How to get order and sum between three tables on mysql? - mysql

Question

I'm trying to sort table 1 using the sort on table 2
and sum the value for each "order number" on table 1 and group by "order number"
and after that bring the client name from table 3 then the result should be like that:
sort ordernumber sumvalue name location
01 5555 120 Client 2 location 2
01 5498 50 Client 2 location 2
02 2324 50 Client 1 location1
02 4356 30 Client 1 location1
tables:
table 1 orders
===============
id ordernumber code_client value
1 2324 01 20
1 2324 01 30
1 4356 01 30
1 5555 02 40
1 5555 02 40
1 5498 02 50
1 5555 02 40
table 2 sort
============
sort code_client
1 02
2 01
table 3 client
===============
code_client name location
01 Client 1 location1
02 Client 2 location2
what i done in the following code is not respect the order even the sum for each ordernumber
SELECT orders.ordernumber,
SUM(orders.value) AS totalordersvalue,
orders.code_client,
sort.code_client,sort.sort,
client.code_client,client.name, client.location,
FROM orders
LEFT JOIN client
ON client.code_client = orders.code_client
LEFT JOIN sort
ON sort.code_client = orders.code_client
WHERE orders.id = 1
GROUP BY orders.ordernumber
ORDER BY sort.sort
there is any way to get the correct order and correct sum for each order as the final result ? thanks

Answer 1

You can try below -
select sort, ordernumber ,totalordersvalue as sumvalue,name,location from
(
SELECT orders.ordernumber, SUM(orders.value) AS totalordersvalue,
orders.code_client
FROM orders WHERE orders.id = 1 group by orders.ordernumber,orders.code_client
)A inner join client ON client.code_client = A.code_client
inner join sort ON sort.code_client = A.code_client
ORDER BY sort.sort

Answer 2

If the sequence of getting a result doesn't matter for you then you can use the following query
SELECT
DISTINCT o.ordernumber,
s.sort,
(SELECT sum(os.value) AS sum_value FROM orders AS os WHERE o.ordernumber =
os.ordernumber GROUP BY os.ordernumber) AS sum_value,
c.name,
c.location
FROM
sort AS s,
orders AS o,
client AS c
WHERE c.code_client = o.code_client AND o.code_client=s.code_client
ORDER BY s.sort;
Output:
ordernumber sort sumvalue name location
5555 01 120 Client 2 location 2
5498 01 50 Client 2 location 2
2324 02 50 Client 1 location1
4356 02 30 Client 1 location1