Output of sympy.fourier_transform - fft

I run sympy.fourier_transform using the following code
from sympy import fourier_transform, exp,symbols
from sympy.abc import x, k
a=fourier_transform(exp(-x**2), x, k)
s=symbols('s')
Ori=(s)*exp(-(x**2)/(s**2))
FT=fourier_transform(Ori,x,k)
a.subs({k:1}).evalf()
>>>9.16769605680502e-5
FT.subs({s:1,k:1}).evalf()
>>>FourierTransform(exp(-x**2), x, 1)
a.subs({k:1}).evalf() is a number, as I was expecting.
But I don't understand the result of FT.subs({s:1,k:1}).evalf(). It is not a number even though I applied .evalf(). I want to get a numeric value. What is the problem?
Now I'm using sympy version 1.3, python version 3.7.1. This code was running fine with sympy version 1.1.

Related

How to plot a function in Python when both variables cannot be isolated to one side

I am trying to graph variable "u" versus variable "T" for 1<T<1000 (integers). However, the function I have includes both of the variables within an integral so I cannot create an isolated u=f(T) function. My thought process is to manipulate the function so that it is 0=f(T,u) and output a "u" value that minimizes f(T,u) for each T. However, I seem to be struggling a lot with how these variables and functions should be defined. All constants are defined and "E" should be defined through the integration step. The overall function I start with is:
5x10^28=integrate((pi/2)(8m/h^2)(E^0.5)(exp((E-u)/k*T)+1)^-1) from 0 to infinity and with respect to "E"
I am very new to python but the following code is how far I've been able to develop it based on previous forums and video tutorials. Any help is much appreciated!
from scipy.integrate import quad
import numpy as np
import matplotlib.pyplot as plt
import scipy.optimize as spo
m=9.11e-31
h=6.63e-34
k=1.38e-23
T=list(range(1,1001))
def f(E,u):
return (np.pi/2)*(8*m/(h**2))*(E**0.5)*(1/((np.exp((E-u)/k*T)+1)))
Func_Equal_Zero=quad(f,0,np.inf,args=(u,))[0]-5e-28
Start_Guess_T_u=[500,1e-5]
result=spo.minimize(Func_Equal_Zero,Start_Guess_T_u)
plt.plot(T,u)
plt.figure(figsize=(6,6))
plt.xlabel('Temperature (k)')
plt.ylabel('Chemical Potential (J)')
I expected that I could just define the functions including "u" but python does not seem to like what I have tried. I am not sure if any of my other syntax is not correct because I cannot get past its issue with defining "u".

SymPy Wronskian function

I have been trying to compute the wronskian using SymPy, and can not figure out how to use the function. I did look at the program itself but I am very new to python. For functions any sinusoidal is okay. I just want to observe how to use SymPy in this way for future reference. Any help would be great!
~I listed my imports below
import sympy as sp
from scipy import linalg
import numpy as np
sp.init_printing()
I don't this that 'var' is the only thing wrong with what I am inputting.
You have to define the var first. You have not defined it. Also the functions should go in a list.
x = sp.Symbol('x')
## Define your var here
Wronskian_Sol = sp.matrices.dense.wronskian([sp.sin(x), 1-sp.cos(x)**2], var, method="bareiss")
Here is an example in this book "Applied Differntial Equation with Boundary Value Problems" by Vladimir A. Dobrushkin at page 199.
I computed a Wronskian for these three functions using Sympy
x
x*sin(x)
x*cons(x)
import sympy as sp
x = sp.Symbol('x')
var = x
Wronskian_Sol = sp.matrices.dense.wronskian([x, x*sp.cos(x), x*sp.sin(x)], var, method="bareiss")
print(Wronskian_Sol)
print(Wronskian_Sol.simplify())
This gives the output. The first is not simplified, the last one is simplified. You can reduce the first one to simplified version easily by taking the common factor x**3 out which leaves (sin(x)**2 + cos(x)**2) ..and this is nothing but 1.
x**3*sin(x)**2 + x**3*cos(x)**2
x**3
You can confirm the solution by manually taking the determinant of the derivative matrix.

sympy autowrap (cython): limit of # of arguments, arguments in array form?

I have the following issue:
I want to use autowrap to generate a compiled version of a sympy matrix, with cells containing sympy expressions. Depending on the specification of my problem, the number of arguments can get very large.
I ran into the following 2 issues:
The number of arguments that autowrap accepts seems to be limited to 509.
i.e., this works:
import sympy
from sympy.utilities.autowrap import autowrap
x = sympy.symbols("x:509")
exp = sum(x)
cyt = autowrap(exp, backend="cython", args=x)
and this fails to compile:
x = sympy.symbols("x:510")
exp = sum(x)
cyt = autowrap(exp, backend="cython", args=x)
The message I get seems not very telling:
[...] (Full output upon request)
Generating code
c:\users\[classified]\appdata\local\temp\tmp2zer8vfe_sympy_compile\wrapper_module_17.c(6293) : fatal error C1001: An internal error has occurred in the compiler.
(compiler file 'f:\dd\vctools\compiler\utc\src\p2\hash.c', line 884)
To work around this problem, try simplifying or changing the program near the locations listed above.
Please choose the Technical Support command on the Visual C++
Help menu, or open the Technical Support help file for more information
LINK : fatal error LNK1257: code generation failed
error: command 'C:\\Program Files (x86)\\Microsoft Visual Studio 14.0\\VC\\BIN\\x86_amd64\\link.exe' failed with exit status 1257
Is there any way around this? I would like to use versions of my program that need ~1000 input variables.
(I have no understanding of C/cython. Is this an autowrap limitation, a C limitation ...?)
Partly connected to the above:
Can one compile functions that accept the arguments as array.
Is there any way to generate code that accepts a numpy array as input? I specifically mean one array for all the arguments, instead of providing the arguments as list. (Similar to lambdify using a DeferredVector). ufuncify supports array input, but as I understand only for broadcasting/vectorizing the function.
I would hope that an array as argument could circumvent the first problem above, which is most pressing for me. Apart from that, I would prefer array input anyways, both because it seems faster (no need to unpack the numpy array I have as input into a list), and also more straightforward and natural.
Does anyone have any suggestions what I can do?
Also, could anyone tell me whether f2py has similar limitations? This would also be an option for me if feasible, but I don't have it set up to work currently, and would prefer to know whether it helps at all before investing the time.
Thanks!
Edit:
I played around a bit with the different candidates for telling autowrap that the input argument will be something in array form, rather than a list of numbers. I'll document my steps here for posterity, and also to increase chances to get some input:
sympy.DeferredVector
Is what I use with lambdify for the same purpose, so I thought to give it a try. However, warning:
A = sympy.DeferredVector("A")
expression = A[0]+A[1]
cyt = autowrap(expression, backend="cython", args=A)
just completely crashed my OS - last statement started executing, (no feedback), everything got really slow, then no more reactions. (Can only speculate, perhaps it has to do with the fact that A has no shape information, which does not seem to bother lambdify, but might be a problem here. Anyways, seems not the right way to go.)
All sorts of array-type objects filled with the symbols in the expression to be wrapped.
e.g.
x0 ,x1 = sympy.symbols("x:2")
expression = x0 + x1
cyt = autowrap(expression, backend="cython", args=np.array([x0,x1]))
Still wants unpacked arguments. Replacing the last row by
cyt = autowrap(expression, backend="cython", args=[np.array([x0,x1])])
Gives the message
CodeGenArgumentListError: ("Argument list didn't specify: x0, x1 ", [InputArgument(x0), InputArgument(x1)])
Which is a recurrent theme to this approach: also happens when using a sympy matrix, a tuple, and so on inside the arguments list.
sympy.IndexedBase
This is actually used in the autowrap examples; however, in a (to me) inintuitive way, using an equation as the expression to be wrapped. Also, the way it is used there seems not really feasible to me: The expression I want to cythonize is a matrix, but its cells are themselves longish expressions, which I cannot obtain via index operations.
The upside is that I got a minimal example to work:
X = sympy.IndexedBase("X",shape=(1,1))
expression = 2*X[0,0]
cyt = autowrap(expression, backend="cython", args=[X])
actually compiles, and the resulting function correctly evaluates - when passed a 2d-np.array.
So this seems the most promising avenue, even though further extensions to this approach I keep trying fail.
For example this
X = sympy.IndexedBase("X",shape=(1,))
expression = 2*X[0]
cyt = autowrap(expression, backend="cython", args=[X])
gets me
[...]\site-packages\sympy\printing\codeprinter.py", line 258, in _get_expression_indices " rhs indices in %s" % expr)
ValueError: lhs indices must match non-dummy rhs indices in 2*X[0]
even though I don't see how it should be different from the working one above.
Same error message when sticking to two dimensions, but increasing the size of X:
X = sympy.IndexedBase("X",shape=(2,2))
expression = 2*X[0,0]+X[0,1]+X[1,0]+X[1,1]
cyt = autowrap(expression, backend="cython", args=[X])
ValueError: lhs indices must match non-dummy rhs indices in 2*X[0, 0] + X[0, 1] + X[1, 0] + X[1, 1]
I tried snooping around the code for autowrap, but I feel a bit lost there...
So I'm still searching for a solution and happy for any input.
Passing the argument as an array seems to work OK
x = sympy.MatrixSymbol('x', 520, 1)
exp = 0
for i in range(x.shape[0]):
exp += x[i]
cyt = autowrap(exp, backend='cython')
arr = np.random.randn(520, 1)
cyt(arr)
Out[48]: -42.59735861021934
arr.sum()
Out[49]: -42.597358610219345

define theano function with other theano function output

I am new to theano, can anyone help me defining a theano function like this:
Basically, I have a network model looks like this:
y_hat, cost, mu, output_hiddens, cells = nn_f(x, y, in_size, out_size, hidden_size, layer_models, 'MDN', training=False)
here the input x is a tensor:
x = tensor.tensor3('features', dtype=theano.config.floatX)
I want to define two theano functions for later use:
f_x_hidden = theano.function([x], [output_hiddens])
f_hidden_mu = theano.function([output_hiddens], [mu], on_unused_input = 'warn')
the first one is fine. for the second one, the problem is both the input and the output are output of the original function. it gives me error:
theano.gof.fg.MissingInputError: An input of the graph, used to compute Elemwise{identity}(features), was not provided and not given a value.
my understanding is, both of [output_hiddens] and [mu] are related to the input [x], there should be an relation between them. I tried define another theano function from [x] to [mu] like:
f_x_mu = theano.function([x], [mu]),
then
f_hidden_mu = theano.function(f_x_hidden, f_x_mu),
but it still does not work. Does anyone can help me? Thanks.
The simple answer is NO WAY. In here
Because in Theano you first express everything symbolically and afterwards compile this expression to get functions, ...
You can't use the output of theano.function as input/output for another theano.function since they are already a compiled graph/function.
You should pass the symbolic variables, such as x in your example code for f_x_hidden, to build the model.

#cython.wraparound(False) cast integer CORE GENERATED Error

In cython when my code is compiled with
#cython.wraparound(True)
and I use the following cast function to convert (cast) a float to an integer
cdef DTYPE_t_I float_int(np.float_t val):
return <DTYPE_t_I>val
it runs ok
BUT
when I turn off
#cython.wraparound(False)
the code compiles normally and when it runs it gives the following error
CORE GENERATED
It happens compiling in linux with gcc and windows with MGS
What is wrong? Should it be like this?
Because I am trying to gain speed, I would like to know to switch off these flag.