I'm creating a table that can count all 'abnormal' data from three columns and sum those columns as the total.
SELECT
COUNT(CASE WHEN p_eyes <> 'Normal' THEN 1 END) AS 'abnormalEyes',
COUNT(CASE WHEN p_ears <> 'Normal' THEN 1 END) AS 'abnormalEars',
COUNT(CASE WHEN p_nose <> 'Normal' THEN 1 END) AS 'abnormalNose'
FROM student_physical_record_exam_grade_eleven;
This will count all the not 'Normal' from those three columns.
Is there any way I can total those three columns as 'Eyes/Ears/Nose'?
If you want to just sum these results, you could add them. The easiest way of doing this is with a subquery:
SELECT *, abnormalEyes + abnormalEars + abnormalNose AS totalAbnormal
FROM (SELECT COUNT(CASE WHEN p_eyes <> 'Normal' THEN 1 END) AS abnormalEyes,
COUNT(CASE WHEN p_ears <> 'Normal' THEN 1 END) AS abnormalEars,
COUNT(CASE WHEN p_nose <> 'Normal' THEN 1 END) AS abnormalNose
FROM student_physical_record_exam_grade_eleven) t
Related
I have a table in my database from which i want to fetch data on the basis of count
my table name is syncbill and columns are Cancelled and Noofprints i am trying to write a query to fetch the count of cancelled and count of noofbills using single query
For cancelled i want to fetch count of cancelled where cancelled<>Y
for Noofprints i want to fetch count of noofprints where noofprints>1
I am using
select count(CANCELLED) as canceledbill,count(NOOFPRINTS) as duplicatebill
from syncbill where CANCELLED<>'Y' and NOOFPRINTS>1`
this query but it is giving me the same no of counts for both
any one out-here please guide me
you can use sum() with case expreseeion
SELECT
sum(CASE WHEN CANCELLED <> 'Y' THEN 1 else 0 END) AS canceledbill,
sum(CASE WHEN NOOFPRINTS > 1 THEN 1 else 0 END) AS duplicatebill
FROM table_name;
Use conditional aggregation:
SELECT
COUNT(CASE WHEN CANCELLED <> 'Y' THEN 1 END) AS cancelledbill,
COUNT(CASE WHEN NOOFPRINTS > 1 THEN 1 END) AS duplicatebill
FROM yourTable;
If you are actually using MySQL, then the above can be simplified to this:
SELECT
SUM(CANCELLED <> 'Y') AS cancelledbill,
SUM(NOOFPRINTS > 1) AS duplicatebill
FROM yourTable;
USE CASE WHEN Expression
select
sum(case when CANCELLED <> 'Y' then 1 else 0 end) AS cancelledbill,
sum(case when NOOFPRINTS > 1 then 1 else 0 end) AS duplicatebill
FROM tablename;
I am new in sql. I want to count something like:
Select count(*) from table where col1= x and col2=x and Col3=x.
I need to count the same value in all different column.
Any help will be appreciated.
You can use conditional aggregation :
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab;
If you want to have sum of these count values, consider the above query as an inner and use the following :
Select q.*,
q.count_col1 + q.count_col2 + q.count_col3 whole_sum
from
(
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab
) q
Rextester Demo
This question already has answers here:
Is there an alternative to TOP in MySQL?
(4 answers)
Closed 6 years ago.
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
How get TOP 100 rows from this query which have max count type = 'yes' ?
You can use LIMIT to limit the number of results and use an ORDER BY to order it so the results are in descending order of total.
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
ORDER BY type_1 DESC
LIMIT 100
You should add WHERE statement to your query to add conditional statement
Also, I can see that you are using mysql, so that means you should order your data by argument descending and limit result to 100
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
WHERE type='yes'
GROUP by user_id
ORDER BY total DESC
LIMIT 100
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
ORDER by type_1 DESC
LIMIT 100
I'm using CASE to categorize data in the table and count them but the results aren't accurate
live demo [here]
select DATE(date) as day, count(*),
count(distinct case when name = 'fruit' then 1 else 0 end) as fruits,
count(distinct case when name = 'vege' then 1 else 0 end) as vege,
count(distinct case when name = 'sweets' then 1 else 0 end) as sweets
from food
group by day
with rollup
I'm not sure if the issue is with CASE or in the string matching = because there's no 'sweets' still it counts 1?
any pointers I'd be grateful
Your problem is that COUNT counts every result that is not NULL. In your case you are using:
COUNT(distinct case when name = 'sweets' then 1 else 0 end)
So, when the name is not sweets, it counts the 0. Furthermore, since you are using DISTINCT, it counts just one or two values. You should either use SUM or remove the DISTINCT and the ELSE 0:
SELECT DATE(date) as day,
COUNT(*),
SUM(CASE WHEN name = 'fruit' THEN 1 ELSE 0 END) as fruits,
SUM(CASE WHEN name = 'vege' THEN 1 ELSE 0 END) as vege,
SUM(CASE WHEN name = 'sweets' THEN 1 ELSE 0 END) as sweets
FROM food
GROUP BY DAY
WITH ROLLUP
Or:
SELECT DATE(date) as day,
COUNT(*),
COUNT(CASE WHEN name = 'fruit' THEN 1 ELSE NULL END) as fruits,
COUNT(CASE WHEN name = 'vege' THEN 1 ELSE NULL END) as vege,
COUNT(CASE WHEN name = 'sweets' THEN 1 ELSE NULL END) as sweets
FROM food
GROUP BY DAY
WITH ROLLUP
Here is a modified sqlfiddle.
You can't group by an alias. You have to group by the expression.
group by date(date)
You can group on an Alias:
SELECT
FROM_UNIXTIME(UnixTimeField, '%Y') AS 'Year'
,FROM_UNIXTIME(UnixTimeField, '%m') AS 'Month'
FROM table p
GROUP BY Year, Month
I have two queries:
select count(*) from my_table where status="accepted"
and
select count(*) from my_table where status="rejected"
I was to find the ratio of accepted/reject so I Was wondering if it's possible to combine the two queries so I don't have to execute two queries
Putting this answer since none offered so far is correct
select count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
If you also need the individual counts
select count(case when status = "accepted" then 1 end) Accepted,
count(case when status = "rejected" then 1 end) Rejected,
count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
Note: MySQL does not have a divide by zero problem. It returns NULL when Rejected is 0.
select accepted_count, rejected_count, accepted_count/rejected_count ratio
from (
select sum(CASE WHEN status="accepted" THEN 1 ELSE 0 END) accepted_count,
sum(CASE WHEN status="rejected" THEN 1 ELSE 0 END) rejected_count
from my_table
) A
I think this will work:
SELECT (Select count(*) from my_table where status="accepted") / (select count(*) from my_table where status="rejected") AS ratio
select status, count(*) from my_table
where status in ("rejected", "accepted")
group by status;
select sum(case when status='accepted' then 1 else 0 end) as AcceptedCount,
sum(case when status='rejected' then 1 else 0 end) as RejectedCount
from my_table