Count row on table2 based on table1 with prepared statement - mysql

I have 2 tables:
clients_db
| clnt_id | clnt_sid | usr_sid | clnt_name |
| 1 | 12345678 | 10001 | Peter |
| 2 | 87654321 | 10001 | Mikey |
aircon_client_db
| ac_id | clnt_sid |
| 1 | 12345678 |
| 2 | 12345678 |
| 3 | 12345678 |
| 4 | 87654321 |
| 5 | 87654321 |
This is query:
select *,count(air.ac_id) as nAC
from clients_db clnt
left join aircon_client_db air on air.clnt_sid=clnt.clnt_sid
where clnt.usr_sid=?
group by clnt.clnt_sid
order by clnt.clnt_name asc
From the code above. I expect the result clnt_id[1]=3 and clnt_id[2]=2. But the result returns 0 for all. Where should I fix?

You just need to select the count(air.ac_id).
Also replace clnt.usr_sid=? with clnt.clnt_id=? if you're going to expect a result like clnt_id[1]=3.
select count(air.ac_id) as nAC
from clients_db clnt
left join aircon_client_db air on air.clnt_sid=clnt.clnt_sid
where clnt.clnt_id=?
group by clnt.clnt_sid
order by clnt.clnt_name asc
Are you missing clnt_name as column in your question?

Don't use * but explicit column name or in this case you could also use clnt.* (you don't need the value for the left joined table but only the count(*)
select clnt.clnt_id, clnt.clnt_sid ,count(air.ac_id) as nAC
from clients_db clnt
left join aircon_client_db air on trim(air.clnt_sid)=trim(clnt.clnt_sid)
AND trim(clnt.user_sid)= '10001'
group by clnt.clnt_sid
order by clnt.clnt_name asc

Related

Mysql count per distinct user with a join

currently i have two tables with some data. the first table has the following:
+----------------+-----------+
| name | member_id |
+----------------+-----------+
| Juice Box | 49432 |
| Rainsurge | 49631 |
| spiderpigrider | 50482 |
+----------------+-----------+
The second table has the following:
+------------+-----------+
| recruit_id | bin(refs) |
+------------+-----------+
| 49432 | 1 |
| 49631 | 1 |
| 49432 | 1 |
| 49631 | 1 |
| 49432 | 1 |
| 49631 | 1 |
| 49432 | 1 |
| 49631 | 1 |
| 49432 | 1 |
| 49631 | 1 |
+------------+-----------+
I would like to return the name, total refs and member_id/recruit_id like so (listing only users with at least 1 ref)
+------------+-----------+------------+
| recruit_id | name | total_refs |
+------------+-----------+------------+
| 49631 | Rainsurge | 5 |
| 49432 | Juice Box | 5 |
+------------+-----------+------------+
select r.recruit_id,bin(r.refs),ipb.name from refs as r
inner join syndicate_ipb.core_members as ipb on ipb.member_id=r.recruit_id;
this returned my data but obviously without a total count and repeated names/ids
select r.recruit_id,count(bin(r.refs)),ipb.name from refs as r
inner join syndicate_ipb.core_members as ipb on ipb.member_id=r.recruit_id;
this returned data with the total count of everyone but only one id/name
+------------+--------------------+-----------+
| recruit_id | count(bin(r.refs)) | name |
+------------+--------------------+-----------+
| 49432 | 10 | Juice Box |
+------------+--------------------+-----------+
this returns the data but again without a count
select distinct r.recruit_id,bin(r.refs),ipb.name from refs as r
inner join syndicate_ipb.core_members as ipb on ipb.member_id=r.recruit_id;
+------------+-------------+-----------+
| recruit_id | bin(r.refs) | name |
+------------+-------------+-----------+
| 49432 | 1 | Juice Box |
| 49631 | 1 | Rainsurge |
+------------+-------------+-----------+
Any help or guidance is greatly appreciated. I feel like i'm close here but just not competent enough with SQL to get it. thanks!
You were almost there. You just missed the GROUP BY clause at the end.
Query:
SELECT
r.recruit_id,
count(bin(r.refs)),
ipb.name
FROM refs AS r
INNER JOIN syndicate_ipb.core_members AS ipb
ON ipb.member_id = r.recruit_id
GROUP BY r.recruit_id;
Note:
If bin(refs) column always contains value 1 then actually you don't need to keep that column. In that case you can use count(*) or count(r.recruit_id) to get the count.
And if bin(refs) column contains any value then count will not give you the right answer. In that case you need to use sum like Sum( bin(refs)).
You have to use the group by clause:
select r.recruit_id, ipb.name, count(bin(refs)) as total_refs
from refs as r
inner join syndicate_ipb.core_members as ipb
on ipb.member_id=r.recruit_id
group by r.recruit_id, ipb.name
having count(bin(refs)) >= 1
This group by r.recruit_id, ipb.name will group the results and this having count(bin(refs)) >= 1 will garante that it only returns members with at least one ref
Do not only group your columns just by the ones you want. Even though MySql allows it, it is not SQL Ansi pattern and even MySql now is complying with it. Use an aggregation function grouping with your entire columns on the select statement.
SELECT ipb.*, COUNT(`r`.`recruit_id`) AS cid FROM `ipb`
INNER JOIN `r` ON `r`.`join_id` = ipb.`member_id`
GROUP BY ipb.`member_id`

How to join tables with SQL query and take number of tied columns?

I'm having BookTable in database (with foregin hey LibID):
| BookID | BookName | BookPrice | LibID |
-------------------------------------------
| 1 | Book_1 | 200 | 1 |
| 2 | Book_2 | 100 | 1 |
| 3 | Book_3 | 300 | 2 |
| 4 | Book_4 | 150 | 4 |
and also LibraryTable:
| LibID | LibName | LibLocation |
-----------------------------------
| 1 | Lib_1 | Loc_1 |
| 2 | Lib_2 | Loc_2 |
| 3 | Lib_3 | Loc_3 |
| 4 | Lib_4 | Loc_4 |
I need to write SQL query that will return be the info about the library and number of books for that library:
| LibID | LibName | NumberOfBooks|
------------------------------------
| 1 | Lib_1 | 2 |
| 2 | Lib_2 | 1 |
| 3 | Lib_3 | 0 |
| 4 | Lib_4 | 1 |
It should be one SQL query, probably with nested queries or joins.. Not sure how the query should look like:
SELECT L.LibID AS LibID, L.LibName AS LibName, COUNT(B) AS NumberOfBooks
FROM LibraryTable L, BookTable B
WHERE L.LibID = B.LibID
Will that work?
No, this query will not work. COUNT aggregates data, so you must explicitely tell the DBMS for which group of data you want the count. In your case this is the library (you want one result record per library).
COUNT's parameter is a column, not a table, so change this to * (i.e. count records) or a certain column (e.g. LibID).
The join syntax you are using is valid, but deprecated. Use explicit joins instead. In your case an outer join would even show libraries that have no books at all, if such is possible.
select l.libid, l.libname, count(b.libid) as numberofbooks
from librarytable l
left outer join booktable b on b.libid = l.libid
group by l.libid;
You could also do all this without a join at all and get the book count in a subquery instead. Then you wouldn't have to aggregate. That's way simpler and more readable in my opinion.
select
l.libid,
l.libname,
(select count(*) booktable b where b.libid = l.libid) as numberofbooks
from librarytable l;
SELECT lt.LibID AS LibID, lt.LibName AS LibName, count(*) AS NumberOfBooks
FROM BookTable AS bt
LEFT JOIN LibraryTable AS lt ON bt.LibID = lt.LibID
GROUP BY bt.LibID

Using left join with min

I am trying to connect two tables with left join and a date.
My SQL Query
SELECT
ord.`ordernumber` bestellnummer,
his.`change_date` zahldatum
FROM
`s_order` ord
LEFT JOIN
`s_order_history` his ON ((ord.`id`=his.`orderID`) AND (ord.`cleared`=his.`payment_status_id`)) #AND MIN(his.`change_date`)
WHERE
ord.`ordertime` >= \''.$dateSTART.'\' AND ord.`ordertime` <= \''.$dateSTOP.'\'' ;
s_order
+----+---------------------+---------+-------------+
| id | ordertime | cleared | ordernumber |
+----+---------------------+---------+-------------+
| 1 | 2014-08-11 19:53:43 | 2 | 123 |
| 2 | 2014-08-15 18:33:34 | 2 | 125 |
+----+---------------------+---------+-------------+
s_order_history
+----+-------------------+-----------------+---------+---------------------+
| id | payment_status_id | order_status_id | orderID | orderID change_date |
+----+-------------------+-----------------+---------+---------------------+
| 1 | 1 | 5 | 1 | 2014-08-11 20:53:43 |
| 2 | 2 | 5 | 1 | 2014-08-11 22:53:43 |
| 3 | 2 | 7 | 1 | 2014-08-12 19:53:43 |
| 4 | 1 | 5 | 2 | 2014-08-15 18:33:34 |
| 5 | 1 | 6 | 2 | 2014-08-16 18:33:34 |
| 6 | 2 | 6 | 2 | 2014-08-17 18:33:34 |
+----+-------------------+-----------------+---------+---------------------+
Wanted result:
+-------------+---------------------+
| ordernumber | change_date |
+-------------+---------------------+
| 123 | 2014-08-11 22:53:43 |
| 125 | 2014-08-17 18:33:34 |
+-------------+---------------------+
The problem I have is getting only the date, where the cleared/payment_status_id value has been changed in s_order. I currently get all dates where the payment_status_id matches the current cleared value, but I only need the one, where it happend first.
This is only an excerpt of the actually query, since the original is a lot longer (mostly more left joins and a lot more tables).
You can group data by ordernumber
SELECT
ord.`ordernumber` bestellnummer,
MIN(his.`min_change_date`) as zahldatum
FROM
`s_order` ord
LEFT JOIN
`s_order_history` his ON ((ord.`id`=his.`orderID`) AND (ord.`cleared`=his.`payment_status_id`)) #AND MIN(his.`change_date`)
WHERE
ord.`ordertime` >= \''.$dateSTART.'\' AND ord.`ordertime` <= \''.$dateSTOP.'\''
GROUP BY
ord.`ordernumber`;
or you can group data in a subquery:
SELECT
ord.`ordernumber` bestellnummer,
his.`min_change_date` zahldatum
FROM
`s_order` ord
LEFT JOIN (
SELECT
orderID, payment_status_id, MIN(change_date) as min_change_date
FROM
s_order_history
GROUP BY
orderID, payment_status_id
) his ON (ord.`id` = his.`orderID` AND ord.`cleared` = his.`payment_status_id`)
WHERE
ord.`ordertime` >= \''.$dateSTART.'\' AND ord.`ordertime` <= \''.$dateSTOP.'\'';
Try this:
select s_order.ordernumber, min(s_order_history.change_date)
from s_order left join s_order_history
on s_order.id = s_order_history.orderID
and s_order.cleared = s_order_history.payment_status_id
group by s_order.order_id
SELECT ord.`ordernumber` bestellnummer,
MIN( his.`change_date` ) zahldatum
...
GROUP BY ord.`ordernumber`
MIN is an aggregate function so you can't use it in a JOIN straight up like you've tried above. You also are not comparing it to a value in your JOIN.
You'll want to do something like:
his.`change_date` = (SELECT MIN(his.`change_date`) FROM s_order_history where ord.`id` = his.`orderID`)
in your JOIN.

How do I select all the dealers that did not have an order?

I am trying to join two tables and only select the dealers that did not have their promo code used on any order.
How can I do this?
I'm trying this below, but it's not working right. In the example I want to get just Bob, since his promo_code hasn't been used in any orders.
SELECT d.`name`
FROM z_dealer d
LEFT OUTER JOIN z_order o ON (d.promo_code = o.promo_code)
AND o.promo_code IS NULL
Here are my tables...
mysql> select * from z_dealer;
+----+------+------------+
| id | name | promo_code |
+----+------+------------+
| 1 | John | holiday |
| 2 | Suzy | special |
| 3 | Bob | laborday |
+----+------+------------+
mysql> Select * from z_order;
+----+-------+------------+
| id | total | promo_code |
+----+-------+------------+
| 1 | 10 | holiday |
| 2 | 20 | special |
| 3 | 15 | holiday |
| 4 | 45 | special |
+----+-------+------------+
SELECT d.`name` FROM z_dealer d LEFT JOIN z_order o ON (d.promo_code = o.promo_code) WHERE o.promo_code IS NULL
Have you tried INNER JOIN? or You can try IN like this :
SELECT d.name
FROM z_dealer d
WHERE d.promo_code not in( SELECT promo_code FROM z_order)
I'm not entirely sure why it's not working in your example code. I've created the same tables locally and when I run the script you provided I get the single 'Bob' answer.
SELECT d.name
FROM z_dealer d
LEFT OUTER JOIN z_order o ON (d.promo_code = o.promo_code)
AND o.promo_code IS NULL
What results are you seeing exactly?

SQL : Select statement order by

i want to select a column but with diferent order :
i have 2 table :
table_name:
+------+-----------+
| id | name |
+------+-----------+
| 1 | Sindra |
| 2 | Auli |
| 3 | Brian |
| 4 | Bina |
| 5 | zian |
| 6 | Bri |
| 7 | Andre |
+------+-----------+
table_temp, id_temp_name foreign key of id(table_name) :
+------+--------------+
| id | id_temp_name |
+------+--------------+
| 1 | 1 |
| 2 | 3 |
| 3 | 4 |
| 4 | 2 |
+------+--------------+
with this query :
SELECT *
FROM table_name
WHERE id IN
(SELECT id_temp_name FROM table_temp)
the result is always same look with table_name, i was looking for result that exactly same with id_temp_name order , so the result will be :
+------+-----------+
| id | name |
+------+-----------+
| 1 | Sindra |
| 3 | Brian |
| 4 | Bina |
| 2 | Auli |
+------+-----------+
thanks for any advice, .
You need to rewrite the query to be a JOIN between both tables, then you can set an ordering based on any column involved, even when not in the final result set:
SELECT table_name.id,
table_name.name
FROM table_name
INNER JOIN table_temp ON table_name.id = table_temp.id_temp_name
ORDER BY table_temp.id ;
Use a join instead of a sub-query.
SELECT table_name.id, table_name.name
FROM table_name
INNER JOIN table_temp ON table_name.id = table_temp.id
ORDER BY table_temp.id_temp_name
And... usually best to list the fields explicitly instead of using * to select all.
You should use a simple JOIN to achieve your result.
Your query:
SELECT *
FROM table_name
WHERE id IN
(SELECT id_temp_name FROM table_temp)
actually returns all the rows and columns of the table_name Table. So you won't get the desired id_temp_name results, since it's in a different table. That's why, you should use LEFT JOIN, since your left table is table_name, and your right table is table_temp, and you want to show data from a column of table_temp, which is id_temp_name.
So, what you need to do, is this:
SELECT tn.id, tn.name
FROM table_name AS tn
LEFT JOIN table_temp AS tt
ON tn.id= tt.id_temp_name
GROUP BY tn.id