Boolen check if datetime.now() is between the values of any tuple in a list of tuples - boolean-logic

Question

I have a list of tuples looking like this:
import datetime as dt
hours = [(dt.datetime(2019,3,9,23,0), dt.datetime(2019,3,10,22,0)),
(dt.datetime(2019,3,10,23,0), d.datetime(2019,3,11,22,0))]
The list has a variable length and I just need a boolean if datetime.now() is between the first and second element of any tuple in the list.
In NumPy I would do:
((start <= now) & (end >= now)).any()
what is the most efficient way to do this in a pythonic way? Sorry about the beginners question.
this works but I don't like the len():
from itertools import takewhile
len(list(takewhile(lambda x: x[0] <= now and now <= x[1], hours ))) > 0
any better suggestions?

Answer 1

any(map(lambda d: d[0] <= now <= d[1], hours))
any: Logical OR across all elements
map: runs a function on every element of the list
As #steff pointed out map is redundant, because we cause list enumeration directly.
any(d[0] <= now <= d[1] for d in hours)
It would be way better if we can avoid indexing into tuple and use tuple unpacking somehow (this was the reason I started with map)

Answer 2

A more verbose alternative. (But more readable in my eyes)
import datetime as dt
def in_time_ranges(ranges):
now = dt.datetime.now()
return any([r for r in ranges if now <= r[0] and r[1] >= now])
ranges1 = [(dt.datetime(2019, 3, 9, 23, 0), dt.datetime(2019, 3, 10, 22, 0)),
(dt.datetime(2019, 3, 10, 23, 0), dt.datetime(2019, 3, 11, 22, 0)),
(dt.datetime(2019, 4, 10, 23, 0), dt.datetime(2019, 5, 11, 22, 0))]
print(in_time_ranges(ranges1))
ranges2 = [(dt.datetime(2017, 3, 9, 14, 0), dt.datetime(2018, 3, 10, 22, 0)),
(dt.datetime(2018, 3, 10, 23, 0), dt.datetime(2018, 3, 11, 22, 0)),
(dt.datetime(2018, 4, 10, 23, 0), dt.datetime(2018, 5, 11, 22, 0))]
print(in_time_ranges(ranges2))
Output
True
False