How do I create an entirely new column in SQL while using CASE WHEN, GROUPING_ID(), and ROLLUP() syntax?
So far I have tried:
SELECT Country, ContactTitle, COUNT(ContactTitle) AS Count
,CASE(
WHEN
GROUPING_ID(Legend) = 0 THEN ' '
WHEN
GROUPING_ID(Legend) = 1 THEN 'SUBTOTAL(Country)')
GROUP BY ROLLUP(Country, ContactTitle)
FROM dbo.Customers
SELECT Country, ContactTitle, COUNT(ContactTitle) AS Count,
CASE
WHEN GROUPING_ID(Country,ContactTitle) = 0 THEN ''
WHEN GROUPING_ID(Country,ContactTitle) = 1 THEN CONCAT('Subtotal for ',Country)
END AS Legend
FROM dbo.Customers
GROUP BY ROLLUP(Country, ContactTitle);
A CASE needs an END.
And while testing, you could output the GROUPING_ID or GROUPING to understand what they return.
SELECT Country, ContactTitle, COUNT(*) AS Count,
(CASE
WHEN GROUPING_ID(Country, ContactTitle) = 1
THEN CONCAT('SUBTOTAL(',Country,')')
WHEN GROUPING(Country) = 1
THEN 'TOTAL'
ELSE ' '
END) AS Legend
FROM Customers
GROUP BY Country, ContactTitle WITH ROLLUP;
Related
I have tried to debug this for hours. Any help or tips will be appreciated
SELECT PA.PolExec, SUM(ISNULL(PR.Revenue,0) + ISNULL(PF.Revenue,0)) AS Revenue,
CASE P.PolTypeLOB
WHEN 'Me%' THEN 'MED'
WHEN 'Pres' THEN 'MED'
ELSE CASE P.TypeOfBus
WHEN 1 THEN 'PL'
WHEN 2 THEN 'CL'
ELSE 'BEN'
END
END AS PolType
GROUP BY PA.PolExec
ORDER BY PA.PolExec
Use MAX if PolTypeLOB is always the same for all PolExec
SELECT PA.PolExec, SUM(ISNULL(PR.Revenue,0) + ISNULL(PF.Revenue,0)) AS Revenue,
MAX(CASE P.PolTypeLOB
WHEN 'Me%' THEN 'MED'
WHEN 'Pres' THEN 'MED'
ELSE CASE P.TypeOfBus
WHEN 1 THEN 'PL'
WHEN 2 THEN 'CL'
ELSE 'BEN'
END
END) AS PolType
GROUP BY PA.PolExec
ORDER BY PA.PolExec
as the error me3ssage says , all columns in a SELECT have3 to be in the GROUP BY or have a aggregation function
In my current query:
SELECT COUNT(WC.ID) AS "Regions"
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
;
I COUNT(WC.ID) AS "Regions" .
However, we have multiple regions with WC.Type can be 1,2,3,4. I need to count each type occurrence into COUNT(WC.ID) AS "Region_1", COUNT(WC.ID) AS "Region_2" ... depending on WC.Type.
Is there any way to solve this in one query? I am looking at MySQL IF, yet do not know how to integrate it into the count function.
I need it to be in one row (the shown query here is reduced, it's a larger query)
SELECT COUNT(WC.ID) AS "Region_1" , COUNT(WC.ID) AS "Region_2" ...
Here is the complete query if anyone is interested:
SELECT PCS.PDB_id, PCS.Chain, PPA.ENSEMBL_start, PPA.ENSEMBL_end, PPA.eValue, PIN.TITLE AS "pdbTitle", COUNT(WC.ID) AS "Regions"
FROM PDB_Chains AS PCS
LEFT JOIN WHOLE_FEATURES_PDB_CHAINS AS WC ON WC.PDB_CHAIN_ID = PCS.idPDB_chains, PDB_protein_alignment PPA, PDB_INFOS PIN
WHERE PCS.idPDB_chains = PPA.idPDB_Chains
AND PCS.PDB_id = PIN.PDB_ID
AND PPA.idProteins = (SELECT idProteins from Proteins WHERE ENSEMBL_protein_id = "'+submittedID+'")
GROUP BY PCS.PDB_id, PCS.Chain ORDER BY PCS.PDB_id;
Here's the working solutin based on your kind answers
SELECT PIN.TITLE AS "pdbTitle", COUNT(CASE WHEN WC.STRUCTURAL_FEATURES_ID = 1 then 1 end) AS "PPInterface" , COUNT(CASE WHEN WC.STRUCTURAL_FEATURES_ID = 4 then 1 end) AS "flexibleRegions"
FROM PDB_Chains AS PCS LEFT JOIN WHOLE_FEATURES_PDB_CHAINS AS WC ON WC.PDB_CHAIN_ID = PCS.idPDB_chains, PDB_protein_alignment PPA, PDB_INFOS PIN
WHERE PCS.idPDB_chains = PPA.idPDB_Chains
AND PCS.PDB_id = PIN.PDB_ID
AND PPA.idProteins = (SELECT idProteins from Proteins WHERE ENSEMBL_protein_id = "ENSP00000256078.4")
GROUP BY PCS.PDB_id, PCS.Chain ORDER BY PCS.PDB_id;
You can use case when statement inside your aggregate function.
Try this .
count(case when WC.type = 1 then 1 end) as region_1, similarly repeat for another column.
Select
...
...
sum(if WC.ID = 1 then 1 else 0) as Region1,
sum(if WC.ID = 2 then 1 else 0) as Region2,
sum(if WC.ID = 3 then 1 else 0) as Region3,
sum(if WC.ID = 4 then 1 else 0) as Region4
Might do what you want.
You can use GROUP BY with COUNT to get the required result, e.g.:
SELECT WC.Type, COUNT(WC.ID) AS "Regions"
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
GROUP BY WC.Type;
Update
If you want the counts as pivoted column for each region then you can write inner SELECT queries, e.g.:
SELECT
(SELECT COUNT(ID) FROM WHOLE_FEATURES_PDB_CHAINS WHERE type = 1) AS "Region_1",
(SELECT COUNT(ID) FROM WHOLE_FEATURES_PDB_CHAINS WHERE type = 2) AS "Region_2",
other_column
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
WHERE <some condition>;
I have this query:
SELECT i.d, COUNT(id) AS dr, COUNT(id2) AS dn, SUM(eq) AS eq_sum, COUNT(thx) AS thx_count
FROM dsd
INNER JOIN
(
SELECT COUNT(id) AS d FROM ds
) i
Now I want to use WHERE only to column thx like WHERE thx="y" , so that it will count only all values with "y".
But If I just add WHERE at the end of the query it will affect other columns as well which I don't want to.
How to do this?
Then change your COUNT(thx) AS thx_count to below using CASE expression like
COUNT(CASE WHEN thx = 'y' THEN 1 ELSE 0 END) AS thx_count
(OR)
SUM(CASE WHEN thx = 'y' THEN 1 ELSE 0 END) AS thx_count
Considering the following code:
SELECT SUM(w.valor),
SUM(CASE WHEN w.tipo = '+' THEN w.valor ELSE 0 END) AS total_credit,
SUM(CASE WHEN w.tipo = '-' THEN w.valor ELSE 0 END) AS total_debit,
w.clientUNIQUE,
c.client as cclient
FROM wallet AS w
LEFT JOIN clients AS c ON w.clientUNIQUE = c.clientUNIQUE
WHERE w.status='V'
GROUP BY w.clientUNIQUE
ORDER BY total_credit-total_debit
I'm trying to calculate the difference of two aliased calculated values for sorting purposes, but I'm getting the following error:
Reference 'total_credit' not supported (reference to group function)
What am I doing wrong and how can I order results by using the difference value between the two aliases?
You can't refer to columns by their alias in the same select expression, so there are 2 options...
Repeat the expressions in the order by (yuk):
ORDER BY
SUM(CASE WHEN w.tipo = '+' THEN w.valor ELSE 0 END) AS total_credit -
SUM(CASE WHEN w.tipo = '-' THEN w.valor ELSE 0 END) AS total_debit
Or easier on the brain and easier to maintain (DRY), order via a sub query:
select * from (
<your query without the ORDER BY>
) q
ORDER BY total_credit - total_debit
I am trying to get the count of females and males in the gender field of a table.
Is there a way to get the count of each in one query?
Something like:
select * from table count(where gender = 'm') as total_males, count(where gender = 'f') as total_females;
or will it require two queries?
select count(*) from table where gender = 'm';
select count(*) from table where gender = 'f';
This is basically a PIVOT. MySQL does not have a pivot so you can use an aggregate function with a CASE statement to perform this:
select
sum(case when gender = 'm' then 1 else 0 end) Total_Male,
sum(case when gender = 'f' then 1 else 0 end) Total_Female
from yourtable
See SQL Fiddle with Demo
Or using COUNT:
select
count(case when gender = 'm' then 1 else null end) Total_Male,
count(case when gender = 'f' then 1 else null end) Total_Female
from yourtable;
See SQL Fiddle with Demo
Something like this will work:
SELECT SUM(IF(t.gender='m',1,0)) AS total_males
, SUM(IF(t.gender='f',1,0)) AS total_females
FROM mytable t
The "trick" here is that we are using a conditional test to return either a 0 or a 1 for each row, and then adding up the 0's and 1's. To make this a little more clear, I am using the SUM aggregate function rather than COUNT, although COUNT could be used just as easily, though we'd need to return a NULL in place of the zero.
SELECT COUNT(IF(t.gender='m',1,NULL)) AS total_males
, COUNT(IF(t.gender='f',1,NULL)) AS total_females
FROM mytable t
Consider that the two expressions in the SELECT list of this query:
SELECT COUNT(1)
, SUM(1)
FROM mytable t
Will return the same value.
If you want to avoid the MySQL IF function, this can also be done using the ANSI SQL CASE expression:
SELECT SUM( CASE WHEN t.gender = 'm' THEN 1 ELSE 0 END )) AS total_males
, SUM( CASE WHEN t.gender = 'f' THEN 1 ELSE 0 END )) AS total_females
FROM mytable t
select sum(case when gender='m' then 1 else null end) as total_males, sum(case when gender='f' then 1 else null end) as total_females from ...
Should work just fine!
If your only issue is to avoid two queries, you can always write two queries as subselects of one query.
Select (select 1 from dual) as one, (select 2 from dual) as two from dual
This would work for your scenario, too.