I have a database in which each record has a rank and is associated to a certain group.
Also, there is a target number of IDs for each group.
I need to select this target number in each group with the highest ranked records.
This is an example of this data:
Group Id Rank
--------------------------------
GUADALAJARA 1 356
GUADALAJARA 2 387
PUEBLA 3 431
TIJUANA 4 315
PUEBLA 5 315
MONTERREY 6 315
MONTERREY 7 263
PUEBLA 8 356
PUEBLA 9 447
GUADALAJARA 10 356
MONTERREY 11 356
TIJUANA 12 447
PUEBLA 13 356
PUEBLA 14 387
MONTERREY 15 431
MONTERREY 16 412
MONTERREY 17 447
TIJUANA 18 263
And the targets for each group are:
Group Records Goal
----------------------------
GUADALAJARA 4 2
MONTERREY 6 3
PUEBLA 6 3
TIJUANA 3 2
For example, group Guadalajara has 4 records , and I need to select the first two highest-ranked which would be 100630487 and 133255369:
ID Rank
----------------
100630487 447
133255369 387
138314098 356
114194869 356
I will appreciate any ideas to make this query.
Related
I have 3 tables, and a query:
SELECT
DISTINCT assistent.id as id,
name,
events.client as client,
assistentprice.id as priceid,
value
FROM
`assistents`
LEFT JOIN `events` ON assistents.id = events.assistent
LEFT JOIN `assistentprice` ON assistents.id = assistentprice.id_assistente
ORDER BY
name
I got a result like:
id
name
client
priceid
value
88
MARK
44
12
7.00
88
MARK
27
14
8.00
88
MARK
44
15
11.00
88
MARK
27
11
10.00
88
MARK
44
10
9.00
16
OSCAR
49
21
8.00
16
OSCAR
14
23
9.00
16
OSCAR
14
22
7.00
16
OSCAR
49
19
9.00
So, table is ordered by name, but i want to see also ordered/grouped client for every assistent. For exampe, for Mark it have to be:
id
name
client
priceid
value
88
MARK
27
12
7.00
88
MARK
27
14
8.00
88
MARK
44
15
11.00
88
MARK
44
11
10.00
How can i do this?
my table look like following
id person counter
1 Ona 4946
2 Mayra 15077
3 Claire 496
4 Rita 13929
5 Demond 579
6 Winnifred 13580
7 Green 1734
8 Jacquelyn 19092
9 Aisha 5572
10 Kian 8826
11 Alexandrea 7514
12 Dalton 14151
13 Rossie 18403
14 Carson 19537
15 Mason 2022
16 Emie 2394
17 Jonatan 6655
18 June 5037
19 Jazmyn 10856
20 Mittie 18928
here is the fiddle
i would like to select the top 5 by counter and group by first character, here is the sql that i tried:
SELECT SUBSTR(person,1,1) AS Alpha, person, counter
FROM myTable
GROUP BY SUBSTR(person,1,1)
ORDER BY SUBSTR(person,1,1) ASC, counter DESC;
how to select desired result as following:
alpha person counter
a Arvid 9236
a Aisha 5572
a Alf 4000
a Ahmad 3500
a Alvin 2100
b Brandon 13000
b Ben 8230
b Bonny 7131
b Bella 4120
b Bun 1200
c Connie 9320
c Calvin 8310
c Camalia 6123
c Cimon 3419
c Clay 2515
im using mysql 8.0
You can do:
select *
from (
select *, row_number() over(partition by substr(person, 1, 1)
order by counter desc) as rn
from myTable
) x
where rn <= 5
order by substr(person, 1, 1), rn
Result:
id person counter rn
---- ---------- -------- --
153 Alf 19758 1
283 Alycia 19706 2
260 Abe 19463 3
223 Assunta 18808 4
300 Ari 18031 5
210 Bennie 18309 1
159 Barry 18281 2
128 Beulah 18080 3
314 Benny 16795 4
474 Barry 15789 5
342 Casandra 19656 1
14 Carson 19537 2
67 Chaim 19429 3
280 Colin 18507 4
500 Corbin 18433 5
380 Daphney 19138 1
234 Dejah 18781 2
241 Derrick 18722 3
49 Dasia 18562 4
312 Darrel 17903 5
163 Evalyn 19847 1
79 Ernestine 19523 2
344 Emilie 19520 3
371 Eva 19119 4
469 Emma 18403 5
140 Fiona 19522 1
216 Flo 18314 2
356 Frieda 16082 3
254 Floy 15942 4
54 Florencio 12739 5
447 Geoffrey 19858 1
327 Geoffrey 19223 2
335 Grant 19100 3
454 Giuseppe 16175 4
83 Gardner 15235 5
373 Hilario 19507 1
35 Hanna 19276 2
200 Halle 18150 3
491 Hailee 17521 4
411 Hermann 17018 5
21 Idella 7440 1
177 Izabella 5536 2
115 Isai 4164 3
412 Izabella 2112 4
275 Imani 573 5
195 Joannie 19374 1
8 Jacquelyn 19092 2
48 Jalon 18861 3
251 Jamie 18768 4
367 Joanny 17600 5
282 Kendra 19278 1
421 Kendra 19213 2
363 Kaylin 18977 3
96 Kaylie 18423 4
310 Katrine 17754 5
146 Lonzo 19778 1
194 Leonora 18258 2
399 Laurine 16847 3
137 Leslie 16718 4
190 Luther 16318 5
87 Maegan 19112 1
20 Mittie 18928 2
271 Mariana 18149 3
317 Mary 18043 4
305 Maybelle 17666 5
281 Noelia 19203 1
176 Nickolas 19047 2
408 Nelson 15901 3
142 Nasir 13700 4
366 Nicole 10694 5
423 Ova 19759 1
487 Osborne 19539 2
438 Ozella 18911 3
375 Ora 18270 4
414 Onie 17358 5
52 Pascale 19658 1
39 Pearlie 17621 2
364 Price 14177 3
161 Precious 10337 4
294 Paula 9162 5
70 Quincy 18343 1
73 Quincy 16631 2
192 Quentin 13578 3
131 Rodger 19776 1
231 Royal 19033 2
313 Rocky 19008 3
13 Rossie 18403 4
45 Rosanna 15992 5
418 Sydnee 19810 1
470 Sadie 19189 2
123 Shanna 18862 3
485 Savanah 18664 4
302 Steve 16412 5
406 Toney 18283 1
28 Tremaine 16400 2
98 Taurean 15911 3
278 Tremaine 14391 4
311 Treva 14026 5
239 Ubaldo 11630 1
78 Valentina 17736 1
458 Vita 17527 2
170 Vergie 16971 3
158 Vance 15089 4
272 Veronica 12027 5
102 Willis 18155 1
329 Ward 14919 2
156 Westley 14867 3
136 Winnifred 14315 4
6 Winnifred 13580 5
323 Yolanda 17920 1
155 Yesenia 6164 2
402 Zachary 19129 1
37 Zaria 5398 2
See running example at DB Fiddle.
let's say we have records in a table and we would like to be able to order (and reorder them).
the table could look like something like this, see below
id Pos Level parentId
Europe 18 1 0 null
Germany 9 2 1 18
Berlin 2 3 2 9
Frankfurt 20 4 2 9
Stuttgart 23 5 2 9
France 29 6 1 18
Paris 26 7 2 29
Lyon 13 8 2 29
Americas 11 9 0 null
USA 27 10 1 11
New York 22 11 2 27
Manhattan 19 12 3 22
Brooklyn 7 13 3 22
Los Angeles 25 14 2 27
Mexico 6 15 1 11
Canada 4 16 1 11
Montreal 21 17 2 4
Vancouver 3 18 2 4
Asia 8 19 0 null
China 14 20 1 8
Beijing 17 21 2 14
Shenzhen 30 22 2 14
Shanghai 28 23 2 14
Japan 16 24 1 8
Tokyo 1 25 2 16
Shinjuku 15 26 3 1
Oceania 24 27 0 null
Autralia 5 28 1 24
Sydney 10 29 2 5
Africa
12 30 0 null
where id is a unique id (can be anything), position the position of the element in the list, level depth level and parentId parent id (if exists)
Typically I would want the following method:
/**
#param sourceId: id of the element to be moved
#params targetId: id of the element which position needs to be overtaken
#param aboveOrBelow: defines whether the old element (target) will be placed above or below the source element
#return if successful, new position of the source element, if unsuccessful: message explaining why unsuccessful
*/
def move(sourceId: Long, targetId: Long, aboveOrBelow: Boolean = true):Either[Long, String]
what's the most efficient way to implement this or am I missing something? Is there already a built-in mechanism for such operations in (My)SQL?
constraints:
- end user who might be allowed to reorder do not necessarily see all records (e.g. only asian records)
- records can be added and deleted
=== edit ===
i rewrote the structure taking in account suggestions in the comments:
id pos parentId
Europe 18 1 null
Germany 9 1 18
Berlin 2 1 9
Frankfurt 20 2 9
Stuttgart 23 3 9
France 29 2 18
Paris 26 1 29
Lyon 13 2 29
Americas 11 2 null
USA 27 1 11
New York 22 1 27
Manhattan 19 1 22
Brooklyn 7 2 22
Los Angeles 25 2 27
Mexico 6 3 11
Canada 4 4 11
Montreal 21 1 4
Vancouver 3 2 4
Asia 8 3 null
China 14 1 8
Beijing 17 1 14
Shenzhen 30 2 14
Shanghai 28 3 14
Japan 16 2 8
Tokyo 1 1 16
Shinjuku 15 1 1
Oceania 24 4 null
Autralia 5 1 24
Sydney 10 1 5
Africa 12 5 null
And for constructing the tree structure i would use recursive cte as follows. and construct it as a view
with recursive cte(place_name,id,parent_id,level)
as (select place_name,id,parent_id,1 as level
from countries_hierarchy
where parent_id is null
union all
select concat(lpad(' ',a.level+1,' ')
,b.place_name
)
,b.id
,b.parent_id
,a.level+1
from cte a
join countries_hierarchy b
on a.id=b.parent_id
)
select * from cte
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=334820e4e01cf8749c5abcaa447963a0
The table "commissions" is of this form:
affiliate referral amount date
3 2 15 2016-08-27
1 22 10 2016-08-29
4 45 5 2016-09-06
1 33 9 2016-09-08
3 17 4 2016-09-11
2 33 10 2016-09-16
1 9 7 2016-09-26
3 17 9 2016-09-26
2 69 10 2016-09-30
1 21 7 2016-10-01
4 55 2 2016-10-06
I need to find out the ranking of the affiliates with most commissions month to month.
I have tried:
SELECT affiliate, SUM(amount) as amount
FROM commissions
GROUP BY affiliate, YEAR(date), MONTH(date)
But unfortunately it is not throwing the desired results.
Please help.
Dear developers and programmers,
I have a tabel with SHOP_ID, PROD_ID, ipadres and some more tables, but these are where its all about...
Looks like this:
id ip number timestamp shop_id prod_id
--------------------------------------------------
42 81.69.205.25 1319488326 2 3
43 81.205.141.48 1319492649 2 3
44 193.58.10.10 1319520579 14 17
45 84.28.22.226 1319529529 11 19
46 88.15.81.188 1319543745 2 1
47 178.17.241.191 1319563031 14 7
48 87.28.107.171 1319563038 2 6
49 80.156.47.144 1319572818 14 7
50 82.76.241.175 1319577506 11 1
51 82.76.241.175 1319577584 13 1
52 82.76.241.175 1319577785 14 1
53 82.76.241.175 1319577860 4 1
54 62.94.133.153 1319579221 14 1
55 62.94.133.153 1319579281 2 3
56 77.70.175.221 1319617238 11 1
57 77.70.175.221 1319621845 13 1
58 77.70.175.221 1319621848 2 1
59 77.70.175.221 1319621850 11 1
.... more
--------------------------------------------------------
Is there a way to see for each prod_id how many ip numbers there excist for each shop id?
output example
1 2 3 4 5
---------------------------------------------
1 18 5 51 8 4
2 58 5 45 3 4
3 7 6 31 9 2
where horizontal is the prod_id and vertical is the shop_id
I've don this already:
select
shop_id,
count(distinct(ipadres)) amount
from table
GROUP BY shop_id
order by amount desc
but this wil give me only the result of all prod_id's combined.
I would like to have the prod_id's seperate in columns.
I hope there is a solution!
Kind Regards
Try this
select `prod_id`,shop_id,
count(distinct(ipadres)) amount
from table
GROUP BY shop_id,prod_id
order by amount desc