Show exceptions and chttpexceptions in modal yii2 - exception

Hey guys im making an website and i need show an error (exception or chttpexception) when this happens in a modal.
Actually the modal displays empty but the console shows the error.
How i can solve this?
Thanks.
This is what happen now:
https://i.stack.imgur.com/UV61O.png
I need this:
https://i.stack.imgur.com/hPfKi.png
My controller actions:
public function actionMomios($id)
{
$this->findModel(1000); //this number is for the error its an ID
}
This is the function who throws the error:
protected function findModel($id)
{
if (($model = Partido::findOne($id)) !== null) {
return $model;
}
throw new NotFoundHttpException('El partido no se encuentra registrado'); // This is the exception i need to show
}
This is the code who calls the modal (its in a gridview):
'momios' => function($url,$model,$key){
$btn = Html::button("<span class='glyphicon glyphicon-usd'></span>",[
'value'=>Yii::$app->urlManager->createUrl('partido/momios?id='.$key),
'class'=>'momioedit grid-action btn btn-success',
'title'=>'Modificar momios'
]);
return $btn;
},
My modal in the view:
<?php
Modal::begin([
'header' => '<h4>Editar Momio</h4>',
'id' => 'modalmomio',
'size' => 'modal-lg',
]);
echo "<div id='momiocontent'></div>";
Modal::end();
?>
My JS:
$('.momioedit').click(function(){
$('#modalmomio').modal('show')
.find('#momiocontent')
.load($(this).attr('value'));
});

You just need to wrap your code inside a try{}catch(){} block inside the actionMomios($id) that calls the findModel() method like below.
public function actionMomios($id)
{
try{
$this->findModel(1000); //this number is for the error its an ID
}catch(\Exception $e){
return $e->getMessage();
}
}

Related

Validation error on custom model attributes not displayed in form

I have a model with the following custom attributes topic_names, topic_details (string fields). I have also a model form with the custom attributes and custom rules. When I insert wrong data in the form fields, there is a model error, but it isn't displayed.
Model code:
......
public function rules()
{
return [
...
[['topics_names','topics_details'],'string'],
[['topics_names'],'checkCorrectAndSetTopics'],
];
}
public function checkCorrectAndSetTopics(){
if($this->topics_names AND $this->topics_details){
$topicsNamesArray = explode(',',$this->topics_names);
$topicsDetailsArray = explode(';',$this->topics_details);
if(sizeof($topicsNamesArray) !== sizeof($topicsDetailsArray)){
$this->addError('topics_names', \Yii::t('app', 'The topics names and details sets have different sizes'));
return FALSE;
}
}
return TRUE;
}
The problem is when the second rules is violeted, the form doesn't show any error, but there is. I checked it debugging the code below.
Form code:
..........
<?php
ActiveForm::$autoIdPrefix = createRandomId();//Function which creates a random id
$form = ActiveForm::begin(
['enableAjaxValidation' => true, "options"=> ["class"=>"extra-form"]]);
?>
<?= $form->errorSummary($model); ?>
<?= $form->field($model, 'topics_names')->textInput()
->label(\Yii::t('app', 'Topics Names'))?>
<?= $form->field($model, 'topics_details')->textarea(['rows' => 6])
->label(\Yii::t('app', 'Topics Details'))?>
........
Controller code:
public function actionAddExtraData($id){
if(!Yii::$app->request->isAjax){
throw new ForbiddenHttpException(\Yii::t('app','Cannot access this action directly.'));
}
$event = $this->findModel($id);
$extraData = ExtraData::find()
->andWhere(['event_id'=>$id])
->one();
if(!$extraData){
$extraData = new ExtraData();
$extraData->event_id = $id;
}else{
$extraData->prePerformForm();//Insert data on custom attributes
}
if(Yii::$app->request->isPost AND Yii::$app->request->isAjax AND Yii::$app->request->post("submitting") != TRUE
AND $extraData->load(Yii::$app->request->post())){
Yii::$app->response->format = Response::FORMAT_JSON;
$validation = ActiveForm::validate($extraData);
return $validation;
}
if ($extraData->load(Yii::$app->request->post()) && $extraData->save()) {
if (Yii::$app->request->isAjax) {
Yii::$app->response->format = Response::FORMAT_JSON;
return ["success" => TRUE];
} else {
return $this->redirect(Yii::$app->request->referrer);
}
}
return $this->renderAjax('_event_extra_form',['model'=>$extraData,'event'=>$event]);
}
First thing, pretty sure you don't need to return true or false, you just need to add error. Second thing, in your example you name the attribute, you can actually get this when defining the function, so your function could look something like this
public function checkCorrectAndSetTopics($attribute, $model){
if($this->topics_names AND $this->topics_details){
$topicsNamesArray = explode(',',$this->topics_names);
$topicsDetailsArray = explode(';',$this->topics_details);
if(sizeof($topicsNamesArray) !== sizeof($topicsDetailsArray)){
$this->addError($attribute, \Yii::t('app', 'The topics names and details sets have different sizes'));
}
}
}

Check if db row has specific values

I am creating an event, each event will have attendees, I got this working fine, the problem I am having is an attendee can attend the same event twice, which is not good.
Event View
<?php if($this->session->userdata('user_id')): ?>
<hr>
<?php echo form_open('/attendees/add/'.$event['id']); ?>
<input type="hidden" name="user_id" value="<?php echo $_SESSION['user_id']; ?>">
<input type="submit" value="I'm in!" class="btn btn-success">
</form>
<?php endif; ?>
Attendees Controller
<?php
class Attendees extends CI_Controller {
public function add($event_id) {
// Check login
if(!$this->session->userdata('logged_in')){
redirect('users/login');
}
$this->form_validation->set_rules('user_id', 'required|callback_check_userid_eventid');
if($this->form_validation->run() === FALSE){
$this->session->set_flashdata('attendee_not_added', 'You are already on the list.');
redirect('home');
} else {
$this->attendee_model->add_attendee($event_id);
// Set message
$this->session->set_flashdata('attendee_added', 'You have been added to this event.');
redirect('events');
}
}
}
Attendees Model
<?php
class Attendee_model extends CI_Model {
public function __contruct() {
}
public function get_attendees($id = FALSE){
if($id === FALSE) {
$query = $this->db->get('attendees');
return $query->result_array();
}
$this->db->select('attendees.id, attendees.team, attendees.is_goalie, event.id, user.first_name, user.last_name');
$this->db->from('attendees');
$this->db->join('event', 'attendees.event_id = event.id', 'inner');
$this->db->join('user', 'attendees.user_id = user.id', 'inner');
$this->db->where('event.id', $id);
$query = $this->db->get();
return $query->row_array();
}
public function add_attendee($event_id){
$data = array(
'event_id' => $event_id,
'user_id' => $this->session->userdata('user_id')
);
return $this->db->insert('attendees', $data);
}
// Check attendee exists in event
public function check_userid_eventid($event_id, $user_id){
$query = $this->db->get_where('attendees', array('user_id' => $user_id, 'event_id' => $event_id));
if(empty($query->row_array())){
return true;
} else {
return false;
}
}
}
As you can see I tried creating a custom callback on the button form validation but it did not work.
If anyone can point me in the right direction, let me know if I am even somewhat close.
Thanks in advance.
You are not passing the $event_id value to the callback function. Replace your validation with the following line
$this->form_validation->set_rules('user_id', 'User ID', 'required|callback_check_userid_eventid['.$event_id.']');
add following callback function inside the Attendees Controller file
public function check_userid_eventid($user_id, $event_id){
$CI =& get_instance();
$CI->load->database();
$CI->form_validation->set_message('user_id_unique', "Sorry, that %s is already being used.");
return isset($CI->db) ? ($CI->db->limit(1)->get_where('attendees',compact('user_id','event_id'))->num_rows() == 0) : false;
}
Your callback is in a model that form validation knows nothing about. If you look at the docs: callbacks should be in the same controller as the form validation method that uses it.
However, you can use a function in a model as a callback with a different syntax:
$this->form_validation->set_rules(
'username', 'Username',
array(
'required',
array($this->users_model, 'valid_username')
)
);
as documented here.
Finally, on a false return, you need to make sure that you are setting a message as seen in this example:
public function username_check($str)
{
if ($str == 'test')
{
$this->form_validation->set_message('username_check', 'The {field} field can not be the word "test"');
return FALSE;
}
else
{
return TRUE;
}
}
In conclusion: the documentation has all the answers.
Put the call back function into Controller
<?php
class Attendees extends CI_Controller {
public function add($event_id) {
// Check login
if(!$this->session->userdata('logged_in')){
redirect('users/login');
}
$this->form_validation->set_rules('user_id', 'required|callback_check_userid_eventid');
if($this->form_validation->run() === FALSE){
$this->session->set_flashdata('attendee_not_added', 'You are already on the list.');
redirect('home');
} else {
$this->attendee_model->add_attendee($event_id);
// Set message
$this->session->set_flashdata('attendee_added', 'You have been added to this event.');
redirect('events');
}
}
// Check attendee exists in event
public function check_userid_eventid($event_id, $user_id){
$query = $this->db->get_where('attendees', array('user_id' => $user_id, 'event_id' => $event_id));
if(empty($query->row_array())){
return true;
} else {
return false;
}
}
}

How to use Yii 2 Lajax ToggleTranslate

I searched in documentation how to turn on ToggleTranslate on Yii 2 but with no success. I echoed widget
<?= \lajax\translatemanager\widgets\ToggleTranslate::widget(); ?>
but it does not apper. Then I went to source code and got this:
if (!Yii::$app->session->has(Module::SESSION_KEY_ENABLE_TRANSLATE)) {
return;
}
I commented it and my button appeared. But button is not working. So my question is how to properly (by proper flow, by proper guide) configure it and run it?
Site controller I modified:
public function actionLogin()
{
if (!Yii::$app->user->isGuest) {
return $this->goHome();
}
$model = new LoginForm();
if ($model->load(Yii::$app->request->post()) && $model->login()) {
/** set session key for appearing translate button */
if(array_key_exists('admin', Yii::$app->authManager->getAssignments(Yii::$app->user->id)))
\Yii::$app->session->set('frontendTranslation_EnableTranslate',1);
return $this->goBack();
} else {
return $this->render('login', [
'model' => $model,
]);
}
}

Cakephp3: How can I return json data?

I am having a ajax post call to a cakePhp Controller:
$.ajax({
type: "POST",
url: 'locations/add',
data: {
abbreviation: $(jqInputs[0]).val(),
description: $(jqInputs[1]).val()
},
success: function (response) {
if(response.status === "success") {
// do something with response.message or whatever other data on success
console.log('success');
} else if(response.status === "error") {
// do something with response.message or whatever other data on error
console.log('error');
}
}
});
When I try this I get the following error message:
Controller actions can only return Cake\Network\Response or null.
Within the AppController I have this
$this->loadComponent('RequestHandler');
enabled.
the Controller function looks like this:
public function add()
{
$this->autoRender = false; // avoid to render view
$location = $this->Locations->newEntity();
if ($this->request->is('post')) {
$location = $this->Locations->patchEntity($location, $this->request->data);
if ($this->Locations->save($location)) {
//$this->Flash->success(__('The location has been saved.'));
//return $this->redirect(['action' => 'index']);
return json_encode(array('result' => 'success'));
} else {
//$this->Flash->error(__('The location could not be saved. Please, try again.'));
return json_encode(array('result' => 'error'));
}
}
$this->set(compact('location'));
$this->set('_serialize', ['location']);
}
What do I miss here? Is there any additional settings needed?
Instead of returning the json_encode result, set the response body with that result and return it back.
public function add()
{
$this->autoRender = false; // avoid to render view
$location = $this->Locations->newEntity();
if ($this->request->is('post')) {
$location = $this->Locations->patchEntity($location, $this->request->data);
if ($this->Locations->save($location)) {
//$this->Flash->success(__('The location has been saved.'));
//return $this->redirect(['action' => 'index']);
$resultJ = json_encode(array('result' => 'success'));
$this->response->type('json');
$this->response->body($resultJ);
return $this->response;
} else {
//$this->Flash->error(__('The location could not be saved. Please, try again.'));
$resultJ = json_encode(array('result' => 'error', 'errors' => $location->errors()));
$this->response->type('json');
$this->response->body($resultJ);
return $this->response;
}
}
$this->set(compact('location'));
$this->set('_serialize', ['location']);
}
Edit (credit to #Warren Sergent)
Since CakePHP 3.4, we should use
return $this->response->withType("application/json")->withStringBody(json_encode($result));
Instead of :
$this->response->type('json');
$this->response->body($resultJ);
return $this->response;
CakePHP Documentation
Most answers I've seen here are either outdated, overloaded with unnecessary information, or rely on withBody(), which feels workaround-ish and not a CakePHP way.
Here's what worked for me instead:
$my_results = ['foo'=>'bar'];
$this->set([
'my_response' => $my_results,
'_serialize' => 'my_response',
]);
$this->RequestHandler->renderAs($this, 'json');
More info on RequestHandler. Seemingly it's not getting deprecated anytime soon.
UPDATE: CakePHP 4
$this->set(['my_response' => $my_results]);
$this->viewBuilder()->setOption('serialize', true);
$this->RequestHandler->renderAs($this, 'json');
More info
there are few things to return JSON response:
load RequestHandler component
set rendering mode as json
set content type
set required data
define _serialize value
for example you can move first 3 steps to some method in parent controller class:
protected function setJsonResponse(){
$this->loadComponent('RequestHandler');
$this->RequestHandler->renderAs($this, 'json');
$this->response->type('application/json');
}
later in your controller you should call that method, and set required data;
if ($this->request->is('post')) {
$location = $this->Locations->patchEntity($location, $this->request->data);
$success = $this->Locations->save($location);
$result = [ 'result' => $success ? 'success' : 'error' ];
$this->setJsonResponse();
$this->set(['result' => $result, '_serialize' => 'result']);
}
also it looks like you should also check for request->is('ajax); I'm not sure about returning json in case of GET request, so setJsonResponse method is called within if-post block;
in your ajax-call success handler you should check result field value:
success: function (response) {
if(response.result == "success") {
console.log('success');
}
else if(response.result === "error") {
console.log('error');
}
}
In the latest version of CakePHP $this->response->type() and $this->response->body() are deprecated.
Instead you should use $this->response->withType() and $this->response->withStringBody()
E.g:
(this was pinched from the accepted answer)
if ($this->request->is('post')) {
$location = $this->Locations->patchEntity($location, $this->request->data);
if ($this->Locations->save($location)) {
//$this->Flash->success(__('The location has been saved.'));
//return $this->redirect(['action' => 'index']);
$resultJ = json_encode(array('result' => 'success'));
$this->response = $this->response
->withType('application/json') // Here
->withStringBody($resultJ) // and here
return $this->response;
}
}
Relevant Documentation
When you return JSON data you need to define the data type and response body information like below:
$cardInformation = json_encode($cardData);
$this->response->type('json');
$this->response->body($cardInformation);
return $this->response;
In you case just change this return json_encode(array('result' => 'success')); line with below code:
$responseResult = json_encode(array('result' => 'success'));
$this->response->type('json');
$this->response->body($responseResult);
return $this->response;
RequestHandler is not required to send json.
In controller's action:
$this->viewBuilder()->setClassName('Json');
$result = ['result' => $success ? 'success' : 'error'];
$this->set($result);
$this->set('_serialize', array_keys($result));
As of cakePHP 4.x.x the following should work assuming that your controller and routes are set as shown below:
controller: <your_project_name>/src/Controller/StudentsController.php
public function index()
{
$students = $this->Students->find('all');
$this->set(compact('students'));
$this->viewBuilder()->setOption('serialize',['students']);
}
Routes: <your_project_name>/config/routes.php
<?php
use Cake\Routing\Route\DashedRoute;
use Cake\Routing\RouteBuilder;
/** #var \Cake\Routing\RouteBuilder $routes */
$routes->setRouteClass(DashedRoute::class);
$routes->scope('/', function (RouteBuilder $builder) {
$builder->setExtensions(['json']);
$builder->resources('Students');
$builder->fallbacks();
});
Run bin/cake server and visit http://localhost:8765/students.json using postman/insomnia or just the normal browser.
See further documentation for setting up Restful controllers and Restful Routing
Don't forget to set the method to GET on postman and insomnia.
Though I'm not a CakePHP Guru, in my case i'm using cake > 4 and I need some results by ajax call. For this, from my controller i wrote,
echo json_encode(Dashboard::recentDealers()); die;
and in my JS file i just need to parse the data using
JSON.parse(data)
The ajax call like
$.get('/recent-dealers', function (data, status) {
console.log (JSON.parse(data)); });
});

Yii2: why does the layout not get shown?

I have a controller with a working action:
class ConfigurationController extends Controller {
public function actions() {
return [
'error' => [
'class' => 'yii\web\ErrorAction',
],
];
}
public function actionView() {
$myModel = ...
$this->render('view', ['model' => $myModel]);
}
}
All seems to be fine, however the layout file which is app/views/layout/main.php does not get shown. There is no special configuration about the layout. What could be wrong?
The main reason: I did not use the return statement. So the correct action is:
public function actionView() {
$myModel = ...
return $this->render('view', ['model' => $myModel]);
// ^^^^^^
}
More info can be found in the guide.
Note: Usually an empty page would be shown. But I also had a <?php $form = ActiveForm::begin(); ?> without an <?php ActiveForm::end(); ?> in the view file. This caused a partial rendering somehow (caused no exception). So I needed to correct this as well.
I'm just sharing my problem and what I've found out so if anyone else has a similar effect may be reminded that the return statement must not be forgotten.