fetch json data into swift uitable view - json

Question

Below is my json file
and the url is http://localhost/country.php
I want this data into uitable view swift
{ name: ["India","USA","China"] }
let url = NSURL(string: "http://localhost/country.php")
let userdata = NSData(contentsOf: url! as URL)
do {
let values = try JSONSerialization.jsonObject(with: userdata as! Data, options: .allowFragments) as! NSDictionary
print(values)
print("Parse success")
} catch let error as NSError
{
print(error)
return
}
this is the code
please help

Answer 1

So. First of all: Your JSON is not a valid JSON and your URL is (of course) not working. My guess is your JSON looks like that:
{
"name": ["India",
"USA",
"China"
]
}
If so you can change your code like that and it is working as expected:
let jsonString = """
{
"name": ["India",
"USA",
"China"
]
}
"""
let userData = jsonString.data(using: .utf8)!
do {
let values = try JSONSerialization.jsonObject(with: userData) as! [String: Any]
print(values)
print("Parse success")
} catch let error as NSError
{
print(error)
}
Like one comment already mentioned: Try to avoid NStypes in Swift if it is not really needed.
Hope it helps.
And in addition: It is generally a bad practice to load a response from server sync. You should use URLSession and do it async. But this is another thing...
So the full example for your use case would look like this:
let url = URL(string: "http://localhost/country.php")!
let userData = try! Data(contentsOf: url)
do {
let values = try JSONSerialization.jsonObject(with: userData) as! [String: Any]
print(values)
print("Parse success")
} catch let error as NSError
{
print(error)
}
I force unwrap in the example above. I do not recommend that. Savely unwrap your optionals is the better way.