Get number of monday in a rangedate mysql - mysql

Get number of monday in a rangedate MySQL, I run this code but it give me result 0:
select count(*) from tarif where weekday(`end_tarif`<= '2019-02-21'AND `start_tarif`>='2019-02-05') = 0;
my table:
CREATE TABLE `tarif` (
`tarif_id` int(11) NOT NULL AUTO_INCREMENT,
`start_tarif` date NOT NULL,
`end_tarif` date NOT NULL,
`day_tarif` varchar(50) NOT NULL,
PRIMARY KEY (`tarif_id`)
);
INSERT INTO `tarif` VALUES (1, '2019-02-01', '2019-02-10', '10'),
(2, '2019-02-11', '2019-02-20', '20'),
(3, '2019-02-21', '2019-02-28', '10'),
(4, '2019-03-01', '2019-02-10', '15');

You can use a solution using a calendar table. So you can use a solution like the following:
1. create a table with calendar data
-- create the table "calendar"
CREATE TABLE `calendar` (
`dateValue` DATE
);
-- insert the days to the table "calendar"
INSERT INTO calendar
SELECT adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4
HAVING gen_date BETWEEN '2019-01-01' AND '2019-12-31'
You can find the script to generate the calendar data on StackOverflow:
How to populate a table with a range of dates?
2. create the table with your data (with monday tarif)
-- create the table "tarif"
CREATE TABLE tarif (
tarif_id INT(11) NOT NULL AUTO_INCREMENT,
start_tarif DATE NOT NULL,
end_tarif DATE NOT NULL,
day_tarif VARCHAR(50) NOT NULL,
monday_tarif VARCHAR(50) NOT NULL,
PRIMARY KEY (tarif_id)
);
-- insert the tarif information
INSERT INTO tarif VALUES
(1, '2019-02-01', '2019-02-10', '10', '5'),
(2, '2019-02-11', '2019-02-20', '20', '5'),
(3, '2019-02-21', '2019-02-28', '10', '5'),
(4, '2019-03-01', '2019-02-10', '15', '5');
Note: To create a useful example I added the column monday_tarif and insert the value 5 on every date range.
3. get the result
Now you can get all days of your needed range (between 2019-02-05 and 2019-02-21) from the calendar table. With a LEFT JOIN you add your tarif table to all days of date range.
With a CASE WHEN and the condition DAYOFWEEK = 2 or DAYNAME = 'Monday' you can check if the current date is a Monday or not, to get the correct tarif value of the day.
SELECT SUM(CASE WHEN DAYOFWEEK(cal.dateValue) = 2 THEN tarif.monday_tarif ELSE tarif.day_tarif END) AS sumWithMondayTarif
FROM calendar cal
LEFT JOIN tarif ON cal.dateValue BETWEEN start_tarif AND end_tarif
WHERE cal.dateValue BETWEEN '2019-02-05' AND '2019-02-21';
You can also use a SELECT with a sub select of the calendar:
SELECT SUM(CASE WHEN DAYOFWEEK(cal.dateValue) = 2 THEN tarif.monday_tarif ELSE tarif.day_tarif END) AS sumWithMondayTarif FROM (
SELECT adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) dateValue FROM
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4
HAVING dateValue BETWEEN '2019-02-05' AND '2019-02-21'
) cal LEFT JOIN tarif ON cal.dateValue BETWEEN start_tarif AND end_tarif
demo on dbfiddle.uk

Below mentioned query is for sundays count. you can modify it as per your requirement
select ROUND((
(unix_timestamp(`end_tarif`) - unix_timestamp(`start_tarif`) )/(24*60*60)
-7+WEEKDAY(`start_tarif`)-WEEKDAY(`end_tarif`)
)/7)
+ if(WEEKDAY(`start_tarif`) <= 6, 1, 0)
+ if(WEEKDAY(`end_tarif`) >= 6, 1, 0) as Sunday
from tarif
where `end_tarif`<= '2019-02-21' AND `start_tarif`>='2019-02-05' ;

Related

Insert unique random number with recursive MySQL

I want to populate a table with unique random numbers without using a procedure.
I've tried using this reply to do it but not success.
What I'm trying to do is something like this but validating that numbers are not repeated:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1)
SELECT random_num, null
FROM cte;
In the example above, I am able to generate random values and insert them but without validating that the numbers are not repeated.
I have tried to do this:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1 AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL))
SELECT random_num, null
FROM cte;
but the condition AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL) in the where case, causes an SQL Error [4008] [HY000]: Restrictions imposed on recursive definitions are violated for table 'cte'
Any suggestions of how to do it? thank you!.
This could be an option. Generate all possible values, sort randomly and take desired number of entries.
CREATE TABLE random_data (
row1 INT PRIMARY KEY AUTO_INCREMENT,
row2 VARCHAR(10) NOT NULL,
UNIQUE KEY _Idx1 ( row2 )
);
INSERT INTO random_data (row2)
SELECT LPAD(num, 8, 0)
FROM (
SELECT h * 10000000 + g * 1000000 + f * 100000 + e * 10000 + d * 1000 + c * 100 + b * 10 + a AS num
FROM (SELECT 0 a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) ta
JOIN (SELECT 0 b UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tb
JOIN (SELECT 0 c UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tc
JOIN (SELECT 0 d UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) td
JOIN (SELECT 0 e UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) te
JOIN (SELECT 0 f UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tf
JOIN (SELECT 0 g UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tg
JOIN (SELECT 0 h UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) th
) n
ORDER BY RAND()
LIMIT 100000;
If you have a table - any table - with e.g. 100 rows then you can generate million distinct random numbers between 0 and 99999999 as follows:
select distinct floor(rand() * 100000000)
from t as t0, t as t1, t as t2
limit 1000000
Note that because of distinct you will need to generate a bigger number of rows so that you get desired number of rows after distinct.

SQL - Is there a way to calculate a running total on a series of dates?

Given a list of events with date where 1 indicates something (e.g. student) joined a group and -1 indicates something left a group, is it possible to calculate group size by date in SQL? I have code that produces all dates in a range... that works when I run it on its own. Then I'd like to join in enrollment events by class and have a total of the number enrolled on each date. (+1 == class add, -1 == class drop).
I think I am missing something fundamental about how Joins and Grouping works in SQL.
http://sqlfiddle.com/#!9/e4835/5/0
Sample data:
CREATE TABLE classes(`id` int, `name` varchar(7));
INSERT INTO classes(`id`, `name`) VALUES
(1, 'math'),
(2, 'english'),
(3, 'sciene');
CREATE TABLE enrollment_changes(
`class_id` int,
`change_date` date,
`change` int);
INSERT INTO enrollment_changes
(`class_id`, `change_date`, `change`)
VALUES
(1, '2019-01-01', 1),
(1, '2019-01-01', 1),
(1, '2019-01-02', -1),
(3, '2019-01-02', 1),
(1, '2019-01-03', 1),
(2, '2019-01-03', -1)
;
-- This gets me part way there... it produces the product of dates x classes
SELECT
date_range.event_date, c.name
FROM
(SELECT adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) event_date
FROM
(SELECT 0 t0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SELECT 0 t1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
(SELECT 0 t2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2,
(SELECT 0 t3 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3,
(SELECT 0 t4 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4
) AS date_range
JOIN
classes c
WHERE
date_range.event_date BETWEEN '2019-01-01' AND '2019-01-03'
;
-- This does not work at all... it reduces the output to a single record.
SELECT
date_range.event_date, c.name, SUM(e.change) AS 'NetEnrollment'
FROM
(SELECT adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) event_date
FROM
(SELECT 0 t0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SELECT 0 t1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
(SELECT 0 t2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2,
(SELECT 0 t3 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3,
(SELECT 0 t4 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4
) AS date_range
JOIN
classes c
JOIN
enrollment_changes AS e
ON
e.change_date <= date_range.event_date
AND
e.class_id = c.id
WHERE
date_range.event_date BETWEEN '2019-01-01' AND '2019-01-03'
;
Current result:
event_date name NetEnrollment
------------------------------------
2019-01-01 math 6
Desired result:
event_date name NetEnrollment
------------------------------------
2019-01-01 math 1
2019-01-01 english 0
2019-01-01 science 0
2019-01-02 math 1
2019-01-02 english 1
2019-01-02 science 0
2019-01-03 math 2
2019-01-03 english 1
2019-01-03 science 1
You can use the following solution:
SELECT date_range.event_date, c.name, IFNULL(SUM(e.change), 0) AS 'NetEnrollment'
FROM (
SELECT adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) event_date
FROM
(SELECT 0 t0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SELECT 0 t1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
(SELECT 0 t2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2,
(SELECT 0 t3 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3,
(SELECT 0 t4 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4
) AS date_range JOIN classes c
LEFT JOIN enrollment_changes AS e ON e.change_date <= date_range.event_date AND c.id = e.class_id
WHERE date_range.event_date BETWEEN '2019-01-01' AND '2019-01-03'
GROUP BY date_range.event_date, c.name
ORDER BY date_range.event_date, c.name
demo on dbfiddle.uk
Every day on the calendar table get joined with all classes (using JOIN). The encrollment changes get joined (using LEFT JOIN) to the day and specific class. Using IFNULL you can replace the NULL values with 0.
Using a GROUP BY just on the day results in one row per day. To get a row for every class per day you have to GROUP BY day and class name.

MySQL 5.5 - count open items per day with condition

I have been working on one item that is easy in excel and I can not do it in MySQL. This is a follow up question with new values and new requirements to this one:
MySQL 5.5 - count open items per day
So, again I have got the same table in excel and I want to achive Count_open in MySQL.
Excel's formula is =COUNTIFS($A$2:$A$30000,"<="&E2,$B$2:$B$30000,">="&E2)
So, in my T1 table I have got two dates, open and close and I want to calculate how many where open per date.
Previously I used temp table for the last 7 days but this time I need to just stick to T1 table.
To get T1 table, I use the following code:
CREATE TABLE T1
(
ID int (10),
Open_Date date,
Close_Date date);
insert into T1 values (1, '2018-12-17', '2018-12-18');
insert into T1 values (2, '2018-12-18', '2018-12-18');
insert into T1 values (3, '2018-12-18', '2018-12-18');
insert into T1 values (4, '2018-12-19', '2018-12-20');
insert into T1 values (5, '2018-12-19', '2018-12-21');
insert into T1 values (6, '2018-12-20', '2018-12-22');
insert into T1 values (7, '2018-12-20', '2018-12-22');
insert into T1 values (8, '2018-12-21', '2018-12-25');
insert into T1 values (9, '2018-12-22', '2018-12-26');
insert into T1 values (10, '2018-12-23', '2018-12-27');
So far I have tried below code but it does not yield the correct results.
SELECT T1.Open_Date, count(*) FROM T1
WHERE
T1.Open_Date>='2018-12-01' and t1.Close_Date <='2019-03-17'
GROUP BY T1.Open_Date;
I am lost at the moment and your help is much needed!
The difference between Excel and a database is that you have manually generated the dates first in Excel. You could do that too in mysql and write a list of queries each for every date. That is basically the same as you do in your excel.
But luckily mysql isn't excel, so we can automate that. First we must generate a interval of dates. There is a big thread about that here: generate days from date range.
Then we just have to group the valid dates and voila:
Select a.Date, Count(t.ID)
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
) a, T1 t
where a.Date between '2018-12-01' and '2019-03-17'
and a.Date between t.Open_Date and t.Close_Date
group by a.Date

Insert where in join, code confused

This code returns me the most used words in a column in TEXT format called description and is on the table 'messages`.
However I can not stick this in the WHERE code:
messages.tag = 'HELLO'
I need it to do what it already does, but with this WHERE I tried this code and gave not sure:
SELECT message, count(message) as count
FROM (
SELECT
messages.id,
SUBSTRING_INDEX(SUBSTRING_INDEX(messages.message, ' ', count.n), ' ', -1) as message
FROM
(select (h*100+t*10+u+1) n from
(select 0 h union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 t union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) B,
(select 0 u union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) C
) as count
INNER JOIN messages
ON CHAR_LENGTH(messages.message)-CHAR_LENGTH(REPLACE(messages.message, ' ',''))>=count.n-1
ORDER BY id, n
) x
WHERE LENGTH(message) >= 5
AND messages.tag = 'HELLO'
GROUP BY message
ORDER BY count DESC
LIMIT 10
You have to move that where clause into the subquery. The messages alias is not known in the outer query:
FROM (SELECT messages.id,
SUBSTRING_INDEX(SUBSTRING_INDEX(messages.message, ' ', count.n), ' ', -1) as message
FROM (select (h*100+t*10+u+1) n
from (select 0 h union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 t union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) B,
(select 0 u union select 1 union select 2 union select 3 union select 4 union
select 5 union select 6 union select 7 union select 8 union select 9) C
) count INNER JOIN
messages
ON CHAR_LENGTH(messages.message)-CHAR_LENGTH(REPLACE(messages.message, ' ','')) >= count.n-1
WHERE messages.tag = 'HELLO'
ORDER BY id, n
) x
The other condition stays in the outer query.
Try this,
I think messages.tag should be like, not equal to 'HELLO'
SELECT message, count(message) as count
FROM (
SELECT
messages.id,
SUBSTRING_INDEX(SUBSTRING_INDEX(messages.message, ' ', count.n), ' ', -1) as message
FROM
(
select (h*100+t*10+u+1) n
from
(
select 0 h union select 1 union select 2 union select 3 union select 4
union
select 5 union select 6 union select 7 union select 8 union select 9) A,
(select 0 t union select 1 union select 2 union select 3 union select 4
union
select 5 union select 6 union select 7 union select 8 union select 9) B,
(select 0 u union select 1 union select 2 union select 3 union select 4
union
select 5 union select 6 union select 7 union select 8 union select 9) C
) count
INNER JOIN messages
ON CHAR_LENGTH(messages.message)-CHAR_LENGTH(REPLACE(messages.message, ' ',''))>=count.n-1
WHERE messages.tag like '%HELLO%'
ORDER BY id, n
) x
WHERE LENGTH(message) >= 5
GROUP BY message
ORDER BY count DESC
LIMIT 10

using loop to insert 100000 data in mysql

I want to insert data(100000) with a loop in mysql.
When i run no error,but data not insert into my table.
this my query :
DELIMITER //
DECLARE i INT DEFAULT 1;
WHILE i <= 100 DO
INSERT INTO vouchers VALUES (i,'val1','val2','val3');
SET i = i + 1;
END WHILE;
DELIMITER ;
structur table :
id int(11)[autoincrement]
data1 varchar(100)
data2 varchar(100)
data3 varchar(100)
how to fix my query ?
thanks..
You could insert your 100000 rows without a procedure with this unwieldy statement:
INSERT INTO
vouchers
SELECT
t.n, 'val1', 'val2', 'val3'
FROM (
SELECT
1 + a.N + b.N * 10 + c.N * 100 + d.N * 1000 + e.N * 10000 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) c
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) d
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) e
ORDER BY n
) t;
To use the autoincrement feature replace the t.n by NULL:
INSERT INTO
vouchers
SELECT
NULL, 'val1', 'val2', 'val3'
FROM (
SELECT
1 + a.N + b.N * 10 + c.N * 100 + d.N * 1000 + e.N * 10000 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) c
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) d
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) e
ORDER BY n
) t;