvyMovement = document.getElementById("circle");
myCurvyMovement.style.left = 0.5 * x + 'px';
myCurvyMovement.style.top = 1 + x + 'px';
x += 10;
}
#circle {
position: absolute;
width: 100px;
height: 100px;
background: red;
-moz-border-radius: 50px;
-webkit-border-radius: 50px;
border-radius: 50px;
}
/* Cleaner, but slightly less support: use "50%" as value */
#divBox {
position: static
}
<body>
<button style="display:block" onclick="on_click()">Move the box</button>
<div id="circle">
</div>
</body>
when not's absolute you need change the margin-left and margin-top property, in javascript is like this
myCurvyMovement.style.marginLeft = 1 + x + 'px'
myCurvyMovement.style.marginTop = 1 + x + 'px'
(top/bottom and left/rigth)

Related

How can I position the element at very precise pixel on image using Top and Left CSS property

I want to display a dot at specific pixel on image click. I'm displaying it by giving top and left values in %. What happening is the dot isn't moving when clicked another pixel present inside the dot.
When click outside then it is moving. I don't understand why this is happening.
May be it is because there is very small change in top and left values for each pixel.
I've updated CSS for displaying dot within the circle
.hObiiS{
border: solid 1px #303030 !important;
background: rgba(0, 0, 0, 0.3);
border-radius: 50%;
box-sizing: border-box;
box-shadow: none !important;
height: 9px !important;
position: absolute;
transform: translate3d(-50%, -50%, 0);
width: 9px !important;
display: flex;
flex-direction: column;
justify-content: center;
align-items: center;
}
.hObiiS::before{
position: absolute;
content: '';
width: 1px;
height: 1px;
background-color: rgb(224, 1, 1);
border-radius: 50%;
}
<div class="hObiiS" style="top: 25.4601%; left: 58.6382%;"></div>
Can someone please provide solution to move dot per pixel ?
Here is your problem solution.
let container = document.querySelector('img');
let dot = document.getElementById('dot');
document. addEventListener('click', function( e ) {
if (container === event.target && container.contains(e. target)) {
var parentPosition = getPosition(container);
var xPosition = e.clientX - parentPosition.x - (dot.clientWidth / 2);
var yPosition = e.clientY - parentPosition.y - (dot.clientHeight / 2);
dot.style.left = xPosition + "px";
dot.style.top = yPosition + "px";
}
});
// Helper function to get an element's exact position
function getPosition(el) {
var xPos = 0;
var yPos = 0;
while (el) {
if (el.tagName == "BODY") {
// deal with browser quirks with body/window/document and page scroll
var xScroll = el.scrollLeft || document.documentElement.scrollLeft;
var yScroll = el.scrollTop || document.documentElement.scrollTop;
xPos += (el.offsetLeft - xScroll + el.clientLeft);
yPos += (el.offsetTop - yScroll + el.clientTop);
} else {
// for all other non-BODY elements
xPos += (el.offsetLeft - el.scrollLeft + el.clientLeft);
yPos += (el.offsetTop - el.scrollTop + el.clientTop);
}
el = el.offsetParent;
}
return {
x: xPos,
y: yPos
};
}
.container {
position: relative;
cursor: "crosshair";
}
#dot {
position: absolute;
top: 0;
left: 0;
width: 10px;
height: 10px;
display: inline-block;
background-color: red;
transform: translate(100, 0);
}
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<div class="container">
<img width="200px" alt="" src="https://img.rawpixel.com/s3fs-private/rawpixel_images/website_content/upwk62143495-wikimedia-image.jpg?w=800&dpr=1&fit=default&crop=default&q=65&vib=3&con=3&usm=15&bg=F4F4F3&ixlib=js-2.2.1&s=218f80fbd029cd0fa69b8597ef4928c0" />
<span id="dot" />
</div>
</body>
</html>
Codepen
Your mouse click position (e.clientX and e.clientY) is relative to your browser's top-left corner that's why your click position is not accurate. You can study the details explanation in this article.
Move Element to Click Position
You need to stop the dot from stopping the click going through to the image.
You can use pointer-events for that.
Here's a simple example:
.container {
position relative;
display: inline-block;
width: 30vmin;
height: 30vmin;
}
img {
position: relative;
width: 100%;
height: 100%;
object-fit: cover;
}
.dot {
background: red;
width: 30px;
height: 30px;
border-radius: 50%;
position: absolute;
top: 10%;
left: 10%;
pointer-events: none;
}
<div class="container"><img onclick="alert('I saw the click');" src="https://picsum.photos/id/1015/300/300">
<div class="dot"></div>
</div>

How to use negative padding in css

I want to add negative padding in css, I have written a small code of battery charging cell. What I want is if I enter value in negative like -1px than the cell color should move to the left side and div should stay in center.
.cell {
width: 100px;
height: 30px;
border: 1px solid black;
}
.padding {
background-color: #3D9970;
width: 10px;
float: left;
height: 30px;
position: absolute;
left: 55px;
padding-right: 1px;
}
<div class="cell">
<div class="cell1"></div>
<div class="padding"></div><span style="display: inline;">
</div>
Please help me.
You can't.
See the specification:
Unlike margin properties, values for padding values cannot be negative.
I think you can achieve the same effect with pseudo elements:
.cell{
display:block;
width: 100px;
height: 30px;
position:relative;
}
.cell:before{
content:'';
background-color: #3D9970;
width: 10px;
top:0;
left:calc(50% - 5px);
height: 100%;
position: absolute;
}
.cell:after{
content:'';
border: 1px solid black;
width:100%;
height:100%;
display:block;
top:0;
left: 0px;
position: absolute;
}
<div class="cell">
</div>
"Left" property could be negative, so if you change it you can move the position of the green rectangle in the middle (.cell:before) of the block and border itself (.after)
The easiest way is to use an absolute positioning relatively to a parent node. Here the parent node would be the battery "housing".
So you can set the position CSS value of the rot div to relative, and then the charge one to absolute. Indeed, according to MDN Webdocs:
absolute: [...] It is positioned relative to its closest positioned ancestor, if any.
Then, you just have to play with the left and width CSS properties. For the "middle" case, I chose to display one border.
Below a working snippet. Just click the "Begin the charge variation" button to start the show.
var chargeElement = document.getElementById("charge");
// To set a charge to the battery, simply call: setCharge(percentage)
function setCharge(percentage) {
var left;
var width;
if (percentage > 100) percentage = 100;
if (percentage < 0) percentage = 0;
chargeElement.setAttribute("data-value", percentage);
// If the charge is 50%, simply draw a line
if (percentage == 50) {
chargeElement.className = "middle";
} else {
chargeElement.className = "";
}
// Otherwise, adjust left and width values
if (percentage >= 50) {
left = 50;
width = percentage - left;
} else {
left = percentage;
width = 50 - left;
}
// Then update the charge style.
chargeElement.style.left = left + "%";
chargeElement.style.width = width + "%";
}
// A simple function to add / remove some charge
function addCharge(percentage) {
var value = parseInt(chargeElement.getAttribute("data-value"));
value += percentage;
setCharge(value);
}
// Here just some stuff for illustration.
// You don't need those functions to set the charge.
function letsBeginTheShow(buttonElement) {
buttonElement.disabled = true;
setNextCharge(10);
}
function setNextCharge(increment) {
var percentage = parseInt(chargeElement.getAttribute("data-value"))
percentage += increment;
if (percentage > 100) {
percentage = 100;
increment = -5;
}
if (percentage < 0) {
percentage = 0;
increment = 5;
}
setCharge(percentage);
setTimeout(function() {
setNextCharge(increment);
}, 50);
}
setCharge(50);
.battery {
position: relative;
width: 100px;
height: 30px;
border: 1px solid black;
/* Below : only for aestethic reasons */
float: left;
margin-right: 30px;
/* End of aesthethic stuff */
}
#charge {
height: 100%;
position: absolute;
background-color: #3D9970;
border-color: #3D9970;
}
.middle {
border-left: 1px solid;
}
<div class="battery">
<div id="charge" data-value="50" class="middle"></div>
</div>
<button onclick="letsBeginTheShow(this)">Begin the charge variation</button>

Transition to full Window (not screen)

I have a report page, where I have my menus, my headers, footers, etc. However I would like to have an option that the report content can be enlarged to full window size (not full screen) with a transition. I'm experimenting with this example:
https://www.w3schools.com/howto/tryit.asp?filename=tryhow_css_zoom_hover
My main problem is I can't make it transition the movement too, not just the enlargement. It instantly jumps to the top left corner without any transition, while the 100% width and 100% height transition works.
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
* {
box-sizing: border-box;
}
.zoom {
background-color: green;
width: 200px;
height: 200px;
margin: auto;
}
.zoom:hover {
transition: all 1s;
top: 0;
left: 0;
position: fixed;
width: 100%;
height: 100%;
}
</style>
</head>
<body>
<h1>Zoom on Hover</h1>
<p>Hover over the div element.</p>
<div class="zoom"></div>
</body>
</html>
I've been searching for a solution, however most of the results are regarding full screen, and not full window.
By default the position property of .zoom is static, transition is not able to handle change of display type.
So you may need to set position: absolute; for .zoom and preset the position.
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
* {
box-sizing: border-box;
}
.zoom {
position: absolute;
top: 120px;
left: 120px;
background-color: green;
width: 200px;
height: 200px;
}
.zoom:hover {
transition: all 1s;
top: 0;
left: 0;
width: 100%;
height: 100%;
}
</style>
</head>
<body>
<h1>Zoom on Hover</h1>
<p>Hover over the div element.</p>
<div class="zoom"></div>
</body>
</html>
The issue is that you are changing the position to fixed and your top/left values are immediately considering thus the jump. Also I don't think there is a CSS solution to have a transition from the static position to the fixed position by specifying top/left only on hover. The rule of transtion is to have an initial value and a final value.
An idea here is to rely on some JS in order to set a the intial value of top/left values and allow the transition to work fine:
function getPosition(element) {
var xPosition = 0,
yPosition = 0;
while (element) {
xPosition += (element.offsetLeft + element.clientLeft);
yPosition += (element.offsetTop + element.clientTop);
element = element.offsetParent;
}
return {
x: (xPosition - document.documentElement.scrollLeft || document.body.scrollLeft),
y: (yPosition - document.documentElement.scrollTop || document.body.scrollTop)
};
}
var e=document.querySelector('.zoom');
var pos = getPosition(e);
e.style.left=pos.x+ 'px';
e.style.top=pos.y + 'px';
* {
box-sizing: border-box;
}
.zoom {
background-color: green;
width: 200px;
height: 200px;
margin: auto;
}
.zoom:hover {
transition: all 1s;
top: 0!important;
left: 0!important;
position: fixed;
width: 100%;
height: 100%;
}
<h1>Zoom on Hover</h1>
<p>Hover over the div element.</p>
<div class="zoom"></div>
To be more accurate you need to adjust the values on the window scroll and window resize:
function getPosition(element) {
var xPosition = 0,
yPosition = 0;
while (element) {
xPosition += (element.offsetLeft + element.clientLeft);
yPosition += (element.offsetTop + element.clientTop);
element = element.offsetParent;
}
return {
x: (xPosition - document.documentElement.scrollLeft || document.body.scrollLeft),
y: (yPosition - document.documentElement.scrollTop || document.body.scrollTop)
};
}
var e = document.querySelector('.zoom');
var pos = getPosition(e);
e.style.left = pos.x + 'px';
e.style.top = pos.y + 'px';
window.addEventListener('scroll', function() {
var pos = getPosition(e);
e.style.left = pos.x + 'px';
e.style.top = pos.y + 'px';
});
window.addEventListener('resize', function() {
var pos = getPosition(e);
e.style.left = pos.x + 'px';
e.style.top = pos.y + 'px';
});
* {
box-sizing: border-box;
}
.zoom {
background-color: green;
width: 200px;
height: 200px;
margin: auto;
}
.zoom:hover {
transition: all 1s;
top: 0!important;
left: 0!important;
position: fixed;
width: 100%;
height: 100%;
}
<h1>Zoom on Hover</h1>
<p>Hover over the div element.</p>
<div class="zoom"></div>

CSS position elements on the outside of a circle [duplicate]

How can I position several <img> elements into a circle around another and have those elements all be clickable links as well? I want it to look like the picture below, but I have no idea how to achieve that effect.
Is this even possible?
2020 solution
Here's a more modern solution I use these days.
I start off by generating the HTML starting from an array of images. Whether the HTML is generated using PHP, JS, some HTML preprocessor, whatever... this matters less as the basic idea behind is the same.
Here's the Pug code that would do this:
//- start with an array of images, described by url and alt text
- let imgs = [
- {
- src: 'image_url.jpg',
- alt: 'image alt text'
- } /* and so on, add more images here */
- ];
- let n_imgs = imgs.length;
- let has_mid = 1; /* 0 if there's no item in the middle, 1 otherwise */
- let m = n_imgs - has_mid; /* how many are ON the circle */
- let tan = Math.tan(Math.PI/m); /* tangent of half the base angle */
.container(style=`--m: ${m}; --tan: ${+tan.toFixed(2)}`)
- for(let i = 0; i < n_imgs; i++)
a(href='#' style=i - has_mid >= 0 ? `--i: ${i}` : null)
img(src=imgs[i].src alt=imgs[i].alt)
The generated HTML looks as follows (and yes, you can write the HTML manually too, but it's going to be a pain to make changes afterwards):
<div class="container" style="--m: 8; --tan: 0.41">
<a href='#'>
<img src="image_mid.jpg" alt="alt text"/>
</a>
<a style="--i: 1">
<img src="first_img_on_circle.jpg" alt="alt text"/>
</a>
<!-- the rest of those placed on the circle -->
</div>
In the CSS, we decide on a size for the images, let's say 8em. The --m items are positioned on a circle and it's if they're in the middle of the edges of a polygon of --m edges, all of which are tangent to the circle.
If you have a hard time picturing that, you can play with this interactive demo which constructs the incircle and circumcircle for various polygons whose number of edges you pick by dragging the slider.
This tells us that the size of the container must be twice the radius of the circle plus twice half the size of the images.
We don't yet know the radius, but we can compute it if we know the number of edges (and therefore the tangent of half the base angle, precomputed and set as a custom property --tan) and the polygon edge. We probably want the polygon edge to be a least the size of the images, but how much we leave on the sides is arbitrary. Let's say we have half the image size on each side, so the polygon edge is twice the image size. This gives us the following CSS:
.container {
--d: 6.5em; /* image size */
--rel: 1; /* how much extra space we want between images, 1 = one image size */
--r: calc(.5*(1 + var(--rel))*var(--d)/var(--tan)); /* circle radius */
--s: calc(2*var(--r) + var(--d)); /* container size */
position: relative;
width: var(--s); height: var(--s);
background: silver /* to show images perfectly fit in container */
}
.container a {
position: absolute;
top: 50%; left: 50%;
margin: calc(-.5*var(--d));
width: var(--d); height: var(--d);
--az: calc(var(--i)*1turn/var(--m));
transform:
rotate(var(--az))
translate(var(--r))
rotate(calc(-1*var(--az)))
}
img { max-width: 100% }
See the old solution for an explanation of how the transform chain works.
This way, adding or removing an image from the array of images automatically arranges the new number of images on a circle such that they're equally spaced out and also adjusts the size of the container. You can test this in this demo.
OLD solution (preserved for historical reasons)
Yes, it is very much possible and very simple using just CSS. You just need to have clear in mind the angles at which you want the links with the images (I've added a piece of code at the end just for showing the angles whenever you hover one of them).
You first need a wrapper. I set its diameter to be 24em (width: 24em; height: 24em; does that), you can set it to whatever you want. You give it position: relative;.
You then position your links with the images in the center of that wrapper, both horizontally and vertically. You do that by setting position: absolute; and then top: 50%; left: 50%; and margin: -2em; (where 2em is half the width of the link with the image, which I've set to be 4em - again, you can change it to whatever you wish, but don't forget to change the margin in that case).
You then decide on the angles at which you want to have your links with the images and you add a class deg{desired_angle} (for example deg0 or deg45 or whatever). Then for each such class you apply chained CSS transforms, like this:
.deg{desired_angle} {
transform: rotate({desired_angle}) translate(12em) rotate(-{desired_angle});
}
where you replace {desired_angle} with 0, 45, and so on...
The first rotate transform rotates the object and its axes, the translate transform translates the object along the rotated X axis and the second rotate transform brings back the object into position.
The advantage of this method is that it is flexible. You can add new images at different angles without altering the current structure.
CODE SNIPPET
.circle-container {
position: relative;
width: 24em;
height: 24em;
padding: 2.8em;
/*2.8em = 2em*1.4 (2em = half the width of a link with img, 1.4 = sqrt(2))*/
border: dashed 1px;
border-radius: 50%;
margin: 1.75em auto 0;
}
.circle-container a {
display: block;
position: absolute;
top: 50%; left: 50%;
width: 4em; height: 4em;
margin: -2em;
}
.circle-container img { display: block; width: 100%; }
.deg0 { transform: translate(12em); } /* 12em = half the width of the wrapper */
.deg45 { transform: rotate(45deg) translate(12em) rotate(-45deg); }
.deg135 { transform: rotate(135deg) translate(12em) rotate(-135deg); }
.deg180 { transform: translate(-12em); }
.deg225 { transform: rotate(225deg) translate(12em) rotate(-225deg); }
.deg315 { transform: rotate(315deg) translate(12em) rotate(-315deg); }
<div class='circle-container'>
<a href='#' class='center'><img src='image.jpg'></a>
<a href='#' class='deg0'><img src='image.jpg'></a>
<a href='#' class='deg45'><img src='image.jpg'></a>
<a href='#' class='deg135'><img src='image.jpg'></a>
<a href='#' class='deg180'><img src='image.jpg'></a>
<a href='#' class='deg225'><img src='image.jpg'></a>
<a href='#' class='deg315'><img src='image.jpg'></a>
</div>
Also, you could further simplify the HTML by using background images for the links instead of using img tags.
EDIT: example with fallback for IE8 and older (tested in IE8 and IE7)
Here is the easy solution without absolute positioning:
.container .row {
margin: 20px;
text-align: center;
}
.container .row img {
margin: 0 20px;
}
<div class="container">
<div class="row">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
</div>
<div class="row">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
</div>
<div class="row">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
<img src="https://ssl.gstatic.com/s2/oz/images/faviconr2.ico" alt="" width="64" height="64">
</div>
</div>
http://jsfiddle.net/mD6H6/
Using the solution proposed by #Ana:
transform: rotate(${angle}deg) translate(${radius}px) rotate(-${angle}deg)
I created the following jsFiddle that places circles dynamically using plain JavaScript (jQuery version also available).
The way it works is rather simple:
document.querySelectorAll( '.ciclegraph' ).forEach( ( ciclegraph )=>{
let circles = ciclegraph.querySelectorAll( '.circle' )
let angle = 360-90, dangle = 360 / circles.length
for( let i = 0; i < circles.length; ++i ){
let circle = circles[i]
angle += dangle
circle.style.transform = `rotate(${angle}deg) translate(${ciclegraph.clientWidth / 2}px) rotate(-${angle}deg)`
}
})
.ciclegraph {
position: relative;
width: 500px;
height: 500px;
margin: calc(100px / 2 + 0px);
}
.ciclegraph:before {
content: "";
position: absolute;
top: 0; left: 0;
border: 2px solid teal;
width: calc( 100% - 2px * 2);
height: calc( 100% - 2px * 2 );
border-radius: 50%;
}
.ciclegraph .circle {
position: absolute;
top: 50%; left: 50%;
width: 100px;
height: 100px;
margin: calc( -100px / 2 );
background: teal;
border-radius: 50%;
}
<div class="ciclegraph">
<div class="circle"></div>
<div class="circle"></div>
<div class="circle"></div>
<div class="circle"></div>
<div class="circle"></div>
<div class="circle"></div>
</div>
Building off #Ana's excellent answer, I created this dynamic version that allows you to add and remove elements from the DOM and maintain proportionate spacing between the elements - check out my fiddle: https://jsfiddle.net/skwidbreth/q59s90oy/
var list = $("#list");
var updateLayout = function(listItems) {
for (var i = 0; i < listItems.length; i++) {
var offsetAngle = 360 / listItems.length;
var rotateAngle = offsetAngle * i;
$(listItems[i]).css("transform", "rotate(" + rotateAngle + "deg) translate(0, -200px) rotate(-" + rotateAngle + "deg)")
};
};
$(document).on("click", "#add-item", function() {
var listItem = $("<li class='list-item'>Things go here<button class='remove-item'>Remove</button></li>");
list.append(listItem);
var listItems = $(".list-item");
updateLayout(listItems);
});
$(document).on("click", ".remove-item", function() {
$(this).parent().remove();
var listItems = $(".list-item");
updateLayout(listItems);
});
#list {
background-color: blue;
height: 400px;
width: 400px;
border-radius: 50%;
position: relative;
}
.list-item {
list-style: none;
background-color: red;
height: 50px;
width: 50px;
position: absolute;
top: 50%;
left: 50%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<ul id="list"></ul>
<button id="add-item">Add item</button>
Here is a version I made in React from the examples here.
CodeSandbox Example
import React, { useRef, useEffect } from "react";
import "./styles.css";
export default function App() {
const graph = useRef(null);
useEffect(() => {
const ciclegraph = graph.current;
const circleElements = ciclegraph.childNodes;
let angle = 360 - 90;
let dangle = 360 / circleElements.length;
for (let i = 0; i < circleElements.length; i++) {
let circle = circleElements[i];
angle += dangle;
circle.style.transform = `rotate(${angle}deg) translate(${ciclegraph.clientWidth /
2}px) rotate(-${angle}deg)`;
}
}, []);
return (
<div className="App">
<div className="ciclegraph" ref={graph}>
<div className="circle" />
<div className="circle" />
<div className="circle" />
<div className="circle" />
<div className="circle" />
<div className="circle" />
</div>
</div>
);
}
You can certainly do it with pure css or use JavaScript. My suggestion:
If you already know that the images number will never change just calculate your styles and go with plain css (pros: better performances, very reliable)
If the number can vary either dynamically in your app or just may vary in the future go with a Js solution (pros: more future-proof)
I had a similar job to do, so I created a script and open sourced it here on Github for anyone who might need it. It just accepts some configuration values and simply outputs the CSS code you need.
If you want to go for the Js solution here's a simple pointer that can be useful to you. Using this html as a starting point being #box the container and .dot the image/div in the middle you want all your other images around:
Starting html:
<div id="box">
<div class="dot"></div>
<img src="my-img.jpg">
<!-- all the other images you need-->
</div>
Starting Css:
#box{
width: 400px;
height: 400px;
position: relative;
border-radius: 100%;
border: 1px solid teal;
}
.dot{
position: absolute;
border-radius: 100%;
width: 40px;
height: 40px;
left: 50%;
top: 50%;
margin-left: -20px;
margin-top: -20px;
background: rebeccapurple;
}
img{
width: 40px;
height: 40px;
position: absolute;
}
You can create a quick function along these lines:
var circle = document.getElementById('box'),
imgs = document.getElementsByTagName('img'),
total = imgs.length,
coords = {},
diam, radius1, radius2, imgW;
// get circle diameter
// getBoundingClientRect outputs the actual px AFTER transform
// using getComputedStyle does the job as we want
diam = parseInt( window.getComputedStyle(circle).getPropertyValue('width') ),
radius = diam/2,
imgW = imgs[0].getBoundingClientRect().width,
// get the dimensions of the inner circle we want the images to align to
radius2 = radius - imgW
var i,
alpha = Math.PI / 2,
len = imgs.length,
corner = 2 * Math.PI / total;
// loop over the images and assign the correct css props
for ( i = 0 ; i < total; i++ ){
imgs[i].style.left = parseInt( ( radius - imgW / 2 ) + ( radius2 * Math.cos( alpha ) ) ) + 'px'
imgs[i].style.top = parseInt( ( radius - imgW / 2 ) - ( radius2 * Math.sin( alpha ) ) ) + 'px'
alpha = alpha - corner;
}
You can see a live example here
There is no way to magically place clickable items in a circle around another element with CSS.
The way how I would do this is by using a container with position:relative;. And then place all the elements with position:absolute; and using top and left to target it's place.
Even though you haven't placed jquery in your tags it might be best to use jQuery / javascript for this.
First step is placing your center image perfectly in the center of the container using position:relative;.
#centerImage {
position:absolute;
top:50%;
left:50%;
width:200px;
height:200px;
margin: -100px 0 0 -100px;
}
After that you can place the other elements around it by using an offset() of the centerImage minus the offset() of the container. Giving you the exact top and left of the image.
var left = $('#centerImage').offset().left - $('#centerImage').parent().offset().left;
var top = $('#centerImage').offset().top - $('#centerImage').parent().offset().top;
$('#surroundingElement1').css({
'left': left - 50,
'top': top - 50
});
$('#surroundingElement2').css({
'left': left - 50,
'top': top
});
$('#surroundingElement3').css({
'left': left - 50,
'top': top + 50
});
What I've done here is placing the elements relative to the centerImage. Hope this helps.
You could do it like this: fiddle
Don't mind the positioning, its a quick example
The first step is to have 6 long columnar boxes:
The second step is to use position: absolute and move them all into the middle of your container:
And now rotate them around the pivot point located at the bottom center. Use :nth-child to vary rotation angles:
div {
transform-origin: bottom center;
#for $n from 0 through 7 {
&:nth-child(#{$n}) {
rotate: (360deg / 6) * $n;
}
}
Now all you have to do is to locate your images at the far end of every column, and compensate the rotation with an anti-rotation :)
Full source:
<div class="flower">
<div class="petal">1</div>
<div class="petal">2</div>
<div class="petal">3</div>
<div class="petal">4</div>
<div class="petal">5</div>
<div class="petal">6</div>
</div>
.flower {
width: 300px;
height: 300px;
// We need a relative position
// so that children can have "position:abolute"
position: relative;
.petal {
// Make sure petals are visible
border: 1px solid #999;
// Position them all in one point
position: absolute; top: 0; left: 50%;
display: inline-block;
width: 30px; height: 150px;
// Rotation
transform-origin: bottom center;
#for $n from 0 through 7 {
&:nth-child(#{$n}) {
// Petal rotation
$angle: (360deg / 6) * $n;
rotate: $angle;
// Icon anti-rotation
.icon { rotate: -$angle; }
}
}
}
}
See CodePen

HTML5 <div> centered inside <body>

Is there a way to place a div inside body, centered, with given left-right margins equal to x and top-bottom margins, equal to y? Nothing except of the div (and its children) is presented in the document.
UPDATE. I want the following:
Also, I'd be glad to have a more common solution for the case, when x1 != x2, y1 != y2 (though a solution for my particular case x1==x2, y1==y2 is appreciated).
Better solution(?):
Set margin-left and margin-right for the div to "auto"
You can use fixed positioning. It won’t work in IE6, though.
<!DOCTYPE html>
<html xmlns='http://www.w3.org/1999/xhtml' xml:lang='de' lang='de'>
<head>
<meta charset='utf-8' />
<title>Test</title>
<style>
#bla {
position: fixed;
top: 30px;
left: 60px;
right: 60px;
bottom: 30px;
background: yellow;
}
</style>
</head>
<body>
<div id='blah'>
</div>
</body>
</html>
See it in action: http://obda.net/stackoverflow/position-fixed.html
The best I can do without CSS3 is to use two divs.
html {
width: 100%;
height: 100%;
}
body {
position: relative;
width: 100%;
height: 100%;
margin: 0;
padding: 0;
}
div.parent {
display: inline-block;
position: relative;
left: 50%;
top: 50%;
}
div.child {
width: 100px;
margin-left: -50%;
margin-top: -50%;
border: 1px solid #000;
}
You can see it here: http://jsfiddle.net/CatChen/VGpdv/4/
Update: If CSS3 implementation is acceptable, it's a lot easier:
http://www.html5rocks.com/en/tutorials/flexbox/quick/#toc-center
You will have to use javascript if you want the margins to be the same in all browzers.
<body>
<div id="the_div" style="margin: 20 auto;margin-bottom:0;width:300px;">
</div>
<script type="text/javascript">
var dim = (function () {
var _pW, _pH;
if (document.body && document.body.offsetWidth) {
_pW = document.body.offsetWidth;
_pH = document.body.offsetHeight;
}
if (document.compatMode == 'CSS1Compat' &&
document.documentElement && document.documentElement.offsetWidth) {
_pW = document.documentElement.offsetWidth;
_pH = document.documentElement.offsetHeight;
}
if (window.innerWidth && window.innerHeight) {
_pW = window.innerWidth;
_pH = window.innerHeight;
}
return { width : _pW, height : _pH };
})();
var div = document.getElementById( "the_div" );
div.style.height = dim.height - 20 + "px";
</script>
<body>